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PIN or HINGE can resist horizontal and vertical forces...same lang

Thanks for the support!

since the problem is to determine the slope at A, then you will apply unit moment.

sayop boss?

oo...part sa illustration sa Muller-Breslau...

@besfrenjohny Thank you sir

sorry...this video was originally intended for my students....anyway, you can click the caption/subtitle....hopefully it can help you....thank you...

just subdivide the load into a rectangle (uniformly distributed) and a triangle (uniformly varying)...so thr will be two separate diagrams...a 2nd degree spandrel and a 3rd degree spandrel.

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you're welcome...

you're welcome...

hindi...since they are both approximate methods...

thank you!!!

you just sum up moment about point C (roller support). you will get 8/5...and then sum up force along the vertical to get 3/5 downward.

You extend the load to still form it a right triangle and then apply the same (trapezoid in form) acting upward....and once you cut a section the get the expression of M, subdivide the upward load(trapezoid) into a rectangle (uniformly distributed) and a triangle (uniformly varying).

@besfrenjohny yes sir but if yung triangular load po ay nakabaliktad let's say na ang 0 kN/m ay nasa bandang right side then constantly increasing papuntang left side of the beam..

@@osweng163 make it a rectangle(uniformly distributed) by adding a right triangle and then apply the same load acting upward...

@@besfrenjohny thank you sir..

if hindi fixed ang F, magiging unstable cya...but know that ir you are using Muller Breslau, only the support that you consider will be displaced by one unit...the other supports same position lang.

you're welcome....same school ta...dugay na ko wa kabalik didto...

You are welcome!

thank you...

ky naa man sa problem nga five ka annual withdrawals sugod sa 11th.

yes if you are using Macaulay...

Thanks

convert the rate by comparing their effective rates....i have a sample problem in ordinary annuity where the mode of payment is not the same as the interest rate. just watch it for your reference.

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You are welcome

there's a calculator technique for geometric gradient but i didn't include it in the video.

It's because the formula derived in arithmetic gradient is only for the present worth....so when you want to get the future amount, use the formula for compound interest....

thank you sa pasakay....joke

After summing up forces, you have three equations with three unknowns with P as the 3rd variable . You can use MODE 5-2 to solve for the unknows. Just make sure to transpose the constants to the right side of the equation..

@besfrenjohny ako na ge try sir but ma math error sha, ako ng ge tranpose pod ang mga constant pero dle gyod sha ma kuha. Sa pag butang ba sa sa MODE 5-2 sir kay si P is 0???

@@lesvettemarie6652 zero ang coefficient sa P sa duha ka equations...dyn 1 ang ibutang sa equation nga naay P.

@@besfrenjohny nakuha na nako sir, thank you so much! I really loved your videos, sir and It really helps me with my SRB subject. Thank you!

@@lesvettemarie6652 you are welcome...pls help promote my channel to your classmates....thank you..

You are welcome!

ky ang gi-require sa problem ky force sa members ra man...but you can do so by summing up forces at joint D.

Are you referring to the centroid of a triangle or area of a parabolic spandrel and parabolic segment? If centroid, you must know the reference. If it's the area, then 1/3 for a spandrel and 2/3 for a segment.

@@besfrenjohny thank you I got it do you have videos too on superposition method?

@@EurekaQuest yes....you can find it in the playlist.

It's part of the procedure in analyzing indeterminate trusses using consistent deformation method.

Actually, you can put the actual value of L but since there is a condition the problem that the L/A ratio is equal to one, the value of A will be the same as L. So it's okay to put "1" for L and A since ma cancel ra.

thank you...

what do you mean? there is no fixed support in trusses...

The correct answer is "For a roller support, the reaction is perpendicular to the surface". In the given problem, the surface is vertical, therefore the reaction is horizontal.

Mohr's Circle?..puhon...

Welcome

thanks Han...

hi pareng bilok!