Відео

(Cos A +SinA)^2=cos^2A+Sin^2A +2cosA.sinA ( 1)^2=1+2cosA.sinA 1-1= 2cosA.sinA 0=cosA.sinA Now , According to this formula . a^2+b^2 =(a+b)^2 -2ab this can be also written as a^2+b^2 =(a-b)^2+2ab Now let's put value : Cos^2 A+sin^2 A=(cos A-sinA)^2+2ab 1=(cosA-sinA)^2+2*0 1=(cos A- sinA)^2 +_1= cosA -sinA Proved but in a less complicated manner 😊

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