Відео

Best content 🎉 Keep it up sir

Superb information 👍👌🙏

U are great

Answer is 5.36 seconds.

Happy birthday sir, love from OISK ❤❤

Sir, there is a doubt in my mind and i will be very thankful if you clear it,, sir in question no.10 the buoyant force acting on the object should be different because Archimede's principle states that buoyant force is equal to the weight of the displaced water and water displaced in both case given in the question is different therefore I'm asking why did you state that force acting them is equal!!! Sir please clear my doubt,it will indeed help me!

The principal focus of a lens is the point where parallel rays of light, after passing through the lens, converge (in the case of a convex lens) or appear to diverge from (in the case of a concave lens). Here’s a more detailed explanation: 1. Convex Lens (Converging Lens): When parallel rays of light are incident on a convex lens, they bend and converge to a single point on the other side of the lens. This point is called the principal focus. 2. Concave Lens (Diverging Lens): For a concave lens, parallel rays of light diverge after passing through the lens. If these diverging rays are extended backward, they appear to meet at a point on the same side as the source. This point is the principal focus of the concave lens.

Work is the Dot Product(Scalar Product) of Force and Displacement not the vector Product. By mistake i told Vector Product.🫣🙏🏻😁

Note:- 0:52 Work is the Dot Product(Scalar Product) of Force and Displacement not the vector Product. By mistake i told Vector Product. 🫣🙏🏻😁

Happy Birthday sir!🎉

Happiest Birthday sir 🎉

An exceptional and truly inspiring teacher!🙌🏻🙌🏻 Happy Birthday 🎉

😜😜😜❤❤❤

Happy birthday sir do you remember me Your Orchids the International school student Avni Sharath

sir can you please tell the name of video for learning about graph( that you mentioned in the VI graph section)

SIr aapne kaha ki doping pe depend karta hai ki ek semiconductor kaisa ho ,please aap bata de ki doping kya hota hai aur doping ke pehle semi conductor ka no of free electron aur flow of current kaisa hota hai ( aur agar boards me puche toh uske answer me kya likhna hai..) thank you sir

answer of Q12 is R, is it correct?

good videoo😁

Very nice explanation

Sir i think it should be 5A not 1/5A 30:48

Thank sir for working hard for us 💞

Great questions sir ❤ Was finding such questions variety only 12:51

Superb 👍👌🙏👍

Imp Note:- 15:13 1. Power is inversely proportional to Resistance only when voltage is constant. I have told that power is never directly proportional to resistance is true only when electric current is changing. (P=V/R, if V is constant then P is inversely proportional to R) "Generally in real life scenarios voltage is kept constant because of parallel connection so voltage is constant and power inversely proportional to resistance" 2. Power is directly proportional to resistance only when electric current is constant. (P=i^2 R, if i is constant then P is directly proportional to R) 3. Maths:- If A=(B*C)/D, A is directly proportional to B only when C and D is constant, A is directly proportional to C only when B & D is constant, A is inversely proportional to D only when B and C is constant. I hope bacho apko Clear hogaya.❤

Imp Note:- 29:25 1. Power is inversely proportional to Resistance only when voltage is constant. I have told that power is never directly proportional to resistance is true only when electric current is changing. (P=V/R, if V is constant then P is inversely proportional to R) "Generally in real life scenarios voltage is kept constant because of parallel connection so voltage is constant and power inversely proportional to resistance" 2. Power is directly proportional to resistance only when electric current is constant. (P=i^2 R, if i is constant then P is directly proportional to R) 3. Maths:- If A=(B*C)/D, A is directly proportional to B only when C and D is constant, A is directly proportional to C only when B & D is constant, A is inversely proportional to D only when B and C is constant. I hope bacho apko Clear hogaya.❤

Sir ak bar projectile motion in advance level le lo please 🙏

Sir do you know Dr Homi BHA BHA young scientist compition entrance exam

Very good explanation.

Thanku sir ❤

Very well explained Sir ...i have shared your videos with my teachers and students also ..

Super sir😊

Thanku you very much sir❤

I love you sir ❤ ...... Sir our response is not good for your channel means your views is not sufficient as you explain a quality education So please do not demotivate I am your big fan 🙏

Sir if we have to find the depth of the sea then we must take only 'D' not 2D please reply

Love U sir ❤❤❤

40:45 q3 ka answer no hoga kyuki total current 8A h aur fuse 10A le skta h......

37:34 one correction:- Weightlessness is the sensation or condition where an object or person experiences no net gravitational force or other force supporting them, making them feel "weightless." This typically occurs when: An object is in freefall (such as astronauts orbiting Earth). The object does not feel any opposing force, like the normal force we feel on Earth due to the ground pushing back on us. In simple words agar apko weight measure karna ho to weighing scale par khade hokar physically then screen par weight mile ga. But agar aap weighing scale ko touch hi na kar Pau due to free fall then weighing scale reading zero dekha ae gi. So that is weightlessness. (g is not zero)

❤❤❤

Sir bahut mast padate hai for class 9

Hi sir , your student from Orchids the international school. Batch 21-22 grade 8th

Underrated sir ❤

Your teaching techniques are extremely easy to understand🙌🏻👍🏻

amazing ❤😍

Sir do you know Krishna verma 😅 it's me

Best of best....❤

Baahit ache padate hai class 9 olympaid ke liy video baniy

Sir aapne woh circle wale q mei pi*r + pi*r/2 kiya hai..usme actually 2*pi*r + pi*r hoga

❤❤❤

thank you sir