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Niorosky Engineering Online
Philippines
Приєднався 17 бер 2020
Author: Nioro Guevarra Furiscal
AREA MOMENT METHOD APPLIED ON A DOUBLE OVERHANG BEAM
*Correction: @24:33 equation should be (n+1)/(n+2), not (n-1)/(n+2)
Переглядів: 4 112
Відео
AREA MOMENT METHOD APPLIED ON A SIMPLY SUPPORTED BEAM
Переглядів 6 тис.3 роки тому
*Correction: @51:45 - from the commentary, it should be 32, not 75, as part of the curvature of the specific diagram. I pinpointed the wrong value.
DOUBLE INTEGRATION METHOD APPLIED ON RESTRAINED BEAM
Переглядів 9 тис.3 роки тому
DOUBLE INTEGRATION METHOD APPLIED ON RESTRAINED BEAM
DOUBLE INTEGRATION METHOD APPLIED ON PROPPED BEAM
Переглядів 8 тис.3 роки тому
DOUBLE INTEGRATION METHOD APPLIED ON PROPPED BEAM
DOUBLE INTEGRATION METHOD APPLIED ON PROPPED BEAM WITH AN OVERHANG
Переглядів 3,7 тис.3 роки тому
DOUBLE INTEGRATION METHOD APPLIED ON PROPPED BEAM WITH AN OVERHANG
LRFD & ASD FLEXURAL STRENGTH: I-SHAPED STEEL SECTION WITH NONCOMPACT OR SLENDER FLANGE
Переглядів 10 тис.3 роки тому
LRFD & ASD FLEXURAL STRENGTH: I-SHAPED STEEL SECTION WITH NONCOMPACT OR SLENDER FLANGE
LRFD & ASD FLEXURAL STRENGTH: I-SHAPED COMPACT STEEL SECTION
Переглядів 4,3 тис.3 роки тому
LRFD & ASD FLEXURAL STRENGTH: I-SHAPED COMPACT STEEL SECTION
PRINCIPLE OF DESIGN AND ALLOWABLE FLEXURAL STRENGTH OF I SHAPED STEEL SECTIONS BASED ON NSCP 2015
Переглядів 4,7 тис.3 роки тому
PRINCIPLE OF DESIGN AND ALLOWABLE FLEXURAL STRENGTH OF I SHAPED STEEL SECTIONS BASED ON NSCP 2015
CAMBER CALCULATION (ECCENTRIC END SPAN)
Переглядів 3 тис.3 роки тому
CAMBER CALCULATION (ECCENTRIC END SPAN)
CAMBER CALCULATION (NON-ECCENTRIC END SPAN)
Переглядів 1,7 тис.3 роки тому
CAMBER CALCULATION (NON-ECCENTRIC END SPAN)
STEEL LOCAL BUCKLING CONDITIONS (CHECK FOR COMPACTNESS)
Переглядів 8 тис.3 роки тому
STEEL LOCAL BUCKLING CONDITIONS (CHECK FOR COMPACTNESS)
STEEL SECTIONAL PROPERTIES BASED ON AISC STEEL CONSTRUCTION MANUAL 15TH EDITION PART 2 OF 2
Переглядів 2,3 тис.3 роки тому
*CORRECTIONS: @16:37 - Replace ((91/26)(6.34) xsub1) by ((xsub1 - (7/26)(6.34)) @16:39 - 51,531.2023 cu.mm instead of 51,636.2276 cu.mm @17:09 - 103.0624 x10^3 cu.mm instead of 103.2725 x10^3 cu.mm
STEEL SECTIONAL PROPERTIES BASED ON AISC STEEL CONSTRUCTION MANUAL 15TH EDITION PART 1 OF 2
Переглядів 2,4 тис.3 роки тому
STEEL SECTIONAL PROPERTIES BASED ON AISC STEEL CONSTRUCTION MANUAL 15TH EDITION PART 1 OF 2
CAMBER FORMULA DERIVATION FOR A TRAPEZOIDAL TENDON PROFILE
Переглядів 1,6 тис.3 роки тому
CAMBER FORMULA DERIVATION FOR A TRAPEZOIDAL TENDON PROFILE
CAMBER FORMULA DERIVATION FOR A PARABOLIC TENDON PROFILE
Переглядів 3,2 тис.3 роки тому
CAMBER FORMULA DERIVATION FOR A PARABOLIC TENDON PROFILE
CAMBER FORMULA DERIVATION FOR A RECTANGULAR TENDON PROFILE
Переглядів 1,8 тис.3 роки тому
CAMBER FORMULA DERIVATION FOR A RECTANGULAR TENDON PROFILE
CAMBER FORMULA DERIVATION FOR A TRIANGULAR TENDON PROFILE
Переглядів 1,3 тис.3 роки тому
CAMBER FORMULA DERIVATION FOR A TRIANGULAR TENDON PROFILE
SPECIFIED YIELD & TENSILE STRENGTH OF STEEL BASED ON ASTM STANDARDS
Переглядів 2,7 тис.3 роки тому
SPECIFIED YIELD & TENSILE STRENGTH OF STEEL BASED ON ASTM STANDARDS
AISC STEEL SHAPES & SECTION PROPERTIES
Переглядів 12 тис.3 роки тому
AISC STEEL SHAPES & SECTION PROPERTIES
APPLICATION OF PLASTIC THEORY: YIELD MOMENT & PLASTIC MOMENT
Переглядів 2 тис.4 роки тому
APPLICATION OF PLASTIC THEORY: YIELD MOMENT & PLASTIC MOMENT
PLASTIC THEORY: YIELD MOMENT & PLASTIC MOMENT
Переглядів 3 тис.4 роки тому
PLASTIC THEORY: YIELD MOMENT & PLASTIC MOMENT
COLLAPSE MECHANISM OF A CONTINUOUS BEAM
Переглядів 3,7 тис.4 роки тому
COLLAPSE MECHANISM OF A CONTINUOUS BEAM
COLLAPSE MECHANISM OF A SINGLE SPAN BEAM WITH TWO CONCENTRATED LOADS
Переглядів 1,6 тис.4 роки тому
COLLAPSE MECHANISM OF A SINGLE SPAN BEAM WITH TWO CONCENTRATED LOADS
COLLAPSE MECHANISM OF A PROPPED BEAM WITH A UNIFORMLY DISTRIBUTED LOAD
Переглядів 2,3 тис.4 роки тому
COLLAPSE MECHANISM OF A PROPPED BEAM WITH A UNIFORMLY DISTRIBUTED LOAD
COLLAPSE MECHANISM OF A RESTRAINED BEAM WITH A UNIFORMLY DISTRIBUTED LOAD
Переглядів 1,1 тис.4 роки тому
COLLAPSE MECHANISM OF A RESTRAINED BEAM WITH A UNIFORMLY DISTRIBUTED LOAD
COLLAPSE MECHANISM OF A SIMPLY SUPPORTED BEAM WITH A UNIFORMLY DISTRIBUTED LOAD
Переглядів 1,6 тис.4 роки тому
COLLAPSE MECHANISM OF A SIMPLY SUPPORTED BEAM WITH A UNIFORMLY DISTRIBUTED LOAD
COLLAPSE MECHANISM OF A SIMPLY SUPPORTED BEAM WITH A SINGLE CONCENTRATED LOAD
Переглядів 2,7 тис.4 роки тому
COLLAPSE MECHANISM OF A SIMPLY SUPPORTED BEAM WITH A SINGLE CONCENTRATED LOAD
COLLAPSE MECHANISM OF A PROPPED BEAM WITH A SINGLE CONCENTRATED LOAD
Переглядів 1,6 тис.4 роки тому
COLLAPSE MECHANISM OF A PROPPED BEAM WITH A SINGLE CONCENTRATED LOAD
COLLAPSE MECHANISM OF A RESTRAINED BEAM WITH A SINGLE CONCENTRATED LOAD
Переглядів 1,3 тис.4 роки тому
COLLAPSE MECHANISM OF A RESTRAINED BEAM WITH A SINGLE CONCENTRATED LOAD
Sir, ang ultimate bearing capacity po ba ng soil na 870kPa ay ang report na galing sa soil investigation? Lahat po ba ng SBC ay kailangang idivide ng FS?
good day sir ask ko lang po usually kasi ng mga project namin today is footings and pedestal na double matt reinforced( meron pong mga top bars yung footing). ask ko lang po kung yung bakal na nasolve for tension sa footing e yun din po ba yung ilalagay sa compression region(top of footing) or separate calculation po yun
Paano nya po nakuha yung value na x=5.8076?
@@preciousliamb.d9532 just use your calculator functions either the shift solve mode, quadratic eqn (degree of 2), or by manually simplifying the equation using discriminants rule learned from your algebra class. Cheers
9:03 po Plastic moment is greater than nominal moment or less tthan po sir thank you sir in advance!
Hello po good eve sir, bakit ang length sa span ng b to c is 6 po? Sa may integration po ng A1abar1😅 kanang 27/2 ang ans po, ask ko lang po bakit 6 po ang length 😅
hi. baka yung tinatanong mo yung sa integration is bakit 6 yung denominator? it is not the span. it is a constant based on derivation bago mo iapply sa (6/L)(A1a1). Cheers. for clarification check this video lecture for derivation: ua-cam.com/video/M8Sl6XDcu2U/v-deo.htmlsi=TMxJbW_dCvtLNdZ-&t=1536
Hello po! Tanong ko lang po sa 14:46, bakit x=11 na po pag ganyan yung orientation ng triangular distributed load? Thank you!
@@josephjoe9525 use geometric reorientation for those loads not touching the fixing point and loads which is 1st deg or higher should be increasing as it approaches the same point. Cheers
thank you po! bakit po kaya yung "b" yung ginamit para sa triangular load? yung (7-x) po?bakit hindi po x?
@@mmrida_ hi see the principle of derivation. See my discussion in my playlists. Cheers.
Sir @d distance from centerline of support po ba or from face of the support?
hi. if you have a stick model beam analysis (support as drawn like hinge or roller or fixed just like without size of support column) it will look like a center to center position since you dont have a basis where the support face is since no dimensions of support are given. cheers
@ eyy thank youuu, but pag meron namang dimensions ang support then consider ko yung d distance @ face of support?
@@TERENCEKLYNDIAMANTE yes measured from the face (either exterior or interior face) of support (column or spandrel)
@@nioroskyengineeringonline8968 sir same value lang din ba kahit yung loading patterns ang gamitin sa pag solve ng vu?
@@TERENCEKLYNDIAMANTE as chapter 2 considered.
Yung beam weight poba given na yun na merong unit weight na 23.544 ?
@@jmonster4964 yes. Derived from 2.4x9.81
This is so helpful. Salute po.
Could you explain why the 2n-1 and not n-1?
Hi. Section 418.6.4.1 didnt mention to provide stirrups specifically design to carry Vu at support, over the span of 2d. So, i think d would suffice in lieu of 2d? It only mention that stirrups will only be provided in 2d, but not specifically the same spacing as the design spacing requirement @ support’s Vu, which is Vu max. Am i correct?
hi sir. it was mentioned to measure from the face of the support up to the midspan for seismic design requirement. Dont forget that the critical spacings of stirrups are found nearest to the support. distance "d" are for initial analysis to be proven later since spacing of stirrups also adjust not exactly the same as "d" value. Cheers :)
Vu are found nearest to the support which is within the "d" region when measure from the face of the support. Cheers
Note that as per calculation, there is a need to use 8-175mm stirrups that is 1.275 m distance which is higher than "d" :) please refer to the prior calculations before this video lecture. refer to my playlists or proceed to this link: ua-cam.com/video/HwGm3uTpWfc/v-deo.htmlsi=FnH7dcw-3cDMx-hH&t=2430
unstable structure yan, pag mga construction worker nag kasa ng walang paalam sa site engineer. pag subcon manpower display lng ang site engineer.
sir merun po ba kayu sample computation with explanation ng "development length" ng rebars gamit na gamit po kc sa estimate at site
althoung when it comes to column designe, i prefer more strenght in concrete
Di yan ma check nmn yan sa stress strain diagram ahahahaha
mas prefer ko ma over re inforce ang designe when it comes to RCD, so that when concrete failes, there is a way to retrofet it
understand that ductile failure mode is the ultimate aim of any civil engineer. this will permit evaluation of impending failure and building inspectors could decide condemning/ demolition for safety reason. Having over-reinforcement shall mean destructive and sudden failure of structure which is unsafe for any unknowing building occupants.
@russell2514 tnx sir
@russell2514 no worries wala pa ako na design na bahay xD
@russell2514 pag aralan ko ductile failure kong ano yun, sa rcd plng medyo gamay ko
Yong ductile failure yan ba yung lalampas sa C ang compresiv area ng strain diagram? Where C=beta1 a
this one is my professor in college, more power sayu sir. sana mag ka project ka ng steel design na projects ahahahha
salamat sa teaching
dun sa 52:33 sa pagkuha ng Mu, saan galing yung 1/2? nakadivide na by two yung (3.575-0.5) na ah?
sir good morning bakit my 0.75 sa 0.17(10)sqrt(24.21)? ua-cam.com/users/clipUgkxa2P7dNEmsfm3TsTmN7Lk38gWkK1n5YTI?si=43mUpk0iqlNtX1Dg
hello po. ask ko lang po paano po nun yung recalculation ng value ng "x" if less than 300mm po yung lumabas? ano po yung difference sa solution nya sa value ng x which is greater than 300mm?
Yun din ang tanong ko hmm. Since wala naman part ang assumed 300mm sa equation right?
Sir, good day po, meron po ba kayong sample calculation kag case 3 yung soil pressure?
Galing!
Hi po tito hehe
Youre the best.❤❤❤
Solid Engr! 🔥❤ Ano nga po pala reference book niyo? Solid din daw po na reference book ang Principles of Foundation Engineering ni MJB Castro.
thank you po sir mabuhay po kayo
Do you have any videos in Post Tension System?
sir, which code or journal that you used for the reference of this video?
Hi as mentioned in the video, nscp 2015 sections was mentioned.
Sir paano po ang gagawin if Vs is negative?
15:28 Seismic detailing
Yes. The full detail of seismic detailing requirement are soon to be uploaded.
Sir tanong ko po lang when it comes to stiffened meaning welded siya diba? pag tinignan mo siya in actual or fabricated nayan sa machine? sorry for the ignorance po
para sa part a. yung nakuha po na value for tE/A ay in mm pero dinivide siya sa 11 which is in meters.
Hi check again the units. Note that the area moment diagram by parts has units of KNm. And the unit of deviatoric distance is kNm^3, not mm before dividing to EI since it has a unit. Cheers. Review your dimensional analysis.
Note that i used the unit RI in terms of Nmm^2 so there is a need to convert the numerator by 1000^3 to convert kNm^3 to Nmm^3. So Nmm^3/Nmm^2 is mm which is our desired unit of displacement as a deflection :)
thank you sa mga vids sir, engr na ako ❤
Congrats engr :)
@@nioroskyengineeringonline8968 🥹🥹🥹
Sir Niorosky, meron din po ba kayo edge column and corner column footing?
For upload pa in the future
Sorry boss, pero ang hirap sundan. I think mahina talaga ako kasi paulitulit ka na magsalita di ko pa din magets sa dami ng redundancy mong pinagsasabi.
Ok lang yan. You can read books as main material for reference which is dun ko din binase discussions ko. Cheers.
Hi engr, I have a query with regards on finding the qna. Hindi ba dapat qnu/FS siya instead of qu? kasi if iplug in yung values from the solution instead of dividing the summation of weight values ay namultiply siya by the FS.
Hi. If you are asking for dimension assessment its qult first since how can you get qnult if you dont have the size of footing to deduct as an effect of stress to be transferred on the footing itself :) also as set forth in section 413.3.1.1. Cheers
Also by logic, is it right qna is greater than qult whereas qult is the factored stress? Note that qult is the magnified value of stress and qna is the net condition lower than qult due to deductions of stresses transfered from generated stresses above.
@@nioroskyengineeringonline8968 I'm just wondering that the paired equations for q_ult would be q_all and if net would be qn_ult and qn_all. Then basing with NSCP it is not how it should be paired. Anyway, just confirming things. Thanks
@@engineersspace2024 for direct basis, see any reference book authored by braja das or muni buddhu. Cheers.
@@engineersspace2024 @norielepaulcruz3242 q ult is the reference since we are approximating bearing resistance based from forces that understand service state conditions. Note that it is set as a min condition for approximating sizes of footing then note for final checking the qna was taken to assess proper stress where stress of soil was deducted to q ult since size is determined as shown in 1:29:33 for final checking.
Here for advance study sir nioro before magstart 3rd term. Thankyouuu.
may shortcut po ba na formula?
Good day po engineer!! Meron po ba kayong lecture sa rectangular combined footing?
sir bakit po di tayo gumamit ng 1.2DL + 1.6LL?
As explained, crack is under service state.
@@nioroskyengineeringonline8968 maraming salamat po sir
s ir reference book nyo sa problem na yan?@@nioroskyengineeringonline8968
Thank you sir for the clear explanation of this topics.
Plain concrete footing ua-cam.com/video/O5JTNk-sLIk/v-deo.htmlsi=8udijjUWdGGpVpKs
Thank youuu so much po Engr. Nioro sa mga videos mo. Sobrang detailed po and complex yung mga problems. 🤍🤍🤍 #NioroskyEngineeringOnline
sir pag perpendicular po yung load sa base ng footing tapos may given na shear load parallel sa L ng footing , need pa po ba ng inclination factor?
good evening po, question lang po regarding timestamp 18:10 , when using 6M/bdsqrd bakit po sqrd yung 1000 na minultiply sa m na 117.72?
nvm, so 1000 para sa kN to N and another 1000 from meter to mm
Sir in design, when getting the required Zx of steel Fy = Mp/Zx. Yung Mp po ba rito ay Plastic moment or ultimate moment. Salamat po.
As discussed in NSCP and AISC, MP is observed under nominal condition. Please refer to my first set of video lectures found on this playlists
THANK YOU PO!!! <3 <3
Thank you po sir sa lecture, napakalinaw at detailed po. May tanong lang po ako sir, don po sa pagkuha nang As, ginamit ko po kasi sa formula ng Mu ay Mu=∅bd²Rn, then same naman po tayo nakuha sa value ng As na 5543.2797mm², ang tanong ko po ay kapag kinompare po yung rho minimum (p=1.4/bd) sa nasolve ko po na rho, mas malaki po value nung sa rho minimum kaya yon po gagamitin diba po? tas pag ginamit po yun magiiba po non ang As, As=8200mm² na po. Sana po malinawan po ako, hindi kopo kasi alam kung tama po ba idea ko. Thanks po sir!
Hi sir. This topic is for Masteral Degree na po diba