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Math All Day with Dr. George Sweeney
Приєднався 11 лип 2010
I love math and I love to teach math. I especially love difficult math, computer math and linear algebra. My channel is for people who are interested in mathematics, computer math (discrete structures or discrete mathematics) and all of its applications. I hope I can make the learning of this challenging and interesting subject easier and more fun.
How do I solve differential equations for piecewise functions?
In this video, I give an example and discuss the method for solving differential equations that have piecewise components. Piecewise differential equations are very common in engineering and circuit applications and this video gives students a basic overview of the process.
00:00 Introduction
00:56 Solving Piecewise Continous Functions
09:28 Review
10:01 Marker 1
00:00 Introduction
00:56 Solving Piecewise Continous Functions
09:28 Review
10:01 Marker 1
Переглядів: 168
Відео
Orthogonal Trajectories and Families of Functions
Переглядів 302 місяці тому
In this video, I show how to find orthogonal trajectories of a family of functions using differential equations. Orthogonal trajectories are a great way to introduce families of functions and the general solution to a differential equation. 00:00 Introduction 00:01 Introduction 01:01 Families of functions 04:24 Orthogonal Definition 08:39 Orthogonal Trajectories Example 1 14:16 OT Example 2 18:...
What is a parabola and how do I graph one?
Переглядів 354 місяці тому
In this video, I start with the definition of a parabola as the set of all points equidistant from the focus and directrix. I then answer the following questions: 1. What is a parabola? 2. What is the equation for a parabola? 3. How do I find the focus, directrix and graph the parabola given the equation? 4. How do I find the equation for the parabola given the focus and the directrix? 00:00 In...
What is an ellipse and how do I graph one?
Переглядів 346 місяців тому
I describe the different parts of the ellipse, including the major and minor axes, foci, and vertices. I derive the equation and then I graph ellipses using it. This is part of my conic sections lectures. 00:00 Introduction to ellipses 01:14 Defining the ellipse 03:49 Different parts of the ellipse 08:17 Deriving the equation of the ellipse 14:51 The equations for the ellipse 16:25 Ex1: Graphin...
Solving the Volterra Equation using Laplace Transforms
Переглядів 1426 місяців тому
The volterra equation is an integral equation that requires the use of the convolution theorem and Laplace transforms to solve. In this video, we show how to use the convolution theorem to solve Volterra equations. The Volterra equation is used in modelling semiconductors and in different kinds of advanced mathematical physics. I have linked to my video on the Convolution Theorem: 00:00 Definin...
Using the Convolution Theorem to Do Laplace Transforms
Переглядів 1606 місяців тому
If you want to solve initial value problems or systems with laplace transforms and you have a product of two Laplace transforms, you will want to use the Convolution theorem to solve. The Convolution theorem uses the convolution integral in order to define the inverse laplace transform. 00:00 Introduction 00:54 Defining the Convolution Product/Integra 01:23 Convolution Product Example 04:06 Pro...
Verifying Functional Completeness- Boolean Algebras
Переглядів 706 місяців тому
To verify the completeness of a set of operations on a Boolean Algebra, we need to show that our new set of operations give equivalent functions. In this video, we show how to determine if a set of operations is functionally complete by showing how we convert the operations and then show how the new functions give us the same outputs given the same inputs. Functional completeness is valuable be...
Solving Systems of Differential Equations using Laplace Transforms
Переглядів 2097 місяців тому
Now that we have figured out how to solve initial value problems using Laplace transforms, we can use Laplace transforms to solve systems of differential equations. We will use the basic theory and Kramer's rule to solve these systems. If you need a refresher on Kramer's rule, I have linked to a video below: ua-cam.com/video/Ot87qLTODdQ/v-deo.html 00:00 Introduction 00:49 General Method for a 2...
Solving Initial Value Problems using Laplace Transforms- Basic
Переглядів 5507 місяців тому
In this video, I solve differential equations using Laplace transforms and put forward the basic theory. I only use basic fundamental Laplace transforms and inverses, but the method will hold for any functions where we will use Laplace Transforms. 00:00 Introduction 01:27 Laplace transform of the derivative 02:23 Proving the Derivative 05:12 Laplace Transform of y" 06:06 Example 1- First Order ...
The Second Shifting Theorem and the Unit Step Function
Переглядів 3587 місяців тому
This video is on how to use Laplace transforms for piecewise continuous functions without integrating. The first part of the video is on the unit step function, which is what we use to transform piecewise functions into individual functions. Then once we have used the unit step function, we can use the second shifting theorem to find the Laplace transform of piecewise functions. 00:00 Introduct...
Laplace Transfroms-The First Shifting Theorem
Переглядів 1157 місяців тому
In this video, I expand on the theory of laplace transforms to solve initial value problems by using the first shifting theorem. The First Shifting Theorem allows us to expand the number and kind of functions we can find inverse Laplace transforms for. 00:00 Introduction 00:26 Theorem and Proof 03:02 Examples for finding Laplace Transforms 06:36 Examples for finding Inverses 15:54 Techniques an...
Related Rates- Triangle Example
Переглядів 487 місяців тому
In this video, I find the change in the area based upon the change in an angle. We use a trig formula, A=(1/2)ab sin (theta) in order to do this. This is a problem example, so if you are looking for a longer lecture on related rates, please see the lecture video:
Periodic Laplace Transforms
Переглядів 1088 місяців тому
In this video, I show how to find Laplace transforms for periodic functions. 00:00 Introduction 00:44 Definition of the Periodic Transform 02:20 Example 1- cos(t) 05:23 Example 2- Piecewise
Inverse Laplace Transforms - Basic
Переглядів 1228 місяців тому
In this video, I introduce inverse Laplace Transforms so that we can start to work with solving differential equations using the Laplace Transform. I go in and use scalar multiplication, addition/subtraction and partial fractions to find the inverses. If you need a review of partial fractions, the following is a link to my video on partial fractions: ua-cam.com/video/w7MuOZhhCyU/v-deo.html 00:0...
Laplace Transforms of Piecewise Functions
Переглядів 2038 місяців тому
In this video, I show how to find the Laplace transform for a piecewise function. I don't use a chart, but instead I use the definition of the Laplace Transform. If you would like to see how to find basic Laplace transforms or haven't seen the definition of the Laplace Transform, these two videos may be helpful. 00:00 Example 1: Piecewise functions 04:21 Example 2 You can also use the unit step...
Decomposing a matrix into Elementary matrices
Переглядів 377Рік тому
Decomposing a matrix into Elementary matrices
Using Elementary Row Matrices to Do Row Reduction
Переглядів 358Рік тому
Using Elementary Row Matrices to Do Row Reduction
Basic Mixture Problems using first order linear differential equations
Переглядів 752Рік тому
Basic Mixture Problems using first order linear differential equations
Finding Big Theta with subtraction of terms
Переглядів 112Рік тому
Finding Big Theta with subtraction of terms
Divergence Theorem for Non-closed or non-simple volume
Переглядів 350Рік тому
Divergence Theorem for Non-closed or non-simple volume
Discrete Math- Rules of Exponents Review
Переглядів 157Рік тому
Discrete Math- Rules of Exponents Review
thanks dude
incorrect. Recheck your work
You are totally right. I dropped the negative off on the second half of the first integral. It will need a revision.
Nice
25:11 shouldn't this intergral be (x^-p)/(-p+1)
Doesn’t success have 3 s’?
Yes it does. You are dead on. Looks like this one needs a revision.
Can I ask why (log(x))^2 is big O (x)?
A function can be bigO of a potentially infinite number of functions, as long as the g(x) we select grows faster than our function after a certain value. If you look at the graphs for the two functions, y=x and y=(log(x))^2 and you will see that if x is greater than 1, y=x grows at a much faster rate.
Amazing video!
Super helpful god bless
Great video! In the last step when you calculated the flux out from the disc you added to be able to use divergence theorem, how did you change the double integral of S2 with dS to a double integral of D with dA? is it because 12:07 both dS and dA are the area element? Thank you
Very helpful 😊
Thank you!
how do you find the inverse of the modulo?
Minute 10:41 this is what we were talking about today in the homework example, in office hours, the reason why it's not valid is because the conclusion is false. In order to have a valid argument, we need the hypothesis to be true and conclusion to be true. If q = t hence -q = f, makes the conclusion false, if the conclusion is false its not a valid argument. If the conclusion was q then it would be valid and it would use the rule of disjunctive syllogism.
This was simple, straightforward, with clear examples. Awesome.
at 23:25 you missed the -1
Got it, I will see if I can get a revision in this weekend. Thank you!
❤❤❤
Helpful video. Thanks man!
Glad it helped!
Let me tell you something. When I was a student and I had to take this class, I can honestly tell you that it did not make sense at all. I have been an Algebra 1 and 2 teacher for almost a ten years, and it finally clicked. Moral of the story, a person must have a strong algebra foundation to truly understand this 😅
This is true because at the end of the day, this kind of proving simply requires some algebra ability and an understanding of what the members of the domain look like.
RADIAN MODE
good explanation, thank you
You are welcome!
Hi there! Love the lecture. Thanks for the mention at 42:42. I am glad these applets I made are useful :) Regards.
Thank you, I and my students really appreciate all the great tools that people have created. Eventually I hope to pay it forward and create some great things for other teachers to use.
And specifically, thank you!
In the first example given the supply of fruits is limited if one places bars in the first two slots there will not be 5 pears to fill the rest of the slots given there are only four pears. Maybe I am missing something
Sameer, if you put the bars in the first two slots, you will have a bowl with 5 pears, no oranges, and no apples. At the bottom of the question, it says there are 5 of each type of fruit. So there should be five pears. Let me know if you have a follow up.
well I listened this from my Professor, and also checked textbook. But It hass been clear just after listening you. thanks
Shiny_apricot, I am glad that it helped.
I need clarification on why the first one is preferred to be the definition over the theorem one. Could anyone please let me know?🙏
I am not sure about the question, but if I understand you right: I use the theorem to evaluate the limits in this video and I think for most purposes this actually is the quickest and most effective way of finding the limits of vector-valued functions. So I use the theorem one for the limits problems. I think I glossed over the limit definition because I didn't want to go into evaluating distance(the two bars on either side of definition of the limit) and all of the machinery of calculating a magnitude when the theorem really was more intuitive and connected better to early ideas of single-variable calculus. So in short, the theorem is actually how we would find limits. I hoped that helped. Let me know if you have a follow up.
@@georgefsweeney Thanks!
Thanks a lot professor I follow you from Algeria.
Wonderful Bouazabachir4286. I am looking forward to hearing from a lot more people. I hope this helps.
swag
In case of Gaus elimination change matrix to a row echelon form??
That is correct. Gaussian Elimination transforms a matrix to row echelon form. Gauss-Jordan Elimination transforms matrices to their reduced row echelon form. The process is virtually identical and I think the video shows both methods. For Gaussian Elimination, just stop at the row echelon form.
@@georgefsweeney thanks for reply
thank you so much !!
You are so welcome!
My discrete math exam is in 45 minutes, and this was the last topic I needed to clean up before going in. Very concise and simple explanations with great examples for both this video and the one-to-one video. Thank you so much!
I am so glad to hear it. I hope your exam went well.
how the heck did you get your x values to plug in. you showed visuals and all but then skipped over how out got 0.1, 0.3, 0.5, 0.7, and 0.9 RIPPPP
Because we are breaking the interval up into 5 parts and the interval is from 0-1, we get each interval is a length of .2. So the first interval goes from 0-.2. Then we take the midpoint of each section, so that first midpoint is .1. Then, .3 and so on. You can see the explanation at about 1:15 in the video.
Thank you❤
You're welcome 😊
Omggg!!! I cannot thank you enough, god bless you with this video 😭💕
You're so welcome!
So if j was 2 how are you going to solve it
Instead of having the first value for the second summation be 1, we would start with 2 and then continue until we hit whatever (the top value was). I hope I am answering your question. In the video, I start each of the second summations at 1, but you can start with any value you would like. It is the same as if we were doing a single summation.
Why do you prove the amount of postage is greater than 8, not 6? Is it because that is the first value that combines 5 and 3, whereas the values before that are independent?
We need to have three consecutive values that can be made using 3 and 5 cent stamps so that we can just add a 3 cent stamp in the proof to create the next value in the sequence. But we cannot create a 7 cent stamp using 3 and 5 cent stamps, so we start at 8= 5+3, 9=3*3 and 10=5*2. I hope that helps.
I LOVE YOU
Thank you !
You're welcome!
You are the best .
I am glad it helped.
Why do u choose 3^3🥲
I chose 3^3 because I wanted to have e be relatively prime to 832, but at the same time I wanted it to be relatively large for the purposes of teaching the encryption and for doing calculation. You can pick any number for e that you want as long as it is relatively prime to phi.
I can't express my gratitude enough for this video. Thank you so much!
You're very welcome!
Thanks
You're welcome
bhen ki chut ek shabd nhi smjh aaya randike bcche angrez teri mkc 😠
Really thank you sir, i was looking for correct explanations and i got this one... thanks sir 😊
You are most welcome
man you explain things so well
Thanks for the kind words, I am glad it helped.
Thanks chief. You are a real one for making this video.
You're welcome. My pleasure
Thank you!
You're welcome.
What about x€R: 0<x<1😓
Sorry I missed these Tariq, but do you mean the cardinality? The cardinality for that set is uncountably infinite and has the same cardinality as the reals.
SIR, your video helped me so much. I'm so grateful for your work. Please keep it up <3 <3
Sir please make a series on relations computer science
Rahul, I have a whole series on functions, but are there other relations other than functions or are there other topics.
Sir in our academics we have antisymmetric, reflexive ,etc and Matrix based on relations and union of relational matrices, finding dom and range of relation, equivalence relation and partial order relation,hasse diagram lattice and many more. For function chp all topics are covered on the channel. Respected sir,. it would be very helpful if you cover all the relation topics too.😊
I was having trouble with my discrete structures class in studying Big O and functions, until I found you! Simple and fast explaining. Thanks for making these videos for students like me! I'm confident I'll past my midterm now 😁
That's great, Kendall. I am glad I could help.
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