Відео

filling order is incorrect, use electron configuration as reference

There's a big problem with this theorem's definition of a side. For an isosceles triangle, the base's midpoint IS one of incircle's points of tangency, which would mean that the triangle only has 2 sides. For an equilateral triangle, the 9 point circle IS the incircle, which means there would be no sides at all.

Are we still calling the 9 point circle the 9 point circle

people forget that the most important property here is that there is only one

Bruh!!!!!!!! 😎

can you do a tutorial on trackers? im using your code on making the tangent line, and im trying to figuer out how to move the points so that the slope of the tangent line changes while its moving.

code?

Oof. Looks like you forgot the fourth rule for a side of a triangle: Shares endpoints with another side Edit: I'm just playing. I didn't know about this neat fact.

Nice bro And you me

x - 14 - 7x = 2 x - 7x - 14 = 2 x - 7x = 16 -6x = 16 6x = -16 x = -8/3

Solution: x + 1/x = 3 Transforms into: (x^2 + 1)/x = 3 x^2 + 1 = 3x x^2 - 3x + 1 = 0 x = (-b ± sqrt(b^2 - 4ac))/2a x = (3 ± sqrt(9 - 4))/2 x = (3 + sqrt(5))/2 x = (3 - sqrt(5))/2 Find x^2 + 1/(x^2) Lets rewrite: x^2 + x^(-2) Put x in: ((3 + sqrt(5))/2)^2 + ((3 + sqrt(5))/2)^-2 And: ((3 - sqrt(5))/2)^2 + ((3 - sqrt(5))/2)^-2 Lets solve one of them: (a-b)^2 = a^2 + b^2 - 2ab (1.5 - sqrt(5/4))^2 = 3.5 - sqrt(11.25) + 1/(3.5 - sqrt(11.25) ≈ 7.00000158554 Answer: ≈ 7.00000158554

very nice you bad boi!!!!!!!!!!!!!!

what about me answer= 7

cool man!!!

7

X=2

X=2

X=4

X=4

I will be back soon 😅

Bohr considered single electron species. Wrong illustration

Hey nice video, just a heads up on the thumbnail, i think the limit might be the wrong way around, so as h approaches 0

I like how this uses phonk music.

This is a great way to show the 6 trig functions on 1 diagram! Keep it up!

thats very beautiful can you give me the source of code pls 🥰🥰🥰