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Ex 2.5 first sums 103 × 107=(100+3) × (100+7) , x=100, a=3, b=7 x^2+(a+b)x+ab, 100^2+(3+7)100+3×7= 10000+1000+21= 11021 ans second sums 95×96 = (90+5)× (90+6) let the x=90, a=5,;b=6 x^2+(a+b)x+ab = (90)^2+11×90+5×6, = 8100+990+30= 9120 ans Third sums 104 × 96 = (100+4)× (100-4)= x^2+;(a+b)x+a.b= 10000+(4-4)100-16 = 10000+0×100-16 = 10000-16 =9984 ans

First sums (x+4) (x+10), x(x+10)+4(x+10),;= x^2+10x+4x+40 or X^2+14x+40 , second sums (x+8) (x-10) =✓d(x-10)+8(x-10) = x^2-10x+8x-80 or x^2-2x-80 ans. Third sums (3x+4) (3x-5)= 3x(3x-5)+4(3x-5), = 9x^2-3x-20 ans fourth sums (y^2+3/2) (y^2-3/2) formulab a^2-b^2) (y^2)^2- (3/2)^2 = y^4-9/4 ans fifth sums (3-2x) (3+2x)= 3(3+2x)-2x(3+2x)= 9+6x-6x-4x^2= +6x-6x is cancelled 9 - 4x^2 ans

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