Dilemmas Decoder
Dilemmas Decoder
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Shortest Distance After Road Addition Queries I |#leetcode #potd | 27-11-2024| |@DecodeMaster01
Code Is In Description:
Intuition:
The problem at hand requires determining the shortest path from city 0 to city n - 1 after each road addition query. The main challenge lies in efficiently updating the shortest path after each road is added. By leveraging Breadth-First Search (BFS), we can dynamically update the shortest path for each query.
Approach:
Initial Road Setup:
The cities are initially connected in a linear fashion: city 0 to city 1, city 1 to city 2, and so on up to city n - 2 to city n - 1.
Graph Representation:
Represent the cities and roads using an adjacency list. Each city points to its next city in the initial setup.
Breadth-First Search (BFS):
Use BFS to calculate the shortest path from city 0 to city n - 1.
BFS works well for finding the shortest path in an unweighted graph because it explores all nodes at the present depth level before moving on to nodes at the next depth level.
Processing Queries:
For each query that adds a new road, update the graph to include this new road.
Run BFS from city 0 to city n - 1 to determine the new shortest path after each road addition.
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Переглядів: 0

Відео

Smallest Positive Missing Number|GFG POTD #gfg #potd | 27-11-2024| |@DecodeMaster01
12 годин тому
Code Is In Description: Intuition: The key idea is to place each number in its correct position (i.e., the number 1 at index 0, the number 2 at index 1, etc.). By doing this, we can quickly identify the smallest missing positive integer by simply traversing the array. Approach: Position Correction: Iterate through the array. For each element arr[i], check if it is in its correct position (i.e.,...
Find Champion II |#leetcode #potd | 26-11-2024| |@DecodeMaster01
Переглядів 32 години тому
Code Is In Description: Intuition for Finding the Champion in a DAG Tournament: In a tournament represented by a Directed Acyclic Graph (DAG), each team is a node, and a directed edge from node a to node b implies team a is stronger than team b. The champion is the team with no incoming edges, meaning no other team is stronger. To determine the champion, we need to identify nodes with zero inco...
Max Circular Subarray Sum|GFG POTD #gfg #potd | 26-11-2024| |@DecodeMaster01
Переглядів 332 години тому
Code Is In Description: Intuition for Maximum Circular Subarray Sum The Maximum Circular Subarray Sum problem extends the classic subarray sum problem to circular arrays, where the end of the array wraps around to the beginning. The challenge is to account for this circular nature and find the maximum subarray sum, whether it's a contiguous segment in the middle of the array or spans from the e...
Sliding Puzzle|#leetcode #potd | 25-11-2024| |@DecodeMaster01
Переглядів 54 години тому
Code Is In Description: Intuition for Sliding Puzzle Problem: The Sliding Puzzle problem can be visualized as a state-space search problem where each state represents a configuration of the puzzle. The goal is to transform the initial state into the target state [[1,2,3],[4,5,0]] using the least number of moves. Each move involves swapping the empty space (0) with one of its adjacent tiles. The...
Maximum Product Subarray|GFG POTD #gfg #potd | 25-11-2024| |@DecodeMaster01
Переглядів 114 години тому
Code Is In Description::: Intuition and Approach: Two Traversals: Traverse the array twice, from left to right and right to left, to handle cases where the product of a subarray turns from negative to positive due to a negative number or a zero resetting the product. Initialization: left and right are initialized to 1. maxLeft and maxRight are initialized to INT_MIN to keep track of the maximum...
Maximum Matrix Sum |#leetcode #potd | 24-11-2024| |@DecodeMaster01
Переглядів 557 годин тому
CODE IS IN DESCRIPTION.. Intuition The goal of the problem is to maximize the sum of all elements in the matrix after performing an allowed operation (multiplying adjacent elements by -1) any number of times. Since multiplying by -1 changes the sign of the elements, the strategy involves understanding the impact of this operation on the overall sum. Key Observations: Absolute Values: The sum of...
Kadane's Algorithm |GFG POTD #gfg #potd | 24-11-2024| |@DecodeMaster01
Переглядів 327 годин тому
Code IS IN DESCRIPTION: Intuition Kadane's Algorithm works on the principle of dynamic programming. It keeps track of the maximum sum subarray ending at each position of the array and uses that to determine the overall maximum sum subarray. The key insight here is that a subarray with the maximum sum will either extend the previous subarray with a positive sum or start a new subarray if the pre...
Rotating the Box|#leetcode #potd | 23-11-2024| |@DecodeMaster01
Переглядів 199 годин тому
Intuition: Rotation and Gravity: First, rotate the box 90 degrees clockwise. After the rotation, stones will fall to the bottom or until they hit an obstacle. Gravity Simulation: After the rotation, simulate gravity by moving each stone down to the lowest available position in its column. Approach: Rotate the Box: Create a new matrix to store the rotated version of the original box. Use nested ...
Minimize the Heights I |GFG POTD #gfg #potd | 23-11-2024| |@DecodeMaster01
Переглядів 399 годин тому
Intuition: Sorting the Array: By sorting the heights, we can effectively analyze the effects of increasing or decreasing the heights around the smallest and largest values. Initial Difference: The initial maximum difference between the highest and lowest tower without any modifications. Iterating and Calculating: The idea is to minimize the maximum difference by checking the results of modifica...
Flip Columns For Maximum Number of Equal Rows|#leetcode #potd | 22-11-2024| |@DecodeMaster01
Переглядів 2512 годин тому
Intuition: The problem involves transforming a binary matrix by flipping columns to maximize the number of rows that have all equal values. The key intuition here is that two rows can be made identical by flipping the same set of columns if and only if they are either identical or complementary to each other. This means for each row, we either keep it as it is or flip it entirely, depending on ...
Stock Buy and Sell - Max one Transaction Allowed|GFG POTD #gfg #potd | 22-11-2024| |@DecodeMaster01
Переглядів 8612 годин тому
Intuition: The problem is to maximize the profit from a single transaction (one buy and one sell) of stocks, given their prices on different days. The key to solving this problem is to track the minimum price encountered so far and calculate the potential profit at each step by comparing the current price with this minimum price. This way, we can ensure that we are always considering the lowest...
Count Unguarded Cells in the Grid|#leetcode #potd | 21-11-2024| |@DecodeMaster01
Переглядів 6614 годин тому
Intuition: The goal is to count the number of unoccupied and unguarded cells in a grid where guards and walls are placed. Each guard can see all cells in the four cardinal directions (north, east, south, and west) unless obstructed by a wall or another guard. The main challenge is to efficiently mark all the cells that are guarded by these guards and then count the cells that remain unguarded. ...
Stock Buy and Sell - Multiple Transaction Allowed |GFG POTD #gfg #potd| 21-11-24| |@DecodeMaster01
Переглядів 7414 годин тому
Intuition: The problem of maximizing profit through multiple transactions involves identifying the optimal buy and sell points to capture all profitable price differences. The key insight is that profit can be accumulated by summing up all the increases between consecutive days where the price rises. This approach ensures that you capture all possible gains without missing out on potential prof...
Take K of Each Character From Left and Right|#leetcode #potd | 20-11-2024| |@DecodeMaster01
Переглядів 6616 годин тому
Intuition: The problem asks us to take at least k occurrences of each character ('a', 'b', and 'c') from a string s by removing characters from either end of the string. The goal is to find the minimum number of characters that need to be taken to meet this condition. If it's not possible to take k of each character, we should return -1. The challenge is to achieve this efficiently while handli...
Majority Element II | GFG Problem Of The Day || #gfg #coding | 20-11-24| @DecodeMaster01
Переглядів 3216 годин тому
Majority Element II | GFG Problem Of The Day || #gfg #coding | 20-11-24| @DecodeMaster01
Next Permutation|GFG Problem Of The Day| 19-11-2024|#gfg #coding @DecodeMaster01
Переглядів 1819 годин тому
Next Permutation|GFG Problem Of The Day| 19-11-2024|#gfg #coding @DecodeMaster01
Maximum Sum of Distinct Subarrays With Length K|#leetcode #potd | 19-11-2024| |@DecodeMaster01
Переглядів 2719 годин тому
Maximum Sum of Distinct Subarrays With Length K|#leetcode #potd | 19-11-2024| |@DecodeMaster01
Defuse the Bomb| leetcode || Problem Of the Day || 18-11-2024 | @DecodeMaster01
Переглядів 5421 годину тому
Defuse the Bomb| leetcode || Problem Of the Day || 18-11-2024 | @DecodeMaster01
Rotate Array| GFG Problem Of The Day| 18-11-2024|#gfg #coding @DecodeMaster01
Переглядів 2421 годину тому
Rotate Array| GFG Problem Of The Day| 18-11-2024|#gfg #coding @DecodeMaster01
Shortest Subarray with Sum at Least K|#leetcode #potd | 17-11-2024| |@DecodeMaster01
Переглядів 25День тому
Shortest Subarray with Sum at Least K|#leetcode #potd | 17-11-2024| |@DecodeMaster01
Reverse an Array|GFG Problem Of The Day| 17-11-2024|#gfg #coding @DecodeMaster01
Переглядів 16День тому
Reverse an Array|GFG Problem Of The Day| 17-11-2024|#gfg #coding @DecodeMaster01
Find the Power of K-Size Subarrays I |#leetcode #potd | 16-11-2024| |@DecodeMaster01
Переглядів 22День тому
Find the Power of K-Size Subarrays I |#leetcode #potd | 16-11-2024| |@DecodeMaster01
Move All Zeros to End|GFG Problem Of The Day| 16-11-2024|#gfg #coding @DecodeMaster01
Переглядів 22День тому
Move All Zeros to End|GFG Problem Of The Day| 16-11-2024|#gfg #coding @DecodeMaster01
Shortest Subarray to be Removed to Make Array Sorted|#leetcode #potd | 15-11-2024| |@DecodeMaster01
Переглядів 19День тому
Shortest Subarray to be Removed to Make Array Sorted|#leetcode #potd | 15-11-2024| |@DecodeMaster01
Second Largest|GFG Problem Of The Day| 15-11-2024|#gfg #coding @DecodeMaster01
Переглядів 25День тому
Second Largest|GFG Problem Of The Day| 15-11-2024|#gfg #coding @DecodeMaster01
Minimized Maximum of Products Distributed to Any Store|#leetcode #potd| 14-11-2024|@DecodeMaster01
Переглядів 26День тому
Minimized Maximum of Products Distributed to Any Store|#leetcode #potd| 14-11-2024|@DecodeMaster01
Nearly sorted|GFG Problem Of The Day| 14-11-2024|#gfg #coding @DecodeMaster01
Переглядів 7День тому
Nearly sorted|GFG Problem Of The Day| 14-11-2024|#gfg #coding @DecodeMaster01
Count the Number of Fair Pairs|#leetcode #potd | 13-11-2024| |@DecodeMaster01
Переглядів 1914 днів тому
Count the Number of Fair Pairs|#leetcode #potd | 13-11-2024| |@DecodeMaster01
Intersection Point in Y Shaped Linked Lists|GFG Problem Of The Day| 13-11-24 @DecodeMaster01
Переглядів 814 днів тому
Intersection Point in Y Shaped Linked Lists|GFG Problem Of The Day| 13-11-24 @DecodeMaster01