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C
use the complex radical formula: sqrt(a-sqrtb)=sqrt((a+sqrt(a^2-b))/2)- sqrt((a-sqrt(a^2-b))/2)={a=10, b=7, sqrt(a^2-b)=sqrt(100-75)=5}=sqrt((10+5)/2)-sqrt((10-5)/2)=sqrt(15/2)-sqrt(5/2)=sqrt5 • (sqrt(3/2)-sqrt(1/2))={x sqrt (2/2)}= (sqrt10 • (sqrt3-1))/2
Let's assume that the solution is a + b*sqrt(3), and let's square both sides. 10 - 5*sqrt(3) = a^2 + 3b^2 + 2ab*sqrt(3) comparing free coefficients and coefficients at sqrt(3) we have: a^2 + 3b^2 = 10 2ab = -5 Solving this gives for a + b*sqrt(3) a positive and a negative (prohibited) answer, and we choose the positive answer sqrt(7.5)-sqrt(2.5). Did we simplify?
4 is poorly written as y.
17
D
В
√(4³+4³+4³)=√(4³×3)=2³√3=8√3
Какое-то странное решение. Ответ получился длиннее и сложнее чем само задание.
B
16
8
(2*(1/3)(/(2/9)=9/3=???
A.3😊
3
3 because -6 ----- -18
B😊
5
5
C 16
32=2^5, 8=2^3 2^5*2^3= 2^8 (2^8)^(1/2)= 2^4 How much is 2^4 ??? This is the correct answer.
A.5😊
16
C.1/8😊
C
c
C
16.67*2=33.34
3*5^(-3)/(3*5^(-4))=5^(-3)*5^(4)= 5^(-3+4)=5^1
5
15
Incorrectly !😟
Es 5
B
4🎉
This is very simple, but is great practice because the problem can be done mentally.
A
(5^1/2)*(2-3^1/2)^1/2 =( 2.5)^1/2*(3^1/2-1)^1/2 = (5*(3^1/2-1)/2)^1/2
This is an arithmetic problem. The multiplication operator is required because that's what they teach in school.
D
il risultato è 24 cioè 576^1/2
Nói thật lòng: xem bạn làm toán quá chán
D
C
or: X√X=25×5 X√X=25√25 X=25
I was just about to comment the same thing.
There is a rule that (x+1)^2 - x^2 = 2*x + 1. So (40+1)^2 -40^2=81. √81=9. Everyone can derive this rule using the formula for the square of the sum (a+b)^2=a^2+2*a*b+b^2
𝚗𝚘𝚗𝚎 𝚝𝚑𝚎 𝚊𝚗𝚜𝚠𝚎𝚛 𝚒𝚜 𝟸𝟺
None
2^7
B
128
9