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Brainy Nerd Tutor
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Приєднався 20 лип 2021
Integral of xe^-x^2 from 0 to infinity - updated 💪
Integrate xe^-x^2 from negative infinity to infinity using a u-substitution. The answer is 1/2. This function is also expressed as xe^(-x^2). This is a Gaussian function that is common in calculus, physics, and chemistry.
I got tons of modifications of this type of integral. Check them out in my integrals playlist!
ua-cam.com/play/PLXnxOygSB_fw7JRN4jDOZLH-y54kMXWNj.html
I got tons of modifications of this type of integral. Check them out in my integrals playlist!
ua-cam.com/play/PLXnxOygSB_fw7JRN4jDOZLH-y54kMXWNj.html
Переглядів: 132
Відео
Integral of xe^-ax^2 from 0 to infinity - updated 💪
Переглядів 380День тому
Integrate xe^-ax^2 from neg infinity to infinity using a u-substitution. The answer is 1/2. This function is also expressed as xe^(-x^2). This is a Gaussian function that is common in calculus, physics, and chemistry. I got tons of modifications of this type of integral. Check them out in my integrals playlist! ua-cam.com/play/PLXnxOygSB_fw7JRN4jDOZLH-y54kMXWNj.html
Integral of e^-ax^2 from 0 to infinity - updated 💪
Переглядів 38414 днів тому
The integral of e^-x^2 from 0 infinity to infinity is sqrt(π/a)/2. This function is also expressed as e^(-x^2). This is a Gaussian function that is common in calculus, physics, and chemistry. Here's a super-detailed version of this integral: ua-cam.com/video/qa9CKGE1EMU/v-deo.html I got tons of modifications of this type of integral. Check them out in my integrals playlist! ua-cam.com/play/PLXn...
partial fractions integral 1/(1-x^2)
Переглядів 6921 день тому
Use partial fractions to integrate 1/(1-x^2). I go through it step-by-step and explain everything. Need more integrals?! Check out my playlist: ua-cam.com/play/PLXnxOygSB_fzFTgdHA_QRvw6r-CHv7077.html
Trig Identity integral - Exam Problem💪
Переглядів 185Місяць тому
Integrate (tan θ)^3(sec θ)^4 quickly using a trig identity and a 'u' substitution Link to the derivative of tan(θ): ua-cam.com/video/DQr8IizPAic/v-deo.html Check out this one...integrate e^-2xcosx using an awesome substitution ua-cam.com/video/c0q0bNy7KE0/v-deo.html 💪 check out MORE integrals here: ua-cam.com/play/PLXnxOygSB_fzFTgdHA_QRvw6r-CHv7077.html&si=wKMAilGyMZYkDg2Q
Integral of (sin x)(cos x) using a trig identity 💪
Переглядів 946Місяць тому
Integrate (sin x)(cos x) quickly using a trig identity! I also did this integral using a simple u-substitution: ua-cam.com/video/_Nq9_vwynfk/v-deo.html 💪 check out MORE integrals here: ua-cam.com/play/PLXnxOygSB_fzFTgdHA_QRvw6r-CHv7077.html&si=wKMAilGyMZYkDg2Q
a BETTER description of internal energy 💪
Переглядів 69Місяць тому
Finally get a great understanding of what internal energy is. Check out how this is used in the 1st law of thermodynamics. ua-cam.com/video/gqeAJ832ZTE/v-deo.html Need to learn thermo? Check out my playlist here: ua-cam.com/play/PLXnxOygSB_fz8zeLzICsw-QB-szHJevc-.html
Integral of cos(ln x)/x 💪
Переглядів 6932 місяці тому
Integrate Integral of cos(ln x)/x really quickly using a 'u' substitution Link to the derivative of tan(θ): ua-cam.com/video/DQr8IizPAic/v-deo.html Check out this one...integrate e^-2xcosx using an awesome substitution ua-cam.com/video/c0q0bNy7KE0/v-deo.html 💪 check out MORE integrals here: ua-cam.com/play/PLXnxOygSB_fzFTgdHA_QRvw6r-CHv7077.html&si=wKMAilGyMZYkDg2Q
Justifying the 1st Law of Thermodynamics 💪
Переглядів 623 місяці тому
Here we setup the first law of thermodynamics as an equation and break it down so that you really understand what is actually going on. Here's my detailed video on systems, surroundings, and boundaries: ua-cam.com/video/eKFJ3cHpDFI/v-deo.html Here's my favourite video on the compression factor: ua-cam.com/video/ysPUOz6S72c/v-deo.html Need to learn thermo? Check out my playlist here: ua-cam.com/...
Introduction to Thermodynamics - Work, State Variables, Equations of State, Ideal vs Real Gases
Переглядів 1453 місяці тому
Begin your journey of thermodynamics here. We discuss the meaning of thermodynamics, work, state variables, equations of state, and ideal vs real gases. This video gives you a conceptual understanding of some fundamental concepts as you begin your thermodynamic journey. Here's my detailed video on systems, surroundings, and boundaried: ua-cam.com/video/eKFJ3cHpDFI/v-deo.html Here's my favourite...
Systems, Surroundings, Boundaries - Thermodynamics 💪
Переглядів 863 місяці тому
This is a thorough and introductory dive into the types of systems and boundaries encountered in thermodynamics. It is crucial to exactly define the systems, surroundings, and boundaries when learning thermodynamics. Be the thermo goat and check out my whole thermodynamics playlist here: ua-cam.com/play/PLXnxOygSB_fz8zeLzICsw-QB-szHJevc-.html&si=F9lDFjL5bU6ILvty
...integral of (sin x)(cos x)💪
Переглядів 1724 місяці тому
Integrate (sin x)(cos x) really quickly using a 'u' substitution Check out this one...integrate e^-2xcosx using an awesome substitution ua-cam.com/video/c0q0bNy7KE0/v-deo.html Here's the video where I solved it be letting u = sin x ua-cam.com/video/lDIigwig5ng/v-deo.html 💪 check out MORE integrals here: ua-cam.com/play/PLXnxOygSB_fzFTgdHA_QRvw6r-CHv7077.html&si=wKMAilGyMZYkDg2Q
but the integral of sin(ln x)/x is too easy 💪
Переглядів 6484 місяці тому
Integrate sin(ln x) - x really quickly using a 'u' substitution Integrate e^-2xcosx using an awesome substitution ua-cam.com/video/c0q0bNy7KE0/v-deo.html 💪 check out MORE integrals here: ua-cam.com/play/PLXnxOygSB_fzFTgdHA_QRvw6r-CHv7077.html&si=wKMAilGyMZYkDg2Q
Integral using the Gamma function 💪
Переглядів 5076 місяців тому
Integrate x^(3/2)e^(-ax) from 0 to infinity quickly the Gamma Function, Γ(z). Check out how to integrate the Gaussian function e^-x^2 from 0 to infinity also using the Gamma Function, Γ(z). ua-cam.com/video/nOmYaINuk8k/v-deo.html I've got TONS more harder integrals here: ua-cam.com/users/playlist?ua-cam.com/play/PLXnxOygSB_fzZ3RPpowYPJjMQkGzSPQSv.html Check out my calc 2 integrals here ua-cam.c...
Integral of 1/sqrt(1+x^2) 💪
Переглядів 3186 місяців тому
Integrate 1/sqrt(1 x^2) really quickly using the reverse power rule! Here's a trig substitution integral for you to try: ua-cam.com/video/t3C60W8VHSU/v-deo.html 💪 check out MORE integrals here: ua-cam.com/play/PLXnxOygSB_fzFTgdHA_QRvw6r-CHv7077.html&si=wKMAilGyMZYkDg2Q
Integral of (x^t-1)/lnx using Feynman's Trick 💪
Переглядів 3619 місяців тому
Integral of (x^t-1)/lnx using Feynman's Trick 💪
Integral of (x^2-1)/lnx using Feynman's Trick 💪
Переглядів 1,5 тис.9 місяців тому
Integral of (x^2-1)/lnx using Feynman's Trick 💪
Integral of (x-1)/lnx from 0 to 1 using Feynman's Trick 💪
Переглядів 46410 місяців тому
Integral of (x-1)/lnx from 0 to 1 using Feynman's Trick 💪
Integral of sinx/x from negative infinity to infinity 💪
Переглядів 2,2 тис.10 місяців тому
Integral of sinx/x from negative infinity to infinity 💪
Integral of (-x)^ne^-x using the Feynman Method 💪
Переглядів 92510 місяців тому
Integral of (-x)^ne^-x using the Feynman Method 💪
Integral of x^100e^-x using Feynman's Trick 💪
Переглядів 1,2 тис.10 місяців тому
Integral of x^100e^-x using Feynman's Trick 💪
Leibniz Integral Rule - updated! 💪
Переглядів 8 тис.10 місяців тому
Leibniz Integral Rule - updated! 💪
Integral of e^-x^2 using Feynman's Trick 💪
Переглядів 7 тис.10 місяців тому
Integral of e^-x^2 using Feynman's Trick 💪
Integral of e^-x^2 from 0 to infinity - super detailed! 💪
Переглядів 3,7 тис.10 місяців тому
Integral of e^-x^2 from 0 to infinity - super detailed! 💪
Integral of e^-x^2 using the Gamma function 💪
Переглядів 2,3 тис.10 місяців тому
Integral of e^-x^2 using the Gamma function 💪
yes yes yes
🥰🥰
😍😍
u are super genius terry 😍😍
Amazing !
Minor correction "anything to the power 0" is not 1. not if the anything is 0.
Hi sir, which software do you use to record your videos?
i love you
this is great stuff! i hope you can derive the physics of a pendulum without the typical derivation of sin theta ~ theta. in other words, the bessel functions of the first and second kinds and how to derive the constants
Just substitute x^2=t. Differentiate and rearrange to get a form of Gamma function. Evaluate it by standard values. Simple.
Good stuff
thank you for the video! keep up the good work :)
This is the best. It is so clear because no step is skipped nor glossed over compared to other derivations.
but my book formula is Change of U= Q-W
In the notation with subtrction (∆U=q-w) work is "by" the system. In this way, work done "by" the system reduces the internal energy as it loses energy as work. You would plug in an positive number for work, which makes the term negative. In the notation with addition (∆Q=q+w), work is "on" the system. In this way, if negative work is done "on" the system (e.g., the system does positive work), then the system loses energy as work, so w is negative.
Thank you so much!!
00:50 brilliant video however one thing I do not understand is why you are evaluating sin(theta) and cos(theta) at pi/2 ? because isn't the integral going to infinity? thanks. otherwise great video keep it up
The integral in terms of 'x' is going to infinity. We let x = tanθ, so therefore tanθ will go to infinity. tanθ will go to infinity as θ goes to pi/2.
cosx is d(sinx)/dx so (sinx)^2/2+C
You helped me in thermodynamics and now in the Integrals I'm encountering in quantum mechanics. Thank you so much for this detailed version....loved the volume under integral explanation
Just to let you know, trig sub is normally a term used when changing from cartesian to polar coordinates, or when you substitute u to be a trigonometric function. It can be used for example in integrals like sqrt(1-x^2), where you take sin(t)=x, so t=arcsin(x) and get an easier integral to solve because sqrt(1-x^2) is now cos(t). And we get in this case the integral of cos(t)^2. What you did is just usage of the sum of angles formula for sin, and simple substitution when taking u=2x
yep youre right man i was just gonna say that
I updated the thumbnail. Thanks for letting me know.
@@brainynerdtutor1626 yw! Good video either way btw, it's also a useful integral with good technique usage that I enjoyed solving for the first time myself
It can also be solved by substitution method ie: let u=sinx Then du=cosx dx Then our original integral becomes integral of u du Then using the power rule the answer is : u^2/2 and we just substituted u= sinx so it is 1/2*(sin^2 x) + c.
u-substitution method is faster. I made a video on that too. ua-cam.com/video/_Nq9_vwynfk/v-deo.html
I be stuck in this one rn, where did the term at the left side of the equal sign came from (this: ∫e^2xsinxdx), i'm lost 😭
Been struggling with this. It was my good fortune to find your video. Much clearer presentation than most over lectures I have seen, and some of those were quite good. Kudos. Immediately subscribed to your channel.
Hope you have a nice life.
the integral that you said you did in your other video at 3:32 is actually root pi/2 not root pi....... this makes the integral in this problem equal to root pi/4 instead of root pi /2 ......
great video, really helped me get this into my head thankss :)
Thank you🎉
liked and subscribed bc this actually made me understand wtf was going on in these problems 😂
Thanks!
thank you! I was working on a similar problem and needed a sanity check. Yours is the only video I found that actually integrates the compressibility.
Thank you you help me solve this problem . Please make more of these videos
this 2 minutes of my life...i was struggling with a problem for phi-3 theory in QFT, struggled for a week and all i needed was the concept of this lecture!!!
Eyyyyyy, I know I am a bit late, but congratulations on finally finding out how to write "sin" and "ln" not in italic. Next step would be to "straighten up" the *d* as well and also distance it a little bit from the integrand. In LaTeX you can do it by defining ewcommand{\dint}[1]{\,\mathrm{d}#1} in the preamble and then simply write "\dint{x}" for the " dx" (including the space produced by "\,").
why is dW negative?
Awesome problem!!!!
Nice one!
Thank you so much! I like how encouraging this video is
wonderful!
bro thank you so fcking much for this video, you have no idea of how this helped me
😅aam i have a doubt if we have to find isothermal irreversible entropy for surrounding but with some pressure
This explanation is very well said in terms of defining why delta S rev can be equal to delta S Irrev Very concept clearing well done
Second time i landed on your channel ,i was integrating sinc function
u = lnx du = 1/xdx xdu = dx int(cos(lnx)/x)dx = int(cos(u)/x * xdu) = int(cos(u)du) = sin(lnx) + C
what software did you use to make this, was it done nearly entirely in editing software or did you use something else?
I used Keynote and my iPhone and edited it using DaVinci Resolve.
Thank you It helped a lot
I like the shirt
Anyone else only watching this because they saw this on TikTok?
Ty
Beautiful integral! Good job! 👏👏👏
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