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Muhammad Irshad
Pakistan
Приєднався 16 жов 2019
Welcome to the UA-cam Mathematics Channel of Muhammad Irshad
This channel provides solution of different mathematics problems related to different branches of mathematics especially
Calculus
Algebra
Geometry
Complex Numbers
Subscribe if you like Mathematics
This channel provides solution of different mathematics problems related to different branches of mathematics especially
Calculus
Algebra
Geometry
Complex Numbers
Subscribe if you like Mathematics
If α and β are roots of ax²+bx+c=0, find the value of 1/α-1/β
#maths
#quadraticroots
#algebra
If α and β are roots of ax²+bx+c=0, find the value of 1/α-1/β
#quadraticroots
#algebra
If α and β are roots of ax²+bx+c=0, find the value of 1/α-1/β
Переглядів: 18
Відео
Integral of √(1+sinx) || Integration of trigonometric functions
Переглядів 1122 години тому
#maths #calculus #integration In this video we shall learn how to find the integral of a trigonometric function.
Integral of sinh^5 x || Integration of Hyperbolic Trigonometric Functions
Переглядів 157 годин тому
#calculus #integration #hyperbolicfunctions In this video we shall learn how to integrate Hyperbolic Trigonometric Function sinh^5 x
1/(cosecθ-cotθ)=√((1+cosθ)/(1-cosθ)) || Proving Trigonometric Identities
Переглядів 317 годин тому
#mathematics #maths #trigonometry In this video we shall prove a trigonometric identity. Important trigonometric identities sinθ=1/cosecθ cosθ=1/secθ tanθ=1/cotθ cotθ=1/tanθ secθ=1/cosθ cosecθ=1/sinθ cos²θ sin²θ=1 1 tan²θ=sec²θ 1 cot²θ=cosec²θ tanθ=sinθ/cosθ cotθ=cosθ/sinθ
Expansion of (2a-1/2a)^3 || a minus b whole cube || (a-b)³=a³-3a²b+3ab²-b³ ||Algebraic Identity
Переглядів 219 годин тому
#maths #algebra #algebraicidentities a minus b whole cube In this video we shall learn how to expand (2a-1/2a)³ by using algeraic identity (a-b)³=a³-3a²b 3ab²-b³
Solution of Quadratic Equation by using Quadratic Formula || x^2-3x-5=0
Переглядів 99 годин тому
#maths #algebra #quadraticequation In this video we will learn how to solve a quadratic equation using quadratic formula.
If α and β are roots of ax²+bx+c=0, find the value of α/β+β/α
Переглядів 712 годин тому
#maths #quadraticroots #algebra If α and β are roots of ax² bx c=0, find the value of α/β β/α
1/(cosecθ-cotθ)=cosecθ+cotθ || Proving Trigonometric Identities
Переглядів 912 годин тому
#mathematics #maths #trigonometry In this video we shall prove a trigonometric identity. Important trigonometric identities sinθ=1/cosecθ cosθ=1/secθ tanθ=1/cotθ cotθ=1/tanθ secθ=1/cosθ cosecθ=1/sinθ cos²θ sin²θ=1 1 tan²θ=sec²θ 1 cot²θ=cosec²θ tanθ=sinθ/cosθ cotθ=cosθ/sinθ
Solution of Quadratic Equation by using Quadratic Formula || x^2-2x-1=0
Переглядів 612 годин тому
#maths #algebra #quadraticequation In this video we will learn how to solve a quadratic equation using quadratic formula.
Integral of cosx/(1+sinx) || Integration of Trigonometric Function
Переглядів 1512 годин тому
#maths #calculus #integration In this video we shall learn how to integrate cosx/(1 sinx)
Expansion of (2a+1/2a)^3 || a plus b whole cube || (a+b)³=a³+3a²b+3ab²+b³ ||Algebraic Identity
Переглядів 2612 годин тому
#maths #algebra #algebraicidentities a plus b whole cube In this video we shall learn how to expand (2a 1/2a)³ by using algeraic identity (a b)³=a³ 3a²b 3ab² b³
(3m-7n)(3m+7n) || a square minus b square || Algebraic Identities
Переглядів 7814 годин тому
#maths #algebra #algebraicidentities In this video we shall learn how to expand algebraic expressions using the algebraic identity a square minus b square (a-b)(a b)=a²-b²
Linear Differential Equation || (x+1)y'-y=(e^x)(x+1)²
Переглядів 2414 годин тому
#maths #calculus #differentialequation In this video we shall learn how to solve a linear differential equation.
Integral of 1/(5-9x) || Integration
Переглядів 814 годин тому
#maths #calculus #integration In this video we shall learn how to find the integral.
sinθ/(1-cosθ)=cosecθ+cotθ || Proving Trigonometric Identities
Переглядів 714 годин тому
#mathematics #maths #trigonometry In this video we shall prove a trigonometric identity. Important trigonometric identities sinθ=1/cosecθ cosθ=1/secθ tanθ=1/cotθ cotθ=1/tanθ secθ=1/cosθ cosecθ=1/sinθ cos²θ sin²θ=1 1 tan²θ=sec²θ 1 cot²θ=cosec²θ tanθ=sinθ/cosθ cotθ=cosθ/sinθ
If α and β are roots of ax²+bx+c=0, find the value of α-β
Переглядів 2514 годин тому
If α and β are roots of ax² bx c=0, find the value of α-β
Express all the trigonometric ratios in terms of cosecθ
Переглядів 1914 годин тому
Express all the trigonometric ratios in terms of cosecθ
Expansion of (2a-1/2a)^2 || a minus b whole square || (a-b)²=a²-2ab+b² ||Algebraic Identity
Переглядів 11316 годин тому
Expansion of (2a-1/2a)^2 || a minus b whole square || (a-b)²=a²-2ab b² ||Algebraic Identity
If α and β are roots of ax²+bx+c=0, find the value of α²+β²
Переглядів 1719 годин тому
If α and β are roots of ax² bx c=0, find the value of α² β²
Linear Differential Equation || y'+y/x=e^x
Переглядів 819 годин тому
Linear Differential Equation || y' y/x=e^x
Expansion of (2a+1/2a)^2 || a plus b whole square || (a+b)²=a²+2ab+b² ||Algebraic Identity
Переглядів 2319 годин тому
Expansion of (2a 1/2a)^2 || a plus b whole square || (a b)²=a² 2ab b² ||Algebraic Identity
Integral of 1/(1+cothx) || Integration of Hyperbolic Functions
Переглядів 819 годин тому
Integral of 1/(1 cothx) || Integration of Hyperbolic Functions
Integral of cosech^4 x || Integration of Hyperbolic Trigonometric Functions
Переглядів 719 годин тому
Integral of cosech^4 x || Integration of Hyperbolic Trigonometric Functions
Nature of roots of a quadratic equation x²-2x+3=0
Переглядів 2319 годин тому
Nature of roots of a quadratic equation x²-2x 3=0
Linear Differential Equation || y'+y=e^x
Переглядів 1821 годину тому
Linear Differential Equation || y' y=e^x
(1+cosθ)/sinθ=cosecθ+cotθ || Proving Trigonometric Identities
Переглядів 1121 годину тому
(1 cosθ)/sinθ=cosecθ cotθ || Proving Trigonometric Identities
If α and β are roots of ax²+bx+c=0, find the value of 1/α+1/β
Переглядів 2921 годину тому
If α and β are roots of ax² bx c=0, find the value of 1/α 1/β
Express all the trigonometric ratios in terms of secθ
Переглядів 421 годину тому
Express all the trigonometric ratios in terms of secθ
Integral of sin x/(1+sin x) || Integration of Trigonometric Function
Переглядів 1421 годину тому
Integral of sin x/(1 sin x) || Integration of Trigonometric Function
a + by + c y^2 = 0 have roots 1/alpha and 1/beta 1/ alpha + 1/beta = - b /c (1/ alpha )( 1/beta ) = a / c (1/ alpha - 1/beta)^2 = ( b /c ) ^2 - 4 a / c =( b^2 - 4 a c) / c^2
I was trying to solve the integral of 1/x^2-1 with a hyperbolic function substitution, I guess I need to find another way
👏
Thanks bro
Nice sir❤
Sir hypotenuse to AB hai na
Yes. It was my mistake.
Sir hypotenuse to AB hai na
Sir hypotenuse to AB hai na
Sir hypotenuse to AB hai na
Sir hypotenuse to AB hai na
Sir hypotenuse to AB hai na
Thnx
How is √u = 1/2√u? (question)
In this video you can find the answer ua-cam.com/video/TF_QK1NUbwY/v-deo.html
Amazing lecture❤
Thank you! 🙂
Nice Explanation 😃
Thanks 🙂
Thanku sirr.. So helpful
Thanks 😊
2+i, 2-i
Thank you so much sir 😊😊
Most welcome
Wonderful explanation 😍🤩
Glad you liked it
Thanks sir 🙏🏻
So nice of you
2:02 -2 kaha se aaya ?
Use a short method....arcSinx=y for ease to solve... then use sin²k+cos²k=1
Why u didn't multiply 2 with one when u multiplied 2 with √2 ??👀
Wow ❤
Thanks 😊
❤❤❤
Thanks 😊
Sir are you angry 😤😂😂
Thankyou very much It helped me alot 😊
Glad to hear that
Good ❤🎉
Thank you 😊
Thank you, you taught me something new
Glad to hear that!
+++ ,5555❤
Hjhhjijigi
u are awesome Muhammad
Thank you 😊
(a²-b³)
thank you so much
You're welcome!
This the best explanation I have ever heard, thank you so much
Glad it was helpful!
simplicity
Scammer
Tem como postar resolução de exercícios aplicando esses resultados.
thanks a ;lot
Thanks
very helpful :) thank you
Glad it was helpful!
you're wrong, check it out on a graphing calculator or geogebra
Bhai Hindi me samjaa dete, haam sab indian hi hain
Thank you
You're welcome
Love your video ❤ it would be better if you explain the upcoming videos in hindi
I just did (a+b) + (a-b) = 10 and I simplified from there, is there a specific reason you did it your way? I got the same answer
Thanking you sir ji😊
Most welcome
ty bro
Welcome
Wrong u used (a-b)³ it was a³-b³
You're genius thanks
So nice of you
should'nt B=-3
Same doubt bro I'm in 11th 😂 it shouldn't btw