- 218
- 699 264
edyumath
Canada
Приєднався 7 лют 2016
A channel for students who are taking math following the Alberta Curriculum. Some of the courses that are covered are:
Math 20-1
Math 20-2
Math 30-1
Math 8
Feel free to contact me for private tutoring support.
Math 20-1
Math 20-2
Math 30-1
Math 8
Feel free to contact me for private tutoring support.
Math 30 1 Trigonometry I Lesson 2 part 3 of 3 Using the arc length formula updated
Math 30-1 Trigonometry I Lesson 2 part 3 of 3 Using the arc length formula @edyumath
Переглядів: 22
Відео
How to submit files in Google Classroom
Переглядів 389 годин тому
How to submit files to Google Classroom. Specifically for Wheatland Crossing Students. @edyumath
How to Multiply Numbers Close to 20 without a Calculator Trick Revealed
Переглядів 11812 годин тому
There is a way to multiply numbers close to 20 quickly without a calculator. An algebraic reason for why these steps work. @edyumath
Binomial Theorem Introduction and examples
Переглядів 5721 день тому
An introduction to the Binomial Theorem through expansion using distributive property then some examples on how to use the binomial theorem to solve puzzles. @edyumath
Combinations: How are they different than Permutations?
Переглядів 49Місяць тому
Combinations are different than Permutations Timestamps: 0:00 - Introduction to Combinations 0:30 - Formula for Combinations 1:15 - Example with Fruits 3:00 - Difference Between Permutations and Combinations 5:00 - Example Problem 9:00 - Wrap-Up and Key Points @edyumath
The Richter Scale, What is a log scale?
Переглядів 43Місяць тому
The Richter Scale, What is a log scale?
Point of Discontinuity Example: Rational Functions
Переглядів 496Рік тому
Point of Discontinuity Example: Rational Functions
Math 20-1 Absolute Value and Reciprocal Functions Lesson #3
Переглядів 709Рік тому
Math 20-1 Absolute Value and Reciprocal Functions Lesson #3
Math 30-1 Trigonometry II Lesson 8 Part II Trigonometric Identities
Переглядів 1,2 тис.2 роки тому
Math 30-1 Trigonometry II Lesson 8 Part II Trigonometric Identities
Math 30-1 Trigonometry II Lesson 2 Example 3
Переглядів 2,8 тис.3 роки тому
Math 30-1 Trigonometry II Lesson 2 Example 3
Math 20-2 Quadratic Functions Lesson 6
Переглядів 1 тис.3 роки тому
Math 20-2 Quadratic Functions Lesson 6
Math 20-2 Quadratic Functions Lesson 5
Переглядів 9533 роки тому
Math 20-2 Quadratic Functions Lesson 5
Math 20-2 Quadratic Functions Lesson 4
Переглядів 1 тис.3 роки тому
Math 20-2 Quadratic Functions Lesson 4
Math 20-2 Quadratic Functions Lesson 3
Переглядів 1,2 тис.3 роки тому
Math 20-2 Quadratic Functions Lesson 3
Math 20-2 Quadratic Functions Lesson 2
Переглядів 1,6 тис.3 роки тому
Math 20-2 Quadratic Functions Lesson 2
Math 20-2 Quadratic Functions Lesson 1
Переглядів 2,7 тис.3 роки тому
Math 20-2 Quadratic Functions Lesson 1
Math 20-2 Radicals Lesson 5 Solving Radical Equations Part 1
Переглядів 7373 роки тому
Math 20-2 Radicals Lesson 5 Solving Radical Equations Part 1
Math 20-2 Radicals Lesson 4 Dividing Radicals
Переглядів 7743 роки тому
Math 20-2 Radicals Lesson 4 Dividing Radicals
Math 20-2 Radicals Lesson 3 Multiplying Radicals
Переглядів 8303 роки тому
Math 20-2 Radicals Lesson 3 Multiplying Radicals
Math 20-2 Statistics Lesson 7 Confidence Intervals and Margin of Error
Переглядів 6083 роки тому
Math 20-2 Statistics Lesson 7 Confidence Intervals and Margin of Error
Math 20-2 Statistics Lesson 6 The Normal Distribution
Переглядів 6773 роки тому
Math 20-2 Statistics Lesson 6 The Normal Distribution
Math 20-2 Statistics Lesson 4: Z-score Tables
Переглядів 8413 роки тому
Math 20-2 Statistics Lesson 4: Z-score Tables
Or much simpler just split it into two easier problems and say: 25x20 + 25x8 = 500 + 200. Easy to do with head math.
This is only easier in the specific case of multiplying by 25 which isn't really the point of the video
@@kennyduncan7 Nah, since multiplying any number with 20 is just multiplying with 2 and adding a 0 to the result. Generally you can always split multiplication problems into smaller easier chunks which often result in an easy solution, even if the numbers are not "close to 20".
Of course use what strategy can work for you!
@@doodlePimp In the case of something like 24 × 27, most people would probably find the method highlighted in the video to be easier and quicker.
Mr Ed yu, do you think you can help me with radicals and rationals
Have a look at the radicals playlist. ua-cam.com/play/PLH2aYkBnhvWUjvq3kxMeSgZSuL6xlQ24b.html
@edyumath thank you
You are welcome. Browse the other playlists to find something appropriate to your course. And of course you can subscribe to see the updated content. :)
take two number somewhat close to and over 40. first number we will call: 40 + a second number will be: 40 + b multiplying these number algebraically can be written as: (40 + a) (40 + b) using the FOIL method this would become: 40^2 + 40a + 40b + ab using this algorithm add a + b to 40 ==> 40 + a + b multiply by 2 ==> 2(40 + a + b) multiply by 2 ==> 4(40 + a + b) multiply by 10 ==> 40(40 + a + b) add a * b ==> 40(40 + a + b) + ab 40(40 + a + b) + ab ==> 40^2 + 40a + 40b + ab Both methods are functionally equivalent, but FOIL works great on paper whereas this method is doable in your head when the numbers are not too big.
Excellent explanation! Will it work for numbers that are under 40?
@@edyumath Yes, it will work, but working with negative numbers is more error prone when doing it in your head. You could also change the base number from 40 to any other number, but then change the multiplication should change to the new base number. Expl: 50 is 100/2 48 x 44 = (50 - 2) (50 - 6) 50 - 2 - 6 = 42 42 / 2 = 21 21 * 100 = 2100 -2 x -6 = 12 2100 + 12 = 2112 ✅
Excellent observation! And great insight on thinking of 50 as 100/2!
Not really that much quicker than .. 2 x 26 = 52 add the zero 520 3 x 26 = 78 add 520 and 78 = 598
@@MrMousley you are right! Just thinking about how to use base 20 in multiplication lends well to how polynomials can be utilized. But you are correct. Many strategies can be used and some are just as fast or faster. Thanks for your comment.
Awesome
This is a amazing video helped me with my test😂
thank you you’re a life saver! my teacher never provided the video for this lesson 😢
You are most welcome! Best of luck to you!
You should really solve the practice Tests:)) Would really appreciate it!
Great idea! I'll think about that.
9+8+7+6+5+4+3+2+1=45, there you have it.
Yes. exactly. How does it compare to the combination formula.
A bit complicated. Use the handshaking lemma. The sum of the degrees is twice the number of edges. (10×9)/2
Absolutely! Very interesting how it relates to combinations. I was stuck in the combinations mindset. :)
The goat🐐
CAN YOU PLEASE PLEASE MAKE MORE VIDEOS ABOUT 8.5- Using Roots, Zeros, and X-ints to find Quadratics and all the other lessons in that book PLEASE! Your videos made me pass my test with a 80% PLEASE sir!
I will see what I can do! I am glad to hear you found the videos useful! Good luck in your math journey.
Holy we are getting Ed yu shorts, too OP.
:)
I'm assuming this is 30-1 right? Either way, loved your videos and they really do help people 😀
Yes, you are correct. This is for Math 30-1 in Alberta but binomial theorem is also studied in higher levels. I'm glad they help. Thank you for your kind words.
you're always my go to for when my teachers not here thanks for the help as always
Happy to help! Best of luck to you.
Oh my goodness, all of your videos are so helpful for studying, thank you.
You are welcome. Good luck in your math journey.
Can’t hear
this hpfl broski
Glad to help!
yaaaaarrrrraaaaaa
Good one
Thanks
when using system of equations aren't you supposed to subtract the top from the bottom? You added
Errors can be possible but the reason why we add or subtract with a system of equations is to somehow eliminate one of the variables so that we can arrive at an equation with just one variable. By adding, I was able to eliminate the b variable.
Your a great guy
at 10.08 Question F...How did you get the -3/2 exponent?
If you think of the -1 in a different way, specifically -2/2 then you can see it I believe. Think of negative half minus a full one more resulting in a negative 1.5 or -3/2
sigma
for class example 4 wouldn’t the horizontal translation coming before the horizontal stretch mean that only the variable (x) is multiplied by the reciprocal of b, instead of x and the translation?
What is the book called
Its from Absolute Publications but it's called iWrite Math
you are my saviour!! Thank you so much!
You are most welcome. Best of luck to you!
ur saving me, I love you
Good luck in your your math journey!
great video
Thanks!
These walkthroughs are incredibly helpful, thank you so much!!
You're very welcome! Good luck in your math journey!
oh ya bud
Thank you so much for these videos! They are very helpful! I was just wondering for class example 2b: could you put x=pi/6 + (2pi/3)n, n∈I? Just to share my rationale: In degrees, the angles are 30, 150, and 270 (I find working directly with degrees is significantly easier than radians). You can step between each by adding or subtracting 120 degrees, and if you add 120 to 270, you get 390, which is 360 + 30, meaning that it loops around. The relationship also works going the other way, going from 30 to -90 (which is a coterminal angle of 270). Finally, 120 degrees in radians is 2pi/3. So I think this would mean that a single equation for the general solution could be established. Again, thank you so much for making these videos!!
This helped me a lot with my work thank you Mr. Yu!
you are welcome. Best of luck.
is this math 30 1 the canada one
yes.
Is this MATH 202 statistics? I'm in 1st semester nursing program? Please help
No this is not statistics for your course but it does offer introductory material. Good luck with your math course.
is this explanation for calculas too ?
Thank you so much! You're literally the only thing getting me through finals <3
You're welcome! You got this! Good luck in your math journey.
Man thankyouuuu your lessons help me alot
Glad to hear that!
Legend
My exam for combinatorics is tomorrow and you actually helped so much! My teacher doesn’t go through examples this in depth, so thanks 🎉🎉
Glad I could help!
Hi! Wouldn't 7!/(3!4!) be equal to 35 and 4!/(2!2!) equal 6 thus 35 times 6 = 210?
yes. absolutely. I don't quite remember how I simplified it. Your way seems so much more straight-forward.
trash❤
Wow. Thank you for the simple and straightforward explanations. The first time I looked at perms and combs, I thought it was pretty hard, but learning from your thought process has made it much simpler. Your videos have helped carry me for 20-1 and 30-1. Thank you for the awesome work!
Thank you for your kind words. Best of luck in your journey.
Hey Ed! Could you point me to the direction to where I can find practice tests to study for? It'll be much appreciated. Thanks!
You may try exambank or look up Math 30-1 or you may look up each topic and study using sites like khan academy. Best of luck.
It's so helpful
Thank you
You're welcome
Isn't this 30-2?
There are some similar topics covered in both Math 30-1 and 30-2
For Class Example#1, did you edit this video at 13:39? Are you trolling us? Cuz the non permissible value is suppose to be π/2, the denominator cannot have cos x = 0, the x value = π/3 is not the non permissible value. You edited the video and gave the results for the restriction to make it look like π/3 is the npv. You even contradicted yourself later when answering d) at 16:26. Perhaps this is a mistake when you edited your video, but I spent about 15 minutes checking my calculator and trying to figure out why using π/3 wasn't showing the npv. Then I rewatched your video again and noticed what you did. I think you got confused for a moment and thought verifying of the statement was related to the restriction. The π/3 value is only meant for verifying, to show that the Y-value is the same for both sides which is 1.5 or 3/2.
Sorry for the confusion.
@@edyumath Sorry I just re watched this part, you did not state π/3 is the NPV, you stated that it verifies because the Y value is 1.5 for both Y1 and Y2. The calculator was highlighted on the previous entry you used which was the NPV, I myself made a insane assumption and was not listening to what you were saying.
For Class Example #1, d) you did not write the 5 before the cos. It should be d(2) = 12 + 5 cos(0.5(2)) = 14.7 meters. Just writing it for other students who may use your videos. Thanks for your work.
Thanks for that! Appreciate it.