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@@saurabhprajapati4502 thanks a ton for sparing your precious time to reach out . This made my day . Couldn’t be more grateful . Wish you all the very best

Thanks a lot for sparing your valuable time to reach out. Wish you all the very best for future.

Thank you for reaching out. As you correctly pointed out I should have taken g = 9.8. Would make sure to make use of the same in future posts.

Thanks a lot for writing. Glad that the content could assist you in the preparation. Wish you all the very best for exams.

Dear aspirant, thanks a ton for reaching out. Yes as you correctly pointed out A, B and C were the directions before striking. If the particles strike at a common point and change directions, their initial directionsA, B, and C describe their motion before the collision. Could you please explain your query a little further so that I can assist you .

@jayjoshi4877 your message means a lot. Thanks a ton for sparing your time to write back. Wish you all the best for your exams

@junaidmalik30 thanks a ton for sparing your valuable time to reach out. Apologies for the error in the solution.

Thank you for reaching out. So your question is what would be sign convention to use if we were to apply first equation of motion. Irrespective of which equation we apply the sign convention would remain the same and any sign convention used will give the same answer if applied correctly. But if you apply the first equation here the solution may not be obtained as it wouldn’t give us any common term to eliminate. Hope I have answered your query. If you feel that further resolution is needed, please feel free to write.

@@nothingButPhysicsPrep no sir I tried to solve it by 1st eqn and my Vb was coming grater then Va so I thought I was not using the right sing convention

@@b.n.mohanty6644could you please give me some time to make a detailed explanation for the same . Will get back to you as soon as possible. In the meanwhile could you please detail more on the exact doubt

@@nothingButPhysicsPrep what details can I share about the doubt??

@@b.n.mohanty6644so from I have understood- you wish to apply first equation of motion and find the relationship between va and vb. But while applying sign convention you are coming across an error.

@@aiims891 Thanks a ton for sparing your time to write back. Really glad that the content could assist you. Wish you all the good luck.

That’s a perfect approach . Less time consuming. Thanks a ton for writing.

thanks you for pointing out the error. Will definitely look into it.

thanks a lot sharing your thoughts. Your feedback is crucial to us. Could you please explain the problem faced so that we can have a detailed resolution of the same. Please share your valuable suggestions so that we can stay upto your expectations.

Hi Saurabh, I honestly don’t know how to express this properly, but I couldn’t be more grateful for your thoughtful comments and support. We’re doing our best to bring out new chapters as quickly as possible. In fact, the goal is to complete Mechanics before NEET 2025. However, it’s a huge task, especially with a very small team and limited working hours. I hope you can understand our situation on this side. It truly disappoints me when I can’t keep up with the pace of your feedback. Trust me, I genuinely feel this way, and so does the entire team. We are doing our absolute best. Most of the team members are either pursuing their master’s degrees or working full-time jobs, which makes it hard for them to commit fully to this project. Despite these challenges, we are working in every way possible to assist you and others in your preparation. Once again, thank you so much for reaching out to us and sharing your thoughts. I also want to sincerely apologize that we haven’t been able to deliver on schedule.

Thanks a ton for reaching out. First of all, the clarity of thought has to be appreciated. Its really a great thing that you are noting down the question meticulously. You are correct in your statement that the body is moving with uniform vel so acceleration should be zero so WD =F.S=ma.s =0 since acceleration is zero . Lets try to breakdown the statement and analyse in depth 1. Uniform Velocity: When a body moves with uniform velocity, its acceleration is zero. This means there is no net force acting on the body, i.e., the sum of all forces on the body equals zero. i.e. Fnet = 0. 2. Rough Horizontal Plane However in this case the body is moving in a ROUGH plane and therefore the Fnet is not zero as force of friction is always opposing the relative motion. 3. Magnitude of applied force Applied Force (𝐹applied): For the body to move at a constant velocity on a rough surface, the applied force must exactly balance the frictional force. 𝐹 friction = F( applied ) 4. Since the body is moving under the applied force, F(applied) is definitely doing work to counteract the friction and keep the body in a state of uniform motion. To summarise - The work done by the applied force is NOT zero because: The applied force 𝐹(applied) is non-zero (it is balancing the frictional force) as There is displacement 𝑠 where s in the direction of the applied force. Thus, the work done by the applied force is: 𝑊 = W = ( μN) * s and is of DEFINITE magnitude and not equal to 0 ( and is positive ) (applied force ) ( oppose friction force) Given statement is false because the work done by the applied force is not zero; it compensates for the work done against friction. The possibilty of doubt comes from equating the net force to zero with net work to zero . While it is true that the net force is zero, individual forces (like the applied force and friction) are doing work. The friction force does negative work (opposes motion) as theta = -180 , and the applied force does positive work (overcomes friction) as theta = 0 . These two works cancel out to maintain uniform velocity. I hope I have the explained the statement. If you need more detailed clarification please feel free to write back. I would be more than happy to assist you.

@nothingButPhysicsPrep thank you crystal cleared concept 🙏

Your message means a lot. Thanks a ton for sparing your valuable time to write back. All the best for your exams

Apologies. Thanks a ton for mentioning the error. Will address it as soon as possible.

Dear @gantitejaswini7927 we really appreciate your time to point the error. We have rectified the same. Thank you once again.

@@nothingButPhysicsPrep im glad

Thanks a ton for sparing your valuable time to write back. Wish you all the good luck for your exams.

@nothingButPhysicsPrep Thanks For Your Kind Words

@@Shreyas-q1uYour message truly made my day-thank you so much. Your kind words mean a great deal to me. I’m incredibly grateful for your support, and I wish you all the very best in your upcoming exams. Thank you again!

@@Shreyas-q1u will definitely look into to your valuable suggestion

@@srinivassathivada6471 your words means a lot. Thanks a ton for reaching out by sparing your valuable time. Wish you all the good luck .

Your words means a lot, thanks a ton for writing. This made my day. Couldn’t be more grateful. Wish you all the best for your preparation. Thank you once again for sparing your valuable time .

Yours words means a lot, thanks a ton for writing back. Wish you all the good luck for your exams.

Your words means a lot, thanks a ton for writing. Wish you all the best for your preparation.

Thanks a lot for reaching out and sharing your thoughts. We kindly request you to share your concern in detail so that the same can be addressed in the future solutions. So it would be great if you can elaborate further or suggest how to fix this so that we can improve . Thanks a ton again.

Your words means a lot, thanks a ton for sparing your valuable time to write back.

@nothingButPhysicsPrep sir please keep on making videos