Відео

wow❤❤

Perfect Sir Jee !

😮😮😮😮

😮😮😮

😮😮😮

Nice

Omveer

Nice😮😮

😮😮😮😮

Very good🎉🎉

THANK YOU SIR🎉🎉

❤❤❤❤

Tq so much

😮😮😮😮😮

Wow 😳😳😳😳

बाँसगढी नगरपालिकाको वनको क्षेत्र प्रतिशत कति हो

thank you sir we want more mathematics solutions without background bufallo sound....😇

Great sir🎉🎉🎉🎉🎉🎉

thankyou sar❤

Namaste sir

thank you sar❤❤

Thank you sar ❤

Thank you so much!! I couldn't find how to write formulas (e.g., square root sign). I'm blind 🙂 Thank you once again! All the bests for you!

Dhanyawad hajur 🙏🏻

Ram Prasad bahutt janee bhako xaa sir 😅

Ok sir ❤

Helpful❤❤

I've been following your UA-cam channel with great interest, and I truly appreciate the effort you've put into sharing math knowledge with the community. I wanted to offer a few suggestions that might help enhance the appeal of your channel. Firstly, I believe that the pacing of your videos could be optimized to keep viewers engaged throughout. Incorporating dynamic visuals, animations, and perhaps even reacting to intriguing math puzzles could make the content more awesome. Adding some well-thought-out sound design and proper background music could significantly elevate the viewing experience. This might help create a more immersive atmosphere that resonates with your audience's emotions. I've noticed that successful UA-camrs often find creative ways to entertain while educating. For instance, adding motion graphics to explain theorems or presenting fascinating mathematical facts through relatable examples could make the learning process even more enjoyable. Please understand that these are just my personal observations, and I'm by no means an expert or a seasoned UA-camr. My suggestions are simply based on insights I've gained from watching various content creators online. Thank you!

😢

Great

Very nice

Thank you❤ sir

Excellent sir

Good job keep it up.

great sir!!

Every mathematics teacher need this morale! Keep it up sir!

Very well material for us

Very Lucky Students.

You are doing better sir. Good luck

एकदमै राम्रो विधि ।।।।

Why FC = 2AB

ED=AB?how

Great job 👍📐

Great job 👍📐

Its Awesome

Great

How to solve ahead