Відео

please tell specifically the time at wihich 0.99 came. I will explain then

These are on my videos only

Hi, I did not get your question. Is it releated to video . mention the time

@@ArnavSreejith-g9i at 6:24 I have shown multiplication 160x2=320 however while writing the answer, I wrote 360 by mistake, thank you for identifying

you are welcome. and thank you for appreciating the effort

Thank you so much for identifying the calculation error. It is 133 degree at 10:20 time.

Please tell at what time in the video

you are welcome :)

Thank you

You are welcome 😇

HI at 24:22 I have explained that height is zero initially as a reference point so potential energy is zero

@@tahmeenakhan7248 okay thank you ❤️

@@sadiabatool7549 you are most welcome 😊

Thank you so much for finding the videos beneficial. Please share with other students.

Yes, it is correct. Conventionally the unknow variable x is written on the LHS.

Thank you so much for liking the video. Please share with other students

Thank you

I donot know someone asked for the solution so i just solved it.

Thank you for identify the human erroe :) let me correct it

yes we will add that distance

I am glad.

I have taken the energy equation for the whole system and hence the direction of the tension is opposite in particle A and particle B. Its impact will cancel out. If you will see the marking scheme there are two more methods given considering only particle A or only particle B. work done due to tension is taken into account there, then. Now about your second question i.e WD due to weight. we consider it when we are solving it by the newtons law method. in energy equation we have considered WD against gravity of that particle and thats why we consider height. if you notice particle A is moving along the ramp but for PE we have taken vertical height between distance of 0.5 m. weight is mg.

I am glad that you are finding videos helpful . I will upload the video soon on HCF and LCM.

Please tell me specifically at what time in this video. I will clarify the concept further.

Hi, I saw your question yesterday and I was also confused. I did some past papers so from what I understand If they want variance for sum of 2 (addition of 2 or more objects) Y= X + X = 2X Var(Y) = Var(X) + Var(X) = 2Var(X) If they want Variance for 2 times(twice), 3x (thrice) Y=2X Var(Y) = 2^2 Var(X) You have to check if the question is asking for a SUM or MULTIPLCATION For example, Total mass, W = Mass of 2 bags of sugar,S and 3 bags of coffee,C W= 2S + 3C Variance W = Variance of 2 bags of sugar + variance of 3 bags of coffee Var(W) = 2 Var(S) + 3 Var (C) Or maybe Mass of 1 bag of coffee is TWO TIMES mass of 1 bag of sugar C=2S Var(C) = 2^2 Var(S) Do more past papers and you will understand better. Basically learn to differentiate if question is asking for sum (X1 + X2) or multiples (2^2X) Hope it helps

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exactly the same i have explained so at what point in the video you got confused

most welcome

tkmathsisfun.blogspot.com/p/m1.html you may find these videos worth watching 😇

most welcome

Most welcome