Відео

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Sir there is a noisy background

This good thing about this video is it tells you predictive point also

Bawaal explanation din ban gaya

One of the best lecture sir 😊

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Good explanation sir😊

Very nice 🙂

You are great 🎉

Can't understand your explanation

👌

Which book prefer sir

Sir ye strong electrolyte k liy h k weak electrolytes k liy

Audio is not clear sir but u explained very well😊

Superb 😮

Explain each and every step.dont see & write

Yes

sir it is the topic of fugacity and mixture of non ideal gases ?

I dont know you have knowledge or not explain what you understood dont tell the textbook lines i have textbook as the same lines repeating sir! Engineering is about understanding concepts! not about scoring marks. Teach like this for 12th and 11th students not for us.

Thank you sir 😅😊

Hi sir this is siranjevi your student

Is it derivation of debye huckel limiting law at appreciable concentration of electrolyte

Super sir

Sir ap kis class ko padhate ho

Hello sir. Please read follows. ni:number of particles with energuy εi gi:number of states in energy level εi N=Σni E=Σniεi (n1,n2,･･･,nk):distribution P(n1,n2,･･･,nk):the probability that the distribution is (n1,n2,･･･,nk) (<n1>,<n2>,･･･,<nk>):disrribution in equilibrium 【Bosons】 P(n1,n2,･･･,nk)=(N!/Πni!)Πgi(gi+1)･･･(gi+ni-1)･exp{-(α1+α2･･･+αN)}･Πexp(-βεi)^ni αN:N is the subscript of α In equilibrium, P(<n1>,<n2>,･･･,<nk>)=Pmax Since P(･･･,<ni>+1,･･･)≒P(･･･,<ni>,･･･)=Pmax P(･･･,<ni>+1,･･･)/P(･･･,<ni>,･･･)≒1 Therefore P(･･･,<ni>+1,･･･)/P(･･･,<ni>,･･･)=(N+1)(gi+<ni>)exp(-αN-βεi)/(<ni>+1)≒1 N+1≒N, <ni>+1≒<ni> →　 N(gi+<ni>)exp(-αN-βεi)/<ni>≒1 (1) Accordingly　<ni>≒N(gi+<ni>)exp(-αN-βεi) And　N=Σ<ni>=Nexp(-αN)Σ(gi+<ni>)exp(-βεi) ∴ exp(αN)=Σ(gi+<ni>)exp(-βεi)≡ZN　　 ZN:N is the subscript of Z Therefore　αN=ln(ZN) By using (1)　<ni>/gi≒1/{(1/N)exp(αN+βεi)-1}=1/{(ZN/N)exp(βεi)-1} 【Fermions】 P(n1,n2,･･･,nk)=(N!/Πni!)Πgi(gi-1)･･･(gi-ni+1)･exp{-(α1+α2･･･+αN)}･Πexp(-βεi)^ni αN:N is the subscript of α In equilibrium, P(<n1>,<n2>,･･･,<nk>)=Pmax Since P(･･･,<ni>+1,･･･)≒P(･･･,<ni>,･･･)=Pmax P(･･･,<ni>+1,･･･)/P(･･･,<ni>,･･･)≒1 Therefore P(･･･,<ni>+1,･･･)/P(･･･,<ni>,･･･)=(N+1)(gi-<ni>)exp(-αN-βεi)/(<ni>+1)≒1 N+1≒N, <ni>+1≒<ni> →　 N(gi-<ni>)exp(-αN-βεi)/<ni>≒1 (2) Accordingly　<ni>≒N(gi-<ni>)exp(-αN-βεi) And　N=Σ<ni>=Nexp(-αN)Σ(gi-<ni>)exp(-βεi) ∴ exp(αN)=Σ(gi-<ni>)exp(-βεi)≡ZN　　 ZN:N is the subscript of Z Therefore　αN=ln(ZN) By using (2)　<ni>/gi≒1/{(1/N)exp(αN+βεi)+1}=1/{(ZN/N)exp(βεi)+1} 【Classical particles】 P(n1,n2,･･･,nk)=(N!/Πni!)Πgi^ni･exp{-α･N)･Πexp(-βεi)^ni In equilibrium, P(<n1>,<n2>,･･･,<nk>)=Pmax Since P(･･･,<ni>+1,･･･)≒P(･･･,<ni>,･･･)=Pmax P(･･･,<ni>+1,･･･)/P(･･･,<ni>,･･･)≒1 Therefore P(･･･,<ni>+1,･･･)/P(･･･,<ni>,･･･)=(N+1)gi･exp(-α-βεi)/(<ni>+1)≒1 N+1≒N, <ni>+1≒<ni> →　 N･gi･exp(-α-βεi)/<ni>≒1 (3) Accordingly　<ni>≒Ngiexp(-α-βεi) And　N=Σ<ni>=Nexp(-α)Σgiexp(-βεi) ∴ exp(α)=Σgiexp(-βεi)≡Z　　 Therefore　α=ln Z By using (3)　<ni>/gi≒Nexp(-α)exp(-βεi)=(N/Z)exp(-βεi)

Ion association concept is bejrrum model or not . please reply

Sir any other methods as present to determine activity and activity co efficient of non electrolutes

Thank you sir 🙏🙏 very useful this video sir 🙏

Complety english kakunda telugu lo kuda explain cheyandi sir

In the rate eqn , it is shown that k1(a-x) + k-1 x But while substituting the value of x It is shown that k1(a-x) - k-1x ..?

It's very useful sir 💯💥

So many mistaken with sign

Super sir

Sir excellent👍💯

Really wonder sir this notes is helpful for us in sem exams .......sir one request book notes show at last for 2 minutes sir to write in exam

Thank you sir❤❤❤

Sir

Sir urdu me lecture banaen

Sir which book refers

Sir plz mic ka use kre aawaj gunj rha he

What a shitty explanation

Nice teaching sir

Audio not clear

Sir ur voice not clear .😪

Thank you sir

alhumdulilah sir u r explanation is a very superb 👏 level tomorrow is my seminar, mam give me this topic before 2 3 days and I'm very scared because I didn't understand literally I'm finding in a youtube which I understood and after I explained to our class fellow and I was searching many channels but it was----- to my mind last I choose this channel and alhumdulilah I understand each and everything every point start taking notes inshallaha it was help to my semester also jazakallaha sir

Resound is coming We can't able to catch ur voice

Can i get your no.

Great explaination

Thank u so much sir and explain super sir😊