Відео

Glad you liked it

Thanks!

what d'you mean???

@@brontosauro2711 it's a mathematic formule...

@@Renkuren ゴゴゴゴゴ

@@brontosauro2711 ブブブブ

I do not know what it means either - believe it is Italian - but hey it's a comment and have not had one of those for a while. I'm still doing Math stuff but have been very busy. Best wishes.

You didnt understand?

Hi klag

Hi Klag, thanks for the comment. Not sure which bit ? refers to, let me know and I will try and explain. All the best.

Thanks for the comment. :-)

Hello Amina, a year of study ahead of you - wishing you all the best. A good tip with maths is if you get stuck, no need to struggle with it. Just look up the topic on youtube, then practice. Just practice little and often. Hope your studies go well.

Many thanks for the encouraging comment

Great, glad that Factorising Harder Quadratics helped. :-)

Thanks for the comment - great to know the video helped.

Great, glad it helped - good to have a reminder now and then.

Great, glad it was useful

Great, glad the video helped.

An example -6x^2-5x-1=0 first take the minus sign outside of a bracket and change all the signs to give -(6x^2+5x+1)=0 which is identical, then solve the expression inside the bracket as shown in the video. Hope that helps, and thanks for the comment.

Thank you for the comment, and for subsribing. I have just started uploading videos again - aiming for one a week, each Sunday. So coming this Sunday is Simultaneous Equations. All the best with your studies.

Thank you for the comment. Glad you liked the explanation. :-)

And the pic after watching?

Thank you for the comment and I am so glad the video was helpful :-)

Do you mean with the X on the top? It is possible to cancel when there is a common factor top and bottom. But in this case there is no common factor. If it was something like (4x+2y)/(x+y) then the top is twice the bottom so the x+y can be cancelled to give the answer 2. Hope that helps.

Great to hear you found it brilliant. Many thanks for the comment. :-)

Yes, your solution is valid. Your's is a negative top and bottom of my solution. And a negative divided by a negative will of course make a positive - so the same. As long as you follow the rule of doing the same to both sides, all should be Ok. Best wishes, Stephen

Glad to hear it helped. All the best :-)

2y=3x+6 I would first change this by dividing the equation by 2 to give y=1.5x+3 then plot it according to the technique shown. Hope that helps.

Thanks, that was helpful

Hello. You will be looking at differentiation. Paste this into youtube Core 1 - Differentiation (1) - Introduction and from first principles Also a web site I find useful is www.m4ths.com Hope this helps

Great, glad it helped.

Hi Matt. The answer is x=(y divided by (1-a)) The technique showing this starts at 3 minutes 20. Basically move the Y to the right side of the equation, bring the ax over to the left. Then you have a common factor in X on the left. This gives x(1-a)=Y Then all that is needed is to divide by (1-a). Hope that helps.

Oops I made a mistake. should be x=(-y divided by (1-a)) The reason being that when Y moves over to the right it becomes negative.

2 times 3 then 2 times -x then -x times 3 and finally -x times -x. This will give 6 -2x -3x +xsquared Then collecting the like terms we finally have 6 -5x + xsquared. I do apologise for the very slow reply.

+Jazzy W Thats why I came here too

haha lol

There is a good saying worth learning when squaring a bracket like this. It is. Square the first term, square the second term, then twice the product of the two. So square x. then square (-10)=+100. Then the product is -10x so twice the product is -20x. so the answer is x(squared) - 20x + 100. I do apologise for the very slow reply.

Thanks! Really helped

than you ***** :)

Hello. As it is shown the 4r cubed would cancel each other out. So # = 3v. But I do not think this is what you mean. A bit more information would be helpful. If it was just # = 3V/(4rcubed) then the best way to do this is first multiply both sides by rcubed. This gives rcubed X # = 3v/4. Then divide both sides by # which gives rcubed =3v/(4#) Then finally cube root both sides. which gives r= CubeRootOf(3v/4#). Hope that makes sense.

Sasmallmath I was asking you how do you make r the subject.

Glad you found it a good method.