Adam Bergeron
Adam Bergeron
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Introduction to Cell Division & DNA Structure
Introduction to Cell Division & DNA Structure
Переглядів: 680

Відео

Structure and Function of the Mitochondrion
Переглядів 1,8 тис.7 років тому
Structure and Function of the Mitochondrion
Introduction to Cell Biology: Prokaryotes vs Eukaryotes
Переглядів 2447 років тому
Introduction to Cell Biology: Prokaryotes vs Eukaryotes
Three point testcross
Переглядів 17 тис.8 років тому
Three point testcross
How to Use the Dilution Equation
Переглядів 157 тис.9 років тому
How to Use the Dilution Equation
Explain Everything
Переглядів 2299 років тому
Made with Explain Everything
Prof. Development - Flipped Classroom
Переглядів 949 років тому
Prof. Development - Flipped Classroom
Abnormal Chromosome Numbers
Переглядів 5 тис.9 років тому
Abnormal Chromosome Numbers
Calvin Cycle and Photorespiration
Переглядів 5159 років тому
Calvin Cycle and Photorespiration
Photosynthesis - Light Reactions
Переглядів 4039 років тому
Photosynthesis - Light Reactions
Facilitated Diffusion and Active Transport
Переглядів 6859 років тому
Facilitated Diffusion and Active Transport
Osmosis
Переглядів 3199 років тому
Osmosis
Membrane Transport - Diffusion
Переглядів 3319 років тому
Membrane Transport - Diffusion
Membrane Structure and Function
Переглядів 6399 років тому
Membrane Structure and Function
Energy and Enzymes
Переглядів 63310 років тому
Energy and Enzymes
Structure and Function of Carbohydrates
Переглядів 32 тис.10 років тому
Structure and Function of Carbohydrates
Structure and Function of Lipids
Переглядів 30 тис.10 років тому
Structure and Function of Lipids
Evidence for DNA as the Genetic Material
Переглядів 2,5 тис.10 років тому
Evidence for DNA as the Genetic Material
Origin and Propagation of the Action Potential - Part 2
Переглядів 60810 років тому
Origin and Propagation of the Action Potential - Part 2
Origin and Propagation of the Action Potential - Part 1
Переглядів 1,4 тис.10 років тому
Origin and Propagation of the Action Potential - Part 1
Origin of the Resting Membrane Potential
Переглядів 5 тис.10 років тому
Origin of the Resting Membrane Potential
Neurons and Neuroglia
Переглядів 21 тис.10 років тому
Neurons and Neuroglia
Biological Functional Groups
Переглядів 42 тис.11 років тому
Biological Functional Groups
Acid, Base, and Buffer Chemistry
Переглядів 3,4 тис.11 років тому
Acid, Base, and Buffer Chemistry
Drawing Lewis Structures for Biol. Mol.
Переглядів 32111 років тому
Drawing Lewis Structures for Biol. Mol.
Hypotheses, Variables, and Controls
Переглядів 15 тис.11 років тому
Hypotheses, Variables, and Controls
How to Create a Shared Folder using Google Drive
Переглядів 32711 років тому
How to Create a Shared Folder using Google Drive
How to Make Accurate Scientific Measurements
Переглядів 1,5 тис.11 років тому
How to Make Accurate Scientific Measurements

КОМЕНТАРІ

  • @Eiser_grayon
    @Eiser_grayon 9 днів тому

    thanks for the explanation

  • @NyamaiLiah
    @NyamaiLiah 3 місяці тому

    Thanks

  • @Paula-lt3ev
    @Paula-lt3ev 3 місяці тому

    Dietetics student here 😊 . Your videos are excellent. Very helpful.

  • @mamtalall6750
    @mamtalall6750 10 місяців тому

    Thank you so much. Excellent simplified explanation.

  • @rahafrahaf73886
    @rahafrahaf73886 Рік тому

    Thank you

  • @osmirod1
    @osmirod1 Рік тому

    IMPORTANT QUESTION: in what situation if ever are you able to solve for one of the two variables on the right side of the equation, that is, either c2 or v2?

  • @IWusHErE303
    @IWusHErE303 Рік тому

    Bro thank you I had to make a dilution lab and I forgot how this works you saved my butt thank you!

  • @uniteamerica9446
    @uniteamerica9446 Рік тому

    Thank you. I'm diluting rooting hormone to soak green giant arborvitae tree cuttings overnight. Now I know how to dilute my stock solution. I will successfully root my tree cuttings and sell them next year. You helped me make money grow on trees. Money really does grow on trees if you propagate and sell the right ones. Propagate and sell screening plants, hedge plants and ground covers. People usually by a lot more than 1 of these type of plants,

  • @rottenapple2276
    @rottenapple2276 2 роки тому

    The mitochondria is the powerhouse of the cell

  • @kamlablake6753
    @kamlablake6753 2 роки тому

    are the parents male or female i am confused as hell

  • @Alice444V
    @Alice444V 2 роки тому

    very helfpul and clear thanks!

  • @musamohammedmaud2497
    @musamohammedmaud2497 2 роки тому

    you’re indeed a man of your words #Dr.Ani John on UA-cam, after purchasing and using his herbal product for HSV2 I was totally cured permanently within few days. Thanks to #Dr.Ani John for the fast recovery

  • @annusharma4016
    @annusharma4016 2 роки тому

    Thank you 🙏🙏🙏

    • @musamohammedmaud2497
      @musamohammedmaud2497 2 роки тому

      you’re indeed a man of your words #Dr.Ani John on UA-cam, after purchasing and using his herbal product for HSV2 I was totally cured permanently within few days. Thanks to #Dr.Ani John for the fast recovery

  • @mohfa1806
    @mohfa1806 2 роки тому

    Hello and thank you for your great videos , i have a question please : when diluting a weak acid i noticed in the book that they use the dilution formula :C1V1=C2V2 based on the fact that the number of moles will stay constant , however for weak acid we know that upon adding water the dissociation of the weak acid increases to maintain balance and hence the number of moles of the weak acid decreases , so based on that how the dilution formula still applied?...thank you in advance.

    • @beautyqueen5002
      @beautyqueen5002 Рік тому

      The number of moles of weak acid does not change upon dilution because the dissociation of the weak acid in water is a reversible process. As the weak acid dissociates in water, it produces hydronium ions and the conjugate base of the acid. The concentration of hydronium ions increases, which increases the acidity of the solution and causes the weak acid to dissociate less. This is known as the common ion effect. When the weak acid is diluted with water, the total number of moles of the acid remains constant, but the volume of the solution increases. This results in a decrease in the concentration of the weak acid, which in turn decreases the concentration of hydronium ions in the solution. As a result, the dissociation of the weak acid increases to maintain the equilibrium concentration of hydronium ions. However, the increase in dissociation upon dilution is small compared to the total amount of weak acid present, and the total number of moles of the weak acid remains essentially constant. The dilution equation, C1V1=C2V2, assumes that the number of moles of solute remains constant upon dilution, which is generally true for weak acids and bases.

  • @douglasheinl250
    @douglasheinl250 2 роки тому

    Great video, thank you.

  • @wilmerpadron3622
    @wilmerpadron3622 3 роки тому

    You said early that you can't cancel unit's but later you do

  • @anamshehzadi5695
    @anamshehzadi5695 3 роки тому

    clearly explained

  • @devikanair44
    @devikanair44 3 роки тому

    I don’t imagine you’ll see this comment but I am a bit confused with negative control. You said if you remove the IV then you don’t get the DV. but in the situation with the bugs and meat the cover was the IV so if you removed it you’d get an effect no?

  • @ashrafshahrour6698
    @ashrafshahrour6698 3 роки тому

    ❤️❤️

  • @SachinSingh-xg8gg
    @SachinSingh-xg8gg 3 роки тому

    Thanks

  • @anitatiwari8688
    @anitatiwari8688 4 роки тому

    Ty so much ....it helped me allot sir....keep it up ...make more helpful videos for us ...❤❤☺

  • @Cosmuex
    @Cosmuex 4 роки тому

    "Scientist who guess are unemployed" lmaoo

  • @Dr-Garry
    @Dr-Garry 4 роки тому

    In our institute we take AP chemistry and I am just in grade 9-ASP( Advanced Science program)

  • @leslieenriquez4085
    @leslieenriquez4085 4 роки тому

    I just have trouble knowing what’s the c1 v1 and c2 v2 word problems confuse me 😥

  • @axtonjay3162
    @axtonjay3162 4 роки тому

    why is this so confusing????

    • @dejaharris735
      @dejaharris735 Рік тому

      literally didnt even write out the problem worked. Wish these tutors would go more in depth! Lazy

  • @mangsialthang585
    @mangsialthang585 5 років тому

    So useful 🙂

  • @toneshav340
    @toneshav340 5 років тому

    I thought Ketone has an attached Hydrogen not carbon ...

  • @tinnesarmin3258
    @tinnesarmin3258 5 років тому

    U r superb

  • @arpanalimbu9145
    @arpanalimbu9145 5 років тому

    Thanksss

  • @tezadoctorat7357
    @tezadoctorat7357 5 років тому

    Hey. Unfortunately the dilution equation can be applied only on molar concentrations. See Skoog : Fundamentals of analytical chemistry, 9th edition. page 75. " This equation is based on the fact that the number of moles of solute in the diluted solution must be equal the number of moles in the concentrated reagent.' For example: Let's say that you want to prepare 1 L of 15% H2SO4 solution (density: 1.095 g/mL) from 60 % H2SO4 (density 1.498 g/mL). We have to find out the volume needed. If we use the dilution equation we get that we need 250 mL of 60% H2SO4, but if we calculate correctly we obtain that we actually need only 182.7 mL. Here is the correct calculation: 15% means that 15 g H2SO4 is in 100 g solution. Using its density we calculate the solution's volume, that is V=m/d=100/1.095=91.32 mL. Next we calculate the amount of pure H2SO4 that is in 1L=1000 mL solution, which is going to equal 164.25 g pure H2SO4. Than we say that 60 g H2SO4 is in .......100 g solution 164.25 g H2SO4.........x = 273.76 g solution. And finally we transform the obtained mass into volume using it's density and the formula given earlier, so we get 182.7 mL, instead of 250 mL that we would get using the dilution equation.

  • @wat8437
    @wat8437 5 років тому

    Is this principle used in the manufacture of IV pharmaceutical solutions? They probably are since there's not much room for error

  • @penderchovwe351
    @penderchovwe351 6 років тому

    Thanks a lot

  • @nadifomuse512
    @nadifomuse512 6 років тому

    Thanks a lot

  • @mestudy6049
    @mestudy6049 6 років тому

    amazing! cleared out my doubt! thank u!

  • @sydneea9771
    @sydneea9771 6 років тому

    Why didn't you finish the serious of 4 😞 your videos really helped me! I need one on proteins at this moment in time.

  • @makuchii1
    @makuchii1 6 років тому

    thank you this video helped me a a lot !

  • @vandam7656
    @vandam7656 6 років тому

    very good explanation

  • @whelanylime
    @whelanylime 6 років тому

    I HAVE BEEN TRYING TO FIGURE OUT MY THREE POINT TEST CROSS PROBLEM FOR 3 HOURS AND YOU HAVE SAVED ME

  • @tanisha2659
    @tanisha2659 6 років тому

    how to find c2/vs

  • @yonasiloma2771
    @yonasiloma2771 7 років тому

    Language use English

  • @mailewilkey9491
    @mailewilkey9491 7 років тому

    In my school we take biology freshman year and chemistry sophomore lol

  • @sierraslyh6743
    @sierraslyh6743 7 років тому

    Actually I dont think the mistake at 12:56 was that you forgot to cross v and v+. I think you had them switched before they crossed because the results, CV-CT-V and +-+-+ matches the result from the table of values for 89 and 94. Great video, though! Thsnks!

  • @lynnecota9103
    @lynnecota9103 7 років тому

    So helpful!

  • @GameCritics7
    @GameCritics7 8 років тому

    you need better audio, just a recommendation

  • @salmael_badry2926
    @salmael_badry2926 8 років тому

    but ,sodium and potassium are positive charged ions How can the equilibrium potential of sodium positive charged and that of potassium is negative? explain ,please.

  • @InstaUEC1
    @InstaUEC1 8 років тому

    what about ethanol?

  • @kevinpham7380
    @kevinpham7380 8 років тому

    Thanks!

  • @TrueGoan1325
    @TrueGoan1325 8 років тому

    Hello Adam, Greeting to you from the UK, Great video I tried to copy the formula but I'm still too slow to grab your simplified teaching may be for various reasons. I wish you can help me here. Ok here is confusion, I'm trying to make a fertilizer stock solution of Mn in ppm I need Mn 0.8 ppm, in my final solution I do have a conversion factor i.e 4.061. so 0.8 times 4.061 = 3.2488, I take out the element purity of 90% which will be 3.2 *100/90 = 3.6. So this means I must have 3.6mg/l if I'm not mistaken. Now I want to make a stock solution 600x concentrate in a 50 liter tank, so 3.6*600 =2160 to convert into grams I /(divide) by 1000, so 3.6*600/1000 = 2.16gram . Am I right until now ? If I'm right I go a little further where the confusion begins and I need your precious help So my final solution tank is 3785liter and my stock solution of 600x concentration is 37.85 liter so do I need to take the 2.16grams *(times) 37.85 liter stock tank volume to get the total salt dissolved to make a 600x concentration which is 2.16*37.85 =81.756 or 81.8grams of salt for a 600x concentrate if this is correct please guide me further on how much of stock solution to add to make a final solution for a 3785liter tank of 0.8ppm? Adam I highly appreciate your time and your efforts in getting this solved for me as if I understand this I can work on a few more salts, I'm feeling very embarrassed with my breakdown but I rather put it simple for your understanding and more over for my understanding. Alternatively you can send me a reply on sidneyspleno13@gmail.com I thank you very much for your time and do look forward of your e-teaching. Sidney Rodrigues.

    • @blxckyin8633
      @blxckyin8633 4 роки тому

      Sidney Rodrigues ik you tight because they didn’t respond

  • @soulTC
    @soulTC 8 років тому

    In the <F1 Cross> slide (3:35), why is there no recombination? The gametes produced just replicate exactly the parental chromosomes. Why, for example, is there no v+.cv+.ct+ or v.cv.ct+ gamete?

  • @arohe4705
    @arohe4705 8 років тому

    thank u😄😌😍