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You Can Learn Math with Alyssa
United States
Приєднався 16 бер 2021
Math shouldn't be this mysterious and difficult subject. With the right instruction, you can learn math at all levels - I promise!
If you're looking for videos like "How to Learn Every Single Math Concept in Just 10 Minutes!!!!", you won't find that here. This channel is like having your very own personal, experienced math tutor for free :-).
A lot of math instruction focuses on memorizing steps or processes. Personally, I don't believe that's the best way. After all, memorizing steps has a major flaw - it's really REALLY easy to forget a step or two, especially under the pressure of a test or final exam! I believe that by showing you WHY something works, you'll gain a better and more instinctual understanding of HOW to do things.
I've been tutoring people of all ages in basic math, algebra, geometry, trigonometry, SAT prep, calculus, and more for well over a decade, and I want to help you like I've helped many others. So come along with me, and you can learn math, too!
If you're looking for videos like "How to Learn Every Single Math Concept in Just 10 Minutes!!!!", you won't find that here. This channel is like having your very own personal, experienced math tutor for free :-).
A lot of math instruction focuses on memorizing steps or processes. Personally, I don't believe that's the best way. After all, memorizing steps has a major flaw - it's really REALLY easy to forget a step or two, especially under the pressure of a test or final exam! I believe that by showing you WHY something works, you'll gain a better and more instinctual understanding of HOW to do things.
I've been tutoring people of all ages in basic math, algebra, geometry, trigonometry, SAT prep, calculus, and more for well over a decade, and I want to help you like I've helped many others. So come along with me, and you can learn math, too!
Question 15 in SAT Digital Practice Test #5, MATH Section 2 Module 1
This video explains the answer to Question 15 from the SAT Digital Practice Test 5 Section 2 Module 1 Math portion. The question is A right circular cylinder has a base diameter of 22 centimeters and a height of 6 centimeters. What is the volume, in cubic centimeters, of the cylinder?
This question involves volume of a circular cylinder. Calculators ARE allowed on this section. This practice test is provided for free by the College Board. This video will show you how to do this problem and the logic behind it.
Be sure to subscribe to find out when my FREE course on SAT tips and tricks goes live, as well as when my in-depth comprehensive SAT Math and Reading and Writing Course is available.
My Etsy store is: www.etsy.com/shop/YouCanLearnMath
My Spreadshop store is: you-can-learn-math.myspreadshop.com
Useful Videos for Questions in this SAT Section:
Mean, Median, Mode, and Range - How to Find Them All! - ua-cam.com/video/xlApDxiyTG0/v-deo.html
Parallel Lines cut by a Transversal - ALL Theorems! - ua-cam.com/video/2UpQ_1vcopI/v-deo.html
Area of Quadrilaterals: ua-cam.com/video/-NrmolpBJ1Y/v-deo.html
Slope Intercept Form of a Line - ua-cam.com/video/9_THEc4r9pY/v-deo.html
Similar Triangles - AAA, AA, SSS, and SAS Similarity Theorems - ua-cam.com/video/efNsMjrVWgc/v-deo.html
AA Similarity Theorem of Triangles (2-MINUTE MATH) - ua-cam.com/video/Edz8DT8gaHM/v-deo.html
AAA Similarity Theorem of Triangles (2-MINUTE MATH) - ua-cam.com/video/1mNltLOgAFo/v-deo.html
How to Find Axis of Symmetry in a Parabola (2-MINUTE MATH!) - ua-cam.com/video/RTQGaJg_j_w/v-deo.html
How to Find the Vertex Form of a Quadratic Equation / Parabola! - ua-cam.com/video/0XAFcqjWxss/v-deo.html
How to Find the Area of a Triangle! (2-MINUTE MATH!) - ua-cam.com/video/-abY72owtzg/v-deo.html
45 45 90 Triangles! - ua-cam.com/video/Ol2ag7yxSwo/v-deo.html
45-45-90 Right Triangles! (2-MINUTE MATH!) - ua-cam.com/video/gmkfwqQv5Dk/v-deo.html
How to Solve for the Indicated Variable! - ua-cam.com/video/v5uiJpExXaE/v-deo.html
What Are Variables? - ua-cam.com/video/xFS5EuxDgVE/v-deo.html
Evaluating Functions! - ua-cam.com/video/PYUFfBuqz4M/v-deo.html
How to Calculate Percent Change - ua-cam.com/video/Sern57d4Vmk/v-deo.html
Equation of a Line Parallel or Perpendicular to a Given Line Through a Point - ua-cam.com/video/8Hxf2emeNqg/v-deo.html
Simplifying Rational Expressions! - ua-cam.com/video/dGlZ7OLk0tc/v-deo.html
How to Add and Subtract Rational Expressions! - ua-cam.com/video/MTsl8wPx93A/v-deo.html
FOIL Method for Multiplying Binomials (2-MINUTE MATH!) - ua-cam.com/video/DMOdF0-aUW0/v-deo.html
How to Solve Systems of Equations by Elimination - ua-cam.com/video/-v91MsSo0O4/v-deo.html
How to Solve Systems of Equations by Graphing - ua-cam.com/video/-_sO1el7rmk/v-deo.html
How to Solve Systems of Equations by Substitution - ua-cam.com/video/DE_EBF9gQUM/v-deo.html
Simplifying Square Roots! - ua-cam.com/video/QgygmzD63d8/v-deo.html
What Is a Linear Equation? And How Do You Graph a Linear Equation? - ua-cam.com/video/eqBNyvwh-sA/v-deo.html
How to Simplify Fractions! (explanation and examples) - ua-cam.com/video/fktUsXT-bbc/v-deo.html
Parallel, Perpendicular, or Neither? (explanation and examples!) - ua-cam.com/video/FjRjwzyC0_o/v-deo.html
Equation of a Circle! AND How to Convert from General to Standard Form! - ua-cam.com/video/iln6TW3zyWE/v-deo.html
How to Find the Zeros of a Quadratic Equation - ua-cam.com/video/LLn7epH9B7g/v-deo.html
Discriminant of the Quadratic Equation! - ua-cam.com/video/TzRv9OX9yOY/v-deo.html
Thank you so much for watching! If you have any questions on this video or if there are other specific topics you would like to see me cover, please leave a comment below.
If this was helpful in any way, please like, share, comment, or subscribe - it's the only way I can keep making more of these :-)
I have over 15 years' experience helping children, teens, and adults improve at math in topics ranging from addition to algebra to calculus and beyond. My goal is to make math easy to understand for anyone who wants to learn :-)
If you'd like more Algebra videos, go here: ua-cam.com/users/playlist?list...
For more SAT related videos, go here: ua-cam.com/play/PLwyZvFdGYYk5eUMxkMnt9dmXaazkPoU72.html
#geometry #volumeofprism #volumeofsolid #volumeofcylinder #digitalsat #satpractice #satdigitalpracticetest4 #satpracticetest #satmaths #satmath #satmathprep #satmathtestprep #satmathhelp #sat #actmathhelp #algebra #math #mathematics #mathematicshelp #mathhelp #mathtutor #onlinemathhelp #tutor
This question involves volume of a circular cylinder. Calculators ARE allowed on this section. This practice test is provided for free by the College Board. This video will show you how to do this problem and the logic behind it.
Be sure to subscribe to find out when my FREE course on SAT tips and tricks goes live, as well as when my in-depth comprehensive SAT Math and Reading and Writing Course is available.
My Etsy store is: www.etsy.com/shop/YouCanLearnMath
My Spreadshop store is: you-can-learn-math.myspreadshop.com
Useful Videos for Questions in this SAT Section:
Mean, Median, Mode, and Range - How to Find Them All! - ua-cam.com/video/xlApDxiyTG0/v-deo.html
Parallel Lines cut by a Transversal - ALL Theorems! - ua-cam.com/video/2UpQ_1vcopI/v-deo.html
Area of Quadrilaterals: ua-cam.com/video/-NrmolpBJ1Y/v-deo.html
Slope Intercept Form of a Line - ua-cam.com/video/9_THEc4r9pY/v-deo.html
Similar Triangles - AAA, AA, SSS, and SAS Similarity Theorems - ua-cam.com/video/efNsMjrVWgc/v-deo.html
AA Similarity Theorem of Triangles (2-MINUTE MATH) - ua-cam.com/video/Edz8DT8gaHM/v-deo.html
AAA Similarity Theorem of Triangles (2-MINUTE MATH) - ua-cam.com/video/1mNltLOgAFo/v-deo.html
How to Find Axis of Symmetry in a Parabola (2-MINUTE MATH!) - ua-cam.com/video/RTQGaJg_j_w/v-deo.html
How to Find the Vertex Form of a Quadratic Equation / Parabola! - ua-cam.com/video/0XAFcqjWxss/v-deo.html
How to Find the Area of a Triangle! (2-MINUTE MATH!) - ua-cam.com/video/-abY72owtzg/v-deo.html
45 45 90 Triangles! - ua-cam.com/video/Ol2ag7yxSwo/v-deo.html
45-45-90 Right Triangles! (2-MINUTE MATH!) - ua-cam.com/video/gmkfwqQv5Dk/v-deo.html
How to Solve for the Indicated Variable! - ua-cam.com/video/v5uiJpExXaE/v-deo.html
What Are Variables? - ua-cam.com/video/xFS5EuxDgVE/v-deo.html
Evaluating Functions! - ua-cam.com/video/PYUFfBuqz4M/v-deo.html
How to Calculate Percent Change - ua-cam.com/video/Sern57d4Vmk/v-deo.html
Equation of a Line Parallel or Perpendicular to a Given Line Through a Point - ua-cam.com/video/8Hxf2emeNqg/v-deo.html
Simplifying Rational Expressions! - ua-cam.com/video/dGlZ7OLk0tc/v-deo.html
How to Add and Subtract Rational Expressions! - ua-cam.com/video/MTsl8wPx93A/v-deo.html
FOIL Method for Multiplying Binomials (2-MINUTE MATH!) - ua-cam.com/video/DMOdF0-aUW0/v-deo.html
How to Solve Systems of Equations by Elimination - ua-cam.com/video/-v91MsSo0O4/v-deo.html
How to Solve Systems of Equations by Graphing - ua-cam.com/video/-_sO1el7rmk/v-deo.html
How to Solve Systems of Equations by Substitution - ua-cam.com/video/DE_EBF9gQUM/v-deo.html
Simplifying Square Roots! - ua-cam.com/video/QgygmzD63d8/v-deo.html
What Is a Linear Equation? And How Do You Graph a Linear Equation? - ua-cam.com/video/eqBNyvwh-sA/v-deo.html
How to Simplify Fractions! (explanation and examples) - ua-cam.com/video/fktUsXT-bbc/v-deo.html
Parallel, Perpendicular, or Neither? (explanation and examples!) - ua-cam.com/video/FjRjwzyC0_o/v-deo.html
Equation of a Circle! AND How to Convert from General to Standard Form! - ua-cam.com/video/iln6TW3zyWE/v-deo.html
How to Find the Zeros of a Quadratic Equation - ua-cam.com/video/LLn7epH9B7g/v-deo.html
Discriminant of the Quadratic Equation! - ua-cam.com/video/TzRv9OX9yOY/v-deo.html
Thank you so much for watching! If you have any questions on this video or if there are other specific topics you would like to see me cover, please leave a comment below.
If this was helpful in any way, please like, share, comment, or subscribe - it's the only way I can keep making more of these :-)
I have over 15 years' experience helping children, teens, and adults improve at math in topics ranging from addition to algebra to calculus and beyond. My goal is to make math easy to understand for anyone who wants to learn :-)
If you'd like more Algebra videos, go here: ua-cam.com/users/playlist?list...
For more SAT related videos, go here: ua-cam.com/play/PLwyZvFdGYYk5eUMxkMnt9dmXaazkPoU72.html
#geometry #volumeofprism #volumeofsolid #volumeofcylinder #digitalsat #satpractice #satdigitalpracticetest4 #satpracticetest #satmaths #satmath #satmathprep #satmathtestprep #satmathhelp #sat #actmathhelp #algebra #math #mathematics #mathematicshelp #mathhelp #mathtutor #onlinemathhelp #tutor
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This video explains the answer to Question 10 from the SAT Digital Practice Test 5 Section 2 Module 1 Math portion. The question is Scott selected 20 employees at random from all 400 employees at a company. He found that 16 of the employees in this sample are enrolled in exactly three professional development courses this year. Based on Scott’s findings, which of the following is the best estim...
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Question 1 in SAT Digital Practice Test #5, MATH Section 2 Module 1
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Question 27 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Question 26 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 26 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 25 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 24 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 23 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 22 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Question 21 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 21 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Question 20 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 20 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Question 19 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 19 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Question 18 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 18 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Question 17 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 17 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Question 16 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 16 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Question 15 in SAT Digital Practice Test #4, MATH Section 2 Module 2
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Question 15 in SAT Digital Practice Test #4, MATH Section 2 Module 2
Thank you mam ❤
You’re very welcome 😊
wow this was so much fun <3
But they aren’t asking for proportion they are asking for length and ABC is larger than BDC😔. It’s confusing
There are two reasons why proportion comes up in this problem. When they ask for “what is BC/BD?” they’re asking for a proportion. And the way you find the lengths of those two sides is by comparing the similar (NOT congruent) triangles in the problem. Similar triangles have sides that are *proportional*, not congruent. So if I had a triangle with sides of 3, 4, and 5, it would be similar to a larger triangle with sides of 6, 8, and 10. The proportions should all be the same and they are 3/6 = 4/8 = 5/10, which all can be simplified to 1/2. This can definitely be confusing, but with practice I’m sure you’ll get a good understanding of how to find similar triangles when you draw an altitude in a right triangle (and the SAT loooooves putting problems in there about these triangles, so it will get you some points 😊)
thank you for making this so clear 😭😭😭😭
I’m so glad it was helpful! 😊
Thanks ma'am u always explain better than my lesson teacher 🤗
Aw that’s so nice of you to say - I’m truly flattered 😊
Thank you sooooooooooooo much 😭😭😭💕💕💕
You’re very welcome - I’m so glad I was able to help! 😊
Everything will be alright wish u a healthy recovery.
Thank you so much! 😊
Wishing you s speedy recovery. x
Thank you!! 😊 🙏
I was struggling with my homework😂 Thanks
You’re welcome - I’m so glad it helped! 😊
1:41 ❤❤❤❤❤❤❤
Here's the link: gofund.me/d03276b5 Thank you all so much for your kindness, encouragement, and support - it means the world to me! ☺
Alyssa, I know you can fight through this. While you helped me with my sats, ic outdent thank you enough. I will pray for you and hope you stay strong!
Thank you so much 🥹
Can you prove the chord-tangent theorem for me?
I’m afraid that’s a bit too long/graphic-oriented for me to answer properly in the comments 😓, but if you google this you’ll see some great sites with the details and graphics necessary to explain it, like at geometry help.net for example. Hope that helps! 😊
@@YouCanLearnMathwithAlyssa thank you
I did not learn anything
Sorry ma'am why did y multiply below by -1
When you’re solving a system of equations using elimination, you want one of the variables to cancel out so you only have one variable left. When you have only one variable left, you can solve for that variable. It’s like if I had x + y = 10 and -x + y = -2. If I add those equations together, the x and -x will cancel out. x + y + -x + y = 10 + -2 2y = 8 y = 4 In the problem above, multiplying the bottom equation all by -1 changes the y to a -y. Then, when we add the two equations together, the y and -y will cancel out leaving just x’s. And then we can solve for x.
@@YouCanLearnMathwithAlyssa thanks ma'am i really appreciate
Really important question how would you do the negatiave but with completing the square. The question is 11 plus 8x minus x^2
When you’re doing completing the square, it is incredibly important that the first term be a plain, positive x^2. Always always always divide everything by whatever coefficient is in front of the x^2 first to get rid of it before you start completing the square. Whether that’s a -1, a fraction, whole number, whatever, divide every term in the equation by that coefficient to get rid of it. So for -x^2 +8x+11=0, divide it all by -1 to change it to x^2 -8x -11=0 then go through the usual steps to complete the square
@@YouCanLearnMathwithAlyssathank you so much!! I was so confused:) really help full
Glad to help! 😊. I just remembered I have a video on completing the square that you might find helpful as well. It’s at ua-cam.com/video/pQinf1fPta0/v-deo.html
Are there any other good tests I can take to study for the digital SATS? Because there are only about ~5 in the official Bluebook app. (and I don't want to study from non-digital-sats because they won't be accurate) Thank you!
I think the Princeton Review will let you access some of their digital SAT’s if you buy one of their prep books (The hard part right now is that the fully digital SAT is so new that it looks like a lot of test prep companies haven’t had a chance to make comparable practice tests yet) I’ll also add that non-digital-SATs are a great way to zero in on any concepts you need to practice, but I totally agree that practicing with digital SATs is absolutely essential 😊
@@YouCanLearnMathwithAlyssa Thanks!!
Heya, thank you so much! Quick question- Are there any other good tests I can take to study for the digital SATS? Because there are only about ~5 in the official Bluebook app. (and I don't want to study from non-digital-sats because they won't be accurate)
I think the Princeton Review will let you access some of their digital SAT’s if you buy one of their prep books (The hard part right now is that the fully digital SAT is so new that it looks like a lot of test prep companies haven’t had a chance to make comparable practice tests yet) I’ll also add that non-digital-SATs are a great way to zero in on any concepts you need to practice, but I totally agree that practicing with digital SATs is absolutely essential 😊
amazing video, keep it up 🤩
thank you mam,i have watched many videos but i can't understand but your's was use and i understand
That makes me so happy to hear it helped! 😊
❤❤❤❤❤❤❤ AMAZING
Thank you so much - I’m so glad it helped! 😊
Thank you so much! new nothing for ap summer work now its crunch time. 😆
You’re very welcome - always glad to help! 😊
omg thank you so much i love u
Aw you’re very welcome 😊
80+ x+ x+ 2x= 360 4x=280 x= 70(AC) 2x= 140(CD) 80, 70,70, 140 ( all 4 arcs) Inscribed angles ABC and BCD= 1/2(70arcs)= 35 degrees. My answer, with omitted degree and arc symbols, 2 years later. Let’s hope I’m right. You should continue making videos; I’ve watched many different UA-cam teachers over the years and you’re far better than most. Take care!
Aww thank you so much for the kind words! 😊
What if it asks for the minimum?
If a problem says “what is the minimum amount…” of something, you want to be using greater than or greater than or equal to in your equation. This can be confusing to students, since “greater than” and “minimum” sound like opposites. But what we’re saying is “if this is the absolute minimum value, then all the possible answers must be *greater than* that”
I found multiple explanations for this problem, but none made sense until this one. Thank you :D
Aw thank you so much! Knowing I was able to help honestly brightens my day 😊
can I ask a question? So, I'm doing functions, and I'm now at "2x - 4y = 8." I'm trying to isolate y, so I know I need to subtract 2x. Later on in the problem, I have -4y = -2x + 8. I know I now have to divide all terms by -4. How come I have to divide by -4 and not -4y? How come I had to subtract -2x from the initial "2x - 4y = 8" instead of subtracting just 2?
We have to subtract 2x and not just 2 because when we’re adding or subtracting we can’t split terms up. That’s because we have 2 x’s, not a 2 and an x. So if we’re trying to isolate y, we need to move both of those x’s to the other side. So we subtract both x’s - or in other words subtract 2x. Now multiplication and division are different. When I have 4y, I am saying I have 4 y’s - and it’s another way of saying “4 times y”. It’s just like how “3 times 2” is the same as 3 2’s or 2 3’s. Now “3 times 2” is 6. If I divide 6 by 2 what do I get? 3. So dividing “3 times 2” by 2 gets me back to 3. And that’s why dividing “4 times y” or “4y” by 4 will leave you with just y. And that’s our goal in these type of problems. Hope this helps! 😊
would this have 3 roots if you were to solve for them further? so probably x=5,x=7 and i don’t know about the -1
Here’s a quick rule of thumb for the number of roots - the maximum number of roots a “standard” function can have is the highest exponent you see. So if x^2 is the highest exponent, the function could have up to 2 roots. If it’s x^3, it could have up to 3 roots, etc. It may have less, but it won’t have more. The -1 here doesn’t affect the number of roots - it still only has 2 roots 😊
thank you for your videos ! you are a life saver.
Aw I’m so glad they helped! 😊
People nowadays do not do subtraction. They would graph the given function. Then, they would graph each function in the answer choices to see which one matches the given function. It works! So this question does not really mean anything anymore. It does not test how you deal with exponents or like terms.
They can make this question more interesting by asking: What is the total number of people that are not managers? People nowadays solve this problem using Desmos. They have no idea how to do algebraic manipulations. They would graph the function and look for the value of the function at x = 7. If they want to know the number of people who are not managers, they would look for the y intercept. SAT is now a Desmos proficiency test.
You got lucky by identifying a = 6 from the answer choices. The giveaway here is the graph itself. It is showing a vertical asymptote at x = -4. Thus, f(x) has the form a / (x+4). For f(x+4), the only possible answer is Choice C.
There is another way. Just plug in the answer choices. C and D are too far off. You only need to try A and B. This kind of problem won’t be around anymore because of Desmos.
This should be your favorite problem. It has a known solution floating in the clouds. We can quickly derive a+b+c as f(1) = a + b + c We know that the vertex is located at f(9). For the parabola to open upward, f(1) > f(9). In other words, a+b+c > -14 So, Choice D.
You are the first one I saw that knows how to take the mean of the difference. Everybody is taking the mean of A minus the mean of B. Good job! Here is another explanation: [3(20-19) + 4(30-29) + 7(40-39) + 9(50-49)] / 23 = 23/23 = 1
Nice method
thank you
You’re welcome- and thanks for visiting my channel
I’m an upcoming senior who absolutely flunked the math portion of my SAT last year, and I’m looking to improve my score. Going through the practice tests for me has been incredibly difficult as I tend to break down when I don’t understand something. Your channel has helped me in ways I cannot fully express. Not only do I now understand the math, but my anxiety is significantly lessened because of how reassuring you are. The way you point out when questions are as simple as they appear, but also sympathize and express how you can see how one may be tripped up by it is so unique. I haven’t seen such an attitude from other channels I’ve tried. Thank you so much, I’m a lot more confident now and I’m looking forward to retaking the SAT!
Oh my goodness, I think this is the nicest comment I’ve ever received 🥺. Thank you so much for all the kind words- and I’m so happy the videos helped you! 😊
you are so funny!
Aw thank you! 😊
Too much nonsense talk get to the point
My weak concepts grewed and became stronger thank mam❤
ALYSSA I LOVE YOU you saved my friend and me However, I don't understand why you used 19 instead of 20. and 29 instead of 30
This has to do with what we see written in the word problem, not what we see on the chart. On the chart it absolutely looks like that first bar in Data Set B goes from 10-20. However, the text tells us that it represents numbers greater than or equal to 10, but LESS than 20. That’s why when we’re looking for the biggest possible number represented by that first bar in Data Set B, 19 is as high as we can go. And that’s going to apply all the way down the line.
this is great! thank you! natural teacher
Ah you’re very kind to say that - I’m so glad it helped! 😊
Thank you, thank you for this! I was mystified by the answer key explanation (compounded by tiny type all condensed into one massive paragraph) not understanding the difference in numbering (3 x 20 vs. 3 x 19, etc.) Okay, I think I get it now based on the question "what is the SMALLEST possible difference between the mean of data set A and the mean of data set B. Thus choosing the smallest possible terms in the bars of A and the largest in B (so the 3 integers in the first bar of A = 20 and the 3 integers in the bar of B = 19. The smallest difference: 20 - 19 and too 30 - 29, 40 - 39, etc.). Can't thank you enough for clarifying this. I happily learned something today! PS: I assume if the question asked for the LARGEST difference, for the first bars of A and B, respectively we'd have (3 x 29) (from A) - (3 x 10) from B as the first group and going from there. (4 x 39) - (4 x 20), (5 x 49) - (5 x 30), etc.
Yes that’s it exactly 😊. For “biggest difference” we would be lowering Data Set B’s mean and raising Data Set A’s mean as much as possible to increase that gap between them. And I totally understand what you mean about the answer key explanations. After I’ve taken the test myself and prepared my explanations I’ll go check out theirs - I can’t tell you how many times I’ve been like “what on earth…?” 😂 Anyways, I’m so glad this video helped - happy studying! 😊
@@YouCanLearnMathwithAlyssa Thank you so much! This is really wonderful!
omgg thank you so much. The second option is so much easier and understandable. I watched so many videos about this same exact problem but your video helped me alot. THANK YOU.
Aw I’m so happy to hear that it helped! 😊
At 9:59, I say that you get -0.5 when it should be -0.25. Sorry about that - and a big thank you to @edw2 for spotting it and letting me know! 🙂
Great video thank you
I got -0.25 versus-0.5 ?
Just double checked - you’re absolutely right! That was a mistake on my part - sorry about that. Thank you so much for pointing it out - I’ll add a pinned comment to let others know 😊
Can you pls proof RHS theorem as well . your explanation is really good
I’ll add it to the queue! 😊
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I don't understand how taking the smallest mean of A and the largest mean of B results in the smallest possible difference. Why does that result in them being close? Wouldn't you have to use the smallest mean from both and subtract?
Let’s say I told you “Pick one number that’s between 1 and 10. Now pick another number between 11 and 20. And make sure there’s the smallest possible difference between them.” If you just picked the smallest number between 1 and 10 and then the smallest number between 11 and 20 you’d get 1 and 11. The difference between them would be 10. However, if you picked the biggest number between 1 and 10 but the smallest number between 11 and 20, you’d get 10 and 11. The difference between them would be only 1, which is a way smaller difference than the 10 before. That’s what we’re doing here. We’re making B have the largest mean possible and A have the smallest mean possible so those two means are super close together and have the smallest difference possible.
@@YouCanLearnMathwithAlyssa Thank you for the detailed explanation on the logic! This makes so much more sense.