- 2 166
- 463 478
GATE Insights Version: CSE
India
Приєднався 28 лип 2021
Every day, we students face a lot of stress factors about exams, interviews, coaching tests. There is a lot of information available on the world wide web and books. But prioritizing it for the exams is difficult for the freshers. I make their work easier through my website. I will upload all the lecture notes, tutorials, classes, and post some quizzes mainly concentrating for gate
GATE CSE 2015 SET 1
Planning to take coaching on Unacademy
bit.ly/gate_unacademy
or
unacademy.com/
here is a code for 10% off PLUS1BPK1
Telegram Notification Group link:-
t.me/joinchat/X5egW_cvdt9kMGY1
Telegram discussion Group link:-
t.me/joinchat/VCyGUmVq8RNkMzhl
Downloads resources from here
education4fun.com/gate-cse/
MCQ (Single Correct Answer)
GATE CSE 2015 SET 1
A variable x is said to be live at a statement Si in a program if the following three conditions hold simultaneously:
There exists a statement Sj that uses x
2. There is a path from Si to Sj in the flow graph corresponding to the program
3. The path has no intervening assignment to x including at Si and Sj
The variables which are live both at the statement in basic block 2 and at the statement in basic block 3 of the above control flow graph are(A) p, s, u(B) r, s, u(C) r, u(D) q, v
bit.ly/gate_unacademy
or
unacademy.com/
here is a code for 10% off PLUS1BPK1
Telegram Notification Group link:-
t.me/joinchat/X5egW_cvdt9kMGY1
Telegram discussion Group link:-
t.me/joinchat/VCyGUmVq8RNkMzhl
Downloads resources from here
education4fun.com/gate-cse/
MCQ (Single Correct Answer)
GATE CSE 2015 SET 1
A variable x is said to be live at a statement Si in a program if the following three conditions hold simultaneously:
There exists a statement Sj that uses x
2. There is a path from Si to Sj in the flow graph corresponding to the program
3. The path has no intervening assignment to x including at Si and Sj
The variables which are live both at the statement in basic block 2 and at the statement in basic block 3 of the above control flow graph are(A) p, s, u(B) r, s, u(C) r, u(D) q, v
Переглядів: 763
Відео
GATE CSE 2015 SET 1
Переглядів 2712 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ Numerical GATE CSE 2015 Set 1 The least number of temporary variables required to create a th...
GATE CSE 2006
Переглядів 1832 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2006 Consider the following C code segment Which one of ...
GATE CSE 2005
Переглядів 2172 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2005 Consider line number 3 of the following C - program...
GATE CSE 2003
Переглядів 1752 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2003 Which of the following is NOT an advantage of using...
GATE CSE 2020
Переглядів 1132 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2020 Consider the following statements. I. Symbol table ...
GATE CSE 2015 SET 2
Переглядів 1082 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2015 Set 2 Which one of the following is NOT performed d...
GATE CSE 2014 SET 1
Переглядів 1142 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2014 Set 1 Which one of the following is FALSE?(A) A bas...
GATE CSE 2010
Переглядів 792 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2010 Which languages necessarily need heap allocation in...
GATE CSE 2008
Переглядів 1382 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2008 Some code optimizations are carried out on the inte...
GATE CSE 2004
Переглядів 1232 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2004 Consider a program P that consists of two source mo...
GATE CSE 2004
Переглядів 3662 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2004 Consider the grammar rule E → E1 - E2 for arithmet...
GATE CSE 2001
Переглядів 1062 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 2001 The process of assigning load addresses to the vari...
GATE CSE 1995
Переглядів 1172 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 1995 A linker is given object modules for a set of progr...
GATE CSE 1990
Переглядів 812 роки тому
Planning to take coaching on Unacademy bit.ly/gate_unacademy or unacademy.com/ here is a code for 10% off PLUS1BPK1 Telegram Notification Group link:- t.me/joinchat/X5egW_cvdt9kMGY1 Telegram discussion Group link:- t.me/joinchat/VCyGUmVq8RNkMzhl Downloads resources from here education4fun.com/gate-cse/ MCQ (Single Correct Answer) GATE CSE 1990 Match the followings:
❤
Thank you bhai great explanation, but please use hindi language as well during the time of question explanation and answer explanatiom. Because people from belongs to north india he/she more comfortable with hindi language so please use hindi language as well. Thank you for making such grear video.
Wrong answer dear 64, correct answer is 35
Nonsence man
Muh se gutka nikal ke bola kr bhai tu
Good one
Tatti explanation......
2:54 projection eliminates duplicacy so it will be 1 only once
Thank you
Last option is wrong, if we consider tree where d is added after c, so when we visited vertex a-c-d and want to visit b from d Parents of d and b are different But They both r in leaf node So option c true
Thank You so much sir
Good job❤
Your explanations are very clear. Thank you!
Correct ans. Is D
Very nicely explained !!
totally bullshit.correct ans is 7!/4!*3!=35
Super 👍
How Calculate extarnal fragmentation
Woow thank you for explaining this question, so smoothly ❤
You're wrong..... right answer is B
Wrong explanation
poor explanation
Thanks bro, I was solving PYQ and I marked rear node but in answer key of the book it was C. I started looking for answers. I found yours thanks!
How 7 can lost? Why 7 can lost
nice explanation
Bro can you let me know minimum number of tables for c,d
Totally wrong solution? How can you run P1 and P2 more than 1 times without while loop
wow descent explanation
kuch bhi
Tum Gadhe ho Kya ,km se km gyaan dene se Phle seekh to lo. Kya time pass karaate ho ok-ok Bol ke.
Good explanation sir ji❤
but how 😂
Its wrong....plz dont provide wrong solutions
are u sure this is right ?
Nice
Sir they asking Many to one supporting relation for the weak entity here you given weak entity as answer but still suporting then dimond with double border
N=1 was given not S
❤
Kindly explain clearly, nowadays msq are asked then how are you suppose to eliminate
Very helpful 😃
Thanks ❤
The option is correct, but the solution is wrong. If you are telling that option 'A' is wrong, then two processes can never enter critical section at the same time. For Option A) Theoretically this may be true, but practically it can't be true. [Explanation] Let's suppose the size of unsigned integer on your machine is 4 Byte(32 bit) then the max integer value it can store is ((2^32) - 1). If first process checks while condition it will store the value 0+1 = 1 to L because of "Fetch_And_Add" then enters Critical Section without executing "while" body. Now if every next process, only enters to "while" body by executing condition and then preempts just before executing its body, then the L will get values like 1, 2, 3, 4, 5, 6, and when it reaches (2^32) - 1 then next process (2^32th process) will try to store value 2^32 which is 1 greater than your machine can store in L. So, L can overflow and because of this L will get the value 0 by 2^32th process, that means it can also enter critical section. Now 1st process and 2^32th process is inside critical section at the same time (2 process in cs). As we know that having 2^32 processes is not practical. So, this option can't be true. For Option B) True [Explanation] Let's suppose if: 1) Process P1 enters C.S and preempts. Now the value of L is 1. 2) Process P2 enters while loop but preempts before executing its body. Now the value of L is 2 3) Process P1 leaves C.S. Now the value of L is 0. -> Preempts and Scheduled P2 4) Process P2 executes its next line that is L = 1 and then preempts, Now the value of L is 1 => At this point no process is inside the Critical Section and the value of L is 1. So, no process can enter Critical Section now. Every process will get stuck in while loop. It means deadlock. As we can see critical section is free(lock is available) but no one can enter critical section because L is non-zero(Showing Lock is not available). Option C and D are clearly false.
1 to the power any number 1 only, so option B is not correct, option A is correct.
Nice explanation,, thanks 🙏
If option has like course ids in which all female students are not enrolled?? Will it be correct.
Consider the following sequence of instructions, which is to be a 5 stage pipeline: IF, ID, OF, EX and WB. Each stage takes one cycle instruction. Total cycles require to execute this sequence ? ADD R2, R1, R0 MUL R4, R3, R2 SUB R6, R5, R4 ADD R6, R7, R8 MUL R7, R1, R2 SUB R1, R3, R4 Sir can you make a table for this one to get clear idea of total cycle needed ?
Kindly explain clearly
thanks for this question
A depth-first search is performed on a directed acyclic graph. Let d[u] denote the time at which vertex u is visited for the first time and f[u] the time at which the dfs call to the vertex u terminates. Which of the following statements is always true for all edges (u, v) in the graph ? (A) d[u] < d[v] (B) d[u] < f[v] (C) flu] < f[v] (D) f[u] > f[v] can you solve this question please ? if you solve it please comment it here i will get notified
take 104