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TUTOR JERRY
Nigeria
Приєднався 2 чер 2020
Master Maths, Physics & Engineering with engaging lessons and clear explanations.prepare for Exams,ace your courses, and unlock your potential!
Gas power cycle thermodynamics || Carnot cycle Numerical Four ...
Question 4: An investor claims that a new heat cycle will develop 0.4KW for a heat addition of 32.5KJ/min.
The temperature of heat source is 1990K and that of sink is 850K. Is his claim possible?
In this video, we evaluate the claim of an investor who asserts that a new heat cycle can generate 0.4 kW for a heat addition of 32.5 kJ/min. The heat source is at 1990 K, and the heat sink is at 850 K. We will determine whether this claim is possible by using thermodynamic principles and efficiency calculations.
Given data:
Power output: 0.4 kW
Heat addition: 32.5 kJ/min
Source temperature: 1990 K
Sink temperature: 850 K
We will apply the Carnot efficiency formula to check if the proposed power output is realistic based on the heat cycle conditions.
In this video, we assess the feasibility of an investor's claim regarding a heat cycle that supposedly generates 0.4 kW of power with a heat addition of 32.5 kJ/min. Using the Carnot efficiency equation, we explore whether the given source and sink temperatures of 1990 K and 850 K, respectively, support the claim. We walk through the efficiency calculations step by step, comparing the theoretical maximum efficiency with the proposed output. Join us to find out if the claim holds true or if it's beyond thermodynamic limitations.
#HeatCycle #Thermodynamics #CarnotCycle #PowerOutput #EnergyEfficiency #EngineeringAnalysis
The temperature of heat source is 1990K and that of sink is 850K. Is his claim possible?
In this video, we evaluate the claim of an investor who asserts that a new heat cycle can generate 0.4 kW for a heat addition of 32.5 kJ/min. The heat source is at 1990 K, and the heat sink is at 850 K. We will determine whether this claim is possible by using thermodynamic principles and efficiency calculations.
Given data:
Power output: 0.4 kW
Heat addition: 32.5 kJ/min
Source temperature: 1990 K
Sink temperature: 850 K
We will apply the Carnot efficiency formula to check if the proposed power output is realistic based on the heat cycle conditions.
In this video, we assess the feasibility of an investor's claim regarding a heat cycle that supposedly generates 0.4 kW of power with a heat addition of 32.5 kJ/min. Using the Carnot efficiency equation, we explore whether the given source and sink temperatures of 1990 K and 850 K, respectively, support the claim. We walk through the efficiency calculations step by step, comparing the theoretical maximum efficiency with the proposed output. Join us to find out if the claim holds true or if it's beyond thermodynamic limitations.
#HeatCycle #Thermodynamics #CarnotCycle #PowerOutput #EnergyEfficiency #EngineeringAnalysis
Переглядів: 23
Відео
Gas power cycles thermodynamics || Carnot cycle Numerical Two...
Переглядів 1082 місяці тому
Question 2: 0.5kg of air ( ideal gas ) executes a Carnot power cycle having a thermal efficiency of 50 percent. The heat transfer to the air during the isothermal expansion is 40KJ. At the beginning of the isothermal expansion the pressure is 7bar and the volume is 0.12m³. Determine: 1.Maximum and minimum temperature of the cycle in Kelvin 2.The volume at the end of isothermal expansion in m³ 3...
Gas power cycles thermodynamics || Carnot cycle Numerical Three ...
Переглядів 352 місяці тому
Question 3: A reversible engine convert one-sixth of the heat input into work.when the temperature of the sink is reduced by 70⁰C, it's efficiency is doubled. Find the temperature of the source and the sink. In this video, we solve a thermodynamics problem involving a reversible engine that converts one-sixth of the heat input into work. When the temperature of the sink is reduced by 70°C, the ...
Gas power cycles thermodynamics || Carnot cycle Numerical one...
Переглядів 1542 місяці тому
Question 1: A Carnot engine working between 400⁰C and 40⁰C produces 130KJ of work. Determine: 1.The engine thermal efficiency 2.The heat added 3. The entropy changes during heat rejection process. In this video, I solve a Carnot engine thermodynamics problem where the engine operates between temperatures of 400°C and 40°C, producing 130 kJ of work. Using fundamental thermodynamic principles, I ...
Efficiency of Carnot cycle using Pv diagram || Gas power cycles thermodynamics...
Переглядів 342 місяці тому
Unlock the secrets of thermodynamics with this comprehensive breakdown of the Carnot Cycle and its efficiency using Pv diagrams. In this video, we dive deep into the foundations of gas power cycles, exploring the Carnot engine, its performance, and limitations. Learn how to calculate Carnot efficiency and visualize the Pv diagram to better understand the cycle's critical processes. Whether you'...
Efficiency of Carnot cycle using Ts diagram || Gas power cycles thermodynamics...
Переглядів 492 місяці тому
Efficiency of Carnot Cycle Explained with T-s Diagram thermodynamics Unlock the secrets of the Carnot Cycle efficiency using the T-s diagram in this comprehensive thermodynamics tutorial! In this video, we dive deep into gas power cycles, focusing on the Carnot cycle-the most efficient thermodynamic cycle. Learn how to analyze the T-s (Temperature-Entropy) diagram, understand the concept of Car...
Gas Power Cycles thermodynamics || Carnot Cycle Fundamentals || IC Engine
Переглядів 902 місяці тому
In this detailed video, we explore the fundamentals of gas power cycles with a special focus on the Carnot cycle -a crucial concept in thermodynamics and internal combustion (IC) engines. Whether you are an engineering student or a professional, this tutorial will provide you with valuable insights into how gas power cycles work and why the Carnot cycle is key in understanding engine efficiency...
Strengths of materials|| simple stresses and strains|| Numerical fifteen...
Переглядів 1182 місяці тому
Question 15 : A steel wire, 1 mm in diameter, is stretched horizontally between two fixed points 2 m apart. A vertical load applied at the mid-span causes a vertical displacement of 45 mm at the point of application of the load. What will be the stress induced in the wire and the load applied? Neglect the weight of the wire and take E for the material as 200GN/m² Join our Whatsapp group via the...
Strength of materials|| simple stresses and strains|| Number fourteen...
Переглядів 1372 місяці тому
Question 14 : Two parallel wire 6m long 10mm diameter are hung vertically 70mm apart and support a horizontally bar at their lower ends. When a load of 9kN is attached to one of the wires, it is observed that the bar is 2.4⁰ to the horizontal. Find E for the wire. Join our Whatsapp group via the link chat.whatsapp.com/BhbcY5iCGFXL9zXw1PTXwd In this video, we explore a practical problem involvin...
Strength of materials|| simple stresses and strains||Numerical thirteen...
Переглядів 682 місяці тому
Question: A 700 mm length of aluminium alloy bar is suspended from the ceiling to provide a clearance of 0.3 mm between it and a 250 mm length of steel bar, as shown in the figure. Given: Aal = 1250mm² , Eal= 70GN/m² As = 2500mm², Es = 210GN/m² Determine the stress in the aluminium and steel bars due to a 300kN load applied. In this video, we tackle a problem involving two different materials-a...
Strength of materials|| simple stresses and strains|| Numerical twelve...
Переглядів 1442 місяці тому
Question: For the bar shown in the figure, calculate the reaction produced by the lower support in the bar. Take E=200GN/m². Also, find the stresses in the bar. Join our Whatsapp group via the link chat.whatsapp.com/BhbcY5iCGFXL9zXw1PTXwd In this video, we explore a fundamental problem in structural mechanics: calculating the reaction produced by the lower support in a bar. We'll also determine...
Strength of materials || simple stresses and strains|| Numerical Eleven...
Переглядів 1292 місяці тому
Question 11: A straight uniform bar AD is clamped at both ends and loaded as shown. Initially, the bar is stress-free. Determine the stresses in all three parts (AB, BC, CD) of the bar if the cross-sectional area of the bar is 1000 mm². Join our Whatsapp group via the link chat.whatsapp.com/BhbcY5iCGFXL9zXw1PTXwd In this video, we dive deep into an essential problem in engineering mechanics: de...
Strength of materials || simple stresses and strains || Numerical ten...
Переглядів 1822 місяці тому
Question ten : The figure below shows a steel bar with a cross-sectional area of 250 mm², held firmly by end supports and loaded by an axial force of 25 kN. Determine: i. The reactions at supports L and M. ii. The extension of the left portion. Given that the modulus of elasticity (E) is 200 × 10⁹ N/m². Join our Whatsapp group via the link chat.whatsapp.com/BhbcY5iCGFXL9zXw1PTXwd In this proble...
Strength of materials || simple stresses and strains || numerical nine...
Переглядів 2512 місяці тому
Question Nine: A member LMNP is subjected to a point load as shown below. Calculate i. The force P necessary for equilibrium. ii. The total elongation of the bar. Given that the modulus of elasticity (E) is 210 GN/m². Join our Whatsapp group via the link chat.whatsapp.com/BhbcY5iCGFXL9zXw1PTXwd In this problem, we examine the equilibrium of a bar subjected to multiple point loads. The first ste...
Strength of materials || simple stresses and strains || numerical eight...
Переглядів 1332 місяці тому
Question Eight: A steel tie rod 50 mm in diameter and 2.5 m long is subjected to a pull of 100 kN. To what length should the rod be bored centrally so that the total extension will increase by 15% under the same pull, the bore being 25 mm in diameter? Take E = 200 GN/m². Join our Whatsapp group via the link chat.whatsapp.com/BhbcY5iCGFXL9zXw1PTXwd This problem explores the concept of axial load...
Strength of materials || simple stresses and strains || numerical seven...
Переглядів 752 місяці тому
Strength of materials || simple stresses and strains || numerical seven...
Strength of materials || Simple stresses and strains || Numerical six...
Переглядів 693 місяці тому
Strength of materials || Simple stresses and strains || Numerical six...
Strength of materials ||Simple stresses and strains|| Numerical five...
Переглядів 3953 місяці тому
Strength of materials ||Simple stresses and strains|| Numerical five...
Strength of materials||Simple stresses and strains|| Numerical four...
Переглядів 1193 місяці тому
Strength of materials||Simple stresses and strains|| Numerical four...
Strength of materials ||Simple stresses and strains|| Numerical three...
Переглядів 493 місяці тому
Strength of materials ||Simple stresses and strains|| Numerical three...
Third Tds Equation || Thermodynamics relation..
Переглядів 383 місяці тому
Third Tds Equation || Thermodynamics relation..
Application of Second Tds Equation to Reversible adiabatic change of pressure | Thermodynamics..
Переглядів 153 місяці тому
Application of Second Tds Equation to Reversible adiabatic change of pressure | Thermodynamics..
Application of Second Tds Equation to Reversible isothermal change of pressure | thermodynamics..
Переглядів 293 місяці тому
Application of Second Tds Equation to Reversible isothermal change of pressure | thermodynamics..
Strength of materials ||Simple stresses and strains ||Numerical two...
Переглядів 1993 місяці тому
Strength of materials ||Simple stresses and strains ||Numerical two...
Second Tds Equation/Meyers Equation and it's application | Thermodynamics relation
Переглядів 223 місяці тому
Second Tds Equation/Meyers Equation and it's application | Thermodynamics relation
Application of First Tds Equation | Thermodynamics relation...
Переглядів 253 місяці тому
Application of First Tds Equation | Thermodynamics relation...
Thermodynamic relation | Application of Tds Equation to ideal gas...
Переглядів 763 місяці тому
Thermodynamic relation | Application of Tds Equation to ideal gas...
Strength of materials || Simple stresses and strains || Numerical one
Переглядів 3163 місяці тому
Strength of materials || Simple stresses and strains || Numerical one
Application of Cyclic Relations for Interrelating P, V, T | V, S, P | S, T, V | T, H, P
Переглядів 453 місяці тому
Application of Cyclic Relations for Interrelating P, V, T | V, S, P | S, T, V | T, H, P
Unlocking the Power of Entropy: First Tds Equation & Meyer's Equation Explained with Applications
Переглядів 253 місяці тому
Unlocking the Power of Entropy: First Tds Equation & Meyer's Equation Explained with Applications
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Lucknow is the capital city of the Indian state of Uttar Pradesh correct?
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Whe. Calculating for the area of the hollow cylinder , the first diameter is 0.3 not 0.03
Thanks for the correction sir.
Thanks again I just go over the video again and I saw the mistake, really for making sure mistakes.
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