Відео

x = 2 1/3

x = 3 = 24

K= 2 to 3

9.1^2 = 19

k = ^2

9.1 = K

I got 3/3 shots to pass. We don't take STUPIDITY. in 🇻🇳 BUDS or MacV-SOG.

x = 81/3 = 9

x = 81/9 = 9

x = 2/3x

Man, I'm not into math at that moment, but your video was proposed, I see you have barely no viewers and srly I'm so pissed up by all the stupid content about beautiful, stupid challenges, fake politics etc etc I just wanted to encourage you, who took time to make science bright. This is with art, the most important values of humanity.

Why not cube root both sides from first step?

I understand love for detailing, drilling down so on, but is it really necessary in any practical side of life to go to those weird solutions? Everyone knows n=2 by heart. No calculations. There are many things one must know by heart. Of course, I admit there might be a need in weird solutions somewhere in quantum mechanics, but imho UA-cam is not a place where it worths sharing

Can you just use logs ?

n^3=8 n^3=2^3*e^(2*k*π*i) n=2*e^(2*k*π/3*i)=2*(cos(2*k*π/3)+i*sin(2*k*π/3)) {k=0, ±1, ±2} k=0; n1=2 k=1 or k=-2; n2=-1+i√3 k=2 or k=-1; n3=-1- i√3

n=3*exp(i*(2*pi/4)*k) with k element of Z

why the i in -3i

n = ln(80)÷ln(6)

"Well, surely smth between 2 and 3"

That’s pretty easy 10th grade stuff. Why so complicated? Simply go by definition of logarithm: 6^n = 80 | log_6 n = log_6(80) = log_6(2^4*5) n = 4*log_6(2) + log_6(5) So that’s all!

√n/n = √2 √n/(√n•√n) = √2 1/√n = √2 √(1/n) = √2 1/n = 2 n = 1/2

√n/n = √2 (√n/n)^2 = (√2)^2 n/n^2 = 2 n = 2n^2 n/2 = n^2 n^2 = n/2 n^2 = n(1/2) n = 1/2, 0

No you are wrong. The answer is.

First comment🎉

What is your final answer?

а=64

If this was meant to be solved without a calculator then you forgot to specify it in the title. Otherwise nice video.

Your video title is very misleading.

a+a^2+a^3+a^4+a^5 = a(1-a^5)/(1-a) This formula is the sum of five terms of a geometric sequence with first term a and reason a, i.e each term is obtained from the previous one multiplying by a. Now just substitute a=2^3 and we get 2^3(1-2^15)/(1-2^3) = -8/7(1-2^15) (1) We now just have to calculate 2^15 = 2^6*2^6*2^3 = 64*64*8 = 4096*8 = 32768 Substitute 2^15=32768 in (1) and you get -8/7*(1- 32768) =(-8)*(-4681) =37448

I don't beleive that 99% students failed this

please be honest 99% did not fail this

4th method: sqrt(a)/sqrt(a^2) = sqrt(4) sqrt(a/a^2) = sqrt(4) sqrt(1/a) = sqrt(4) 1/a = 4 a = 1/4

sqrt(a) / a = sqrt(4) |² a/a²=4 a=4a² a/a = 4a 1=4a 1/4=a 0.25 = a ------------------------------ sqrt(0.25) / 0.25 = sqrt(4) 0.5 / 0.25 = 2 2 = 2

that was great for me sir! I am an Iranian and I like to know math like you

My intuition was : right part is 2. So the square root of a is larger than a : a must be smaller than 1. To reach 2, let's try something like like 1/sqrt(2), 1/2 or 1/4...

Thats so easy😂

I Wish math olympiads be harder than this basic school piece of cake.

You have very lousy students. It takes 20 seconds or so to resolve. SQR(x)/x=9; SQR(x/x^2)=9; SQR(1/x)=9; 1/x=81; x=1/81;

Sqrt1/sqrt81 is = 1/9 1/9 = 0.111… / 1/81 = 0.01234 The two x are not the same

Simplest ever. i spend 15 seconds to have answer😂

hi