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Bro can you beat me. My username:- Fire.Gamer

We will be do best of 3 like first is normal match and second is semi final. Then we will be do the final

We will be do best of 3 like first is normal match and second is semi final. Then we will be do the final

We will be do best of 3 like first is normal match and second is semi final. Then we will be do the final

Hey man can you beat me. My Username is:- Fire.Gamer. we will be 3 match like first will be practise match and secod will be semi final. And last will be final. I am free from 12:46 to 1:50.

Collab Me I,m A Professional Fc Player

Tumi amar sathe khalba

আামার সাথে খেলবেন id name:Fc.Gamer..

Awesome Bro

Le lien svp

Link bro

Thank you

a= x b^2 = x^2 - 9 a+b = 9 , a^2 - b^2 = 9 a - b = 1 answer

👍 Second method (√3/2) sin 20 sin (60-20) sin (60+20) = (√3/2) sin 20 { (sin 60)^2 - ( sin 20)^2 } (√3/8) { 3 sin 20 - 4(sin 20)^3 } = (√3/8)(sin 60) = 3/16

12^4+84^4+96^4 = (12^4) (1+7^4+8^4) = (144^2)(1+49^2+64^2) = (144)^2 (1+2401+4096) = (144)^2 (2402+4096) = 2(144)^2 (1201+2048) = 2(144)^2 (3249) = 2 (144)^2 (57)^2 Putting in given expression Ans is 144 × 57 = 8208

tan 70 = (tan 50 + tan 20)/(1 - tan 50 tan 20) hence tan 70 - tan 70 tan 20 tan 50 = tan 50 + tan 20 tan 70 = 2 tan 50 + tan 20 equation (1) (because tan 70 = cot 20) now 2 x = tan 50 + tan 20 2 y = tan 70 + tan 20 = 2 ( tan 50 + tan 20) ( by equation 1 ) 2 y = 4 x hence y = 2 x

❤ Second method tan 50 = tan (70-20) = (tan 70 - tan 20)/(1+tan 70 tan 20) = (tan 70 - tan 20)/2 (because tan 70 = cot 20) hence tan 70 - tan 20 = 2 tan 50 tan 70 = tan 20 + 2 tan 50 Putting in expression answer is 2 Third method We know that tan A + tan B = sin (A+B)/(cos A cos B) hence given expression is (sin 90 cos 20 cos 50)/(sin 70 cos 20 cos 70) = cos 50/(sin 70 cos 70) = 2 cos 50/sin 140 = 2cos 50/sin (90+50) = 2 cos 50/cos 50 = 2

x = y +9 x -16 = y -7 hence answer is zero

Merci 😊

Very important problem ❤

Excellent

Good problem Other method x = 7+4√3 , 1/x = 7 - 4√3 Let y = √x+1/√x y^2 = x+1/x+2 = 7+4√3+7-4√3+2 = 16 hence y = 4

cot(A+B) = cos(A+B)/sin(A+B) = (cosA cosB - sinA sinB)/sin (A+B) = 1/(tanA+tan B) - 1/(cot A+cot B) = 1/m - 1/ n

20 is answer h ❤❤❤❤

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If it were in English I would have benefited It seems you are the only one around with such vid Please make it in English plss😢

Pagol... knowledge badau ap phele

Thanks bro. Big love from Egypt

10:43 has the best 😍💋 💝💖❤️

I need boyfriend 💋💋💋💋💋💞💞💞💞

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