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A group of 7 students was asked, How many hours did you watch television last week = 17,7,16,13,6,4,
A group of 7 students was asked, How many hours did you watch television last week = 17,7,16,13,6,4,19 Find the median and mean number of hours for these students. If necessary; round your answers to the nearest tenth (a) Median hours (b) Mean hours
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Переглядів: 4

Відео

A group of 8 students was asked, How many hours did you watch television last week Here are their re
Переглядів 319 годин тому
A group of 8 students was asked, How many hours did you watch television last week Here are their responses 18,15,9,8,10, 13,8, 18 Find the median and mean number of hours for these students If necessary, round your answers to the nearest tenth Median Mean 2 hours hours Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl.com/3r74...
A group of 6 students was asked, How many hours did you watch television last week Here are their re
Переглядів 619 годин тому
A group of 6 students was asked, How many hours did you watch television last week Here are their responses 10, 5, 18, 9, 17, 12 Find the median and mean number of hours for these students. If necessary, round your answers to the nearest tenth. Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl.com/3r745duk 📕 #Math Q&A - tinyurl...
Group of 8 students was asked, How many hours did you watch television last week Here are their resp
Переглядів 319 годин тому
Group of 8 students was asked, How many hours did you watch television last week Here are their responses 19, 19, 19, 11, 5, 15, 10, 17. Find the mean number of hours for these students. If necessary, round your answer to the nearest tenth of an hour. Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl.com/3r745duk 📕 #Math Q&A - ...
'A group of 8 students was asked, How many hours did you watch television last week Here are their r
Переглядів 819 годин тому
'A group of 8 students was asked, How many hours did you watch television last week Here are their responses 10, 14, 13, 13, 16, 12, 9,7 Find the median and mean number of hours for these students. If necessary, round your answers to the nearest tenth. X 5 Median hours Mean hours Mean and Median 01 a dalaset group of B students was asked, How many hours did you watch television Iast weck Hcre a...
The rate constant k for a reaction is measured as a function of temperature A plot of lnk versus 1T
Переглядів 1День тому
The rate constant (k) for a reaction is measured as a function of temperature. A plot of ln(k) versus 1T (in K) is linear and has a slope of -6750 K. Based on this information, the activation energy (Ea) for this reaction is (R = 8.314 Jmol-K) Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl.com/3r745duk 📕 #Math Q&A - tinyurl....
The rate constant for a reaction was measured at several temperatures, and the data were processed t
День тому
The rate constant for a reaction was measured at several temperatures, and the data were processed to yield the graph below. What is the activation energy in kJmol for the reaction R = 8.314 Jmol-K or 0.008314 kJmol-K 1tik 1 Select ore 4.11,9 kJmol OOx10 ^ kJmol 8.4210 kJmol D. -5.89x10^-5 kJmol E. 10.1 kJmol 0 0 Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/...
The equilibrium constant K for a certain reaction was measured as a function of temperature in Kelvi
Переглядів 1День тому
The equilibrium constant K for a certain reaction was measured as a function of temperature (in Kelvin). A plot of ln(K) versus 1T for this reaction gives a straight line with a slope of 1.352 x 10^4 K and a y-intercept of -14.51. Determine the value of ΔH° for this reaction. Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl....
The rate constant k for a given reaction was measured at several different temperatures A graph of
Переглядів 3День тому
The rate constant (k) for a given reaction was measured at several different temperatures. A graph of ln K vs. 1T (temperature measured in Kelvin) produced a straight line with a slope of -4269 K. What is the activation energy of this reaction in kJ mol-1 Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl.com/3r745duk 📕 #Math Q&...
The empirical formula of a compound of phosphorus and oxygen was found to be P2O5 Experimentation s
Переглядів 2День тому
The empirical formula of a compound of phosphorus and oxygen was found to be P2O5. Experimentation shows that the molar mass of this compound is 283.89 gmol. What is the compound's molecular formula Given Empirical formula P2O5 Molar mass 283.89 gmol Find Molecular formula Solution To find the compound's molecular formula, we need to determine the ratio between the empirical formula and the mol...
Find the amount in millimoles of phosphorous in 850 mg of P2O5
Переглядів 1День тому
Find the amount in millimoles of phosphorous in 850 mg of P2O5. Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl.com/3r745duk 📕 #Math Q&A - tinyurl.com/32ue6d49 📕 #Statistics Q&A - tinyurl.com/4yzhvect 📕 #Psychology - tinyurl.com/46a72y3k 📕 #Computerscience Q&A -tinyurl.com/3e52hufx 📕 #Accounting Q&A - tinyurl.com/23f5wbha 📕 #...
How many moles of O2 are needed to produce 12 4 g of P2O5 from the equation P4 + 5O2 = 2P2O5
Переглядів 1День тому
How many moles of O2 are needed to produce 12.4 g of P2O5 from the equation P4 5O2 = 2P2O5? Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl.com/3r745duk 📕 #Math Q&A - tinyurl.com/32ue6d49 📕 #Statistics Q&A - tinyurl.com/4yzhvect 📕 #Psychology - tinyurl.com/46a72y3k 📕 #Computerscience Q&A -tinyurl.com/3e52hufx 📕 #Accounting Q&...
How would I find the percent of P2O5 present in a sample of KH2PO4 I know that phosphorus is 22 761%
День тому
How would I find the percent of P2O5 present in a sample of KH2PO4 I know that phosphorus is 22.761% by mass of KH2PO4. I weighed out 0.422g of KH2PO4, then filtered it with water. Then I added 10 mL of 0.4 M MgSO4 to the filtrate. Then I added 1 mL of 6 M NH3 slowly with a disposable pipette while stirring. Then I touched the stirring rod to red litmus paper. Then I continued adding 1 mL NH3 a...
What is the maximum amount in moles of P2O5 that can theoretically be made from 161 g of P4 and exce
День тому
What is the maximum amount in moles of P2O5 that can theoretically be made from 161 g of P4 and excess oxygen Express your answer to three significant figures and include the appropriate units. the answer is 2.60 mol 2. What is the maximum amount in moles of P2O5 that can theoretically be made from 176 g of O2 and excess phosphorus Express your answer to three significant figures and include th...
Calculate the number of phosphorus atoms in a 100 0g sample of diphosphorus pentoxide P2O5 Be sure
Переглядів 5День тому
Calculate the number of phosphorus atoms in a 100.0g sample of diphosphorus pentoxide P2O5 . Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits. Most Viewed Playlist of HomeworkLIB UA-cam Channel 📕 #Economics Q&A - tinyurl.com/2sb9vdn4 📕 #Chemistry Q&A - tinyurl.com/3r745duk 📕 #Math Q&A - tinyurl.com/32ue6d49 📕 #Statistics Q&A - tinyurl.com/4yzhvect 📕 #Psyc...
Calculate the mass of diphosphorus pentoxide P2O5 that contains one billion 1 00 x 10^9 oxygen atoms
Переглядів 4День тому
Calculate the mass of diphosphorus pentoxide P2O5 that contains one billion 1 00 x 10^9 oxygen atoms
Consider the molecular orbital diagram for methane CH4 drawn below 1 2p 2p 2p 1111 hydrogens carbon
День тому
Consider the molecular orbital diagram for methane CH4 drawn below 1 2p 2p 2p 1111 hydrogens carbon
Assign E or configuration to the following alkenes
Переглядів 1День тому
Assign E or configuration to the following alkenes
Problem 1 Are the following alkenes cis, trans, or neither, based on the arrangement of substituents
Переглядів 8День тому
Problem 1 Are the following alkenes cis, trans, or neither, based on the arrangement of substituents
Which of the following alkenes don't exhibit either cis trans or E Z isomerism Point CH3CH=CHCH3 II
Переглядів 12День тому
Which of the following alkenes don't exhibit either cis trans or E Z isomerism Point CH3CH=CHCH3 II
shown below 5' A A T G C A G C T 3' OH Answer Predict the sequence of bases in
Переглядів 1День тому
shown below 5' A A T G C A G C T 3' OH Answer Predict the sequence of bases in
Suppose that one strand of DNA has the sequence 5' ATGCCAT 3' What is the sequence of the complemen
День тому
Suppose that one strand of DNA has the sequence 5' ATGCCAT 3' What is the sequence of the complemen
Consider the DNA sequence 5'GATTACA 3' If the strand with this sequence forms a double helix with a
Переглядів 3День тому
Consider the DNA sequence 5'GATTACA 3' If the strand with this sequence forms a double helix with a
Chlorine gas and nitrogen gas can react to form NCl3 unbalanced equation N2 + Cl2 NCl3 You perform
Переглядів 2День тому
Chlorine gas and nitrogen gas can react to form NCl3 unbalanced equation N2 Cl2 NCl3 You perform
Solve the following problem Calculate the freezing and boiling point of a solution containing 651 g
Переглядів 1День тому
Solve the following problem Calculate the freezing and boiling point of a solution containing 651 g
Automotive antifreeze consists of ethylene glycol, CH2OHCH2OH, a nonvolatile nonelectrolyte Calcula
Переглядів 2День тому
Automotive antifreeze consists of ethylene glycol, CH2OHCH2OH, a nonvolatile nonelectrolyte Calcula
Ethylene glycol EG, CH2OHCH2OH, is a common automobile antifreeze It is water soluble and fairly no
Переглядів 5День тому
Ethylene glycol EG, CH2OHCH2OH, is a common automobile antifreeze It is water soluble and fairly no
Ethylene glycol CH2 OH CH2 OH is a common antifreeze for automobiles It is soluble in water and low
Переглядів 4День тому
Ethylene glycol CH2 OH CH2 OH is a common antifreeze for automobiles It is soluble in water and low
Ethylene glycol EG CH2OHCH2OH is a common automobile antifreeze It is water soluble and fairly non
Переглядів 8День тому
Ethylene glycol EG CH2OHCH2OH is a common automobile antifreeze It is water soluble and fairly non
Ethylene glycol EG, CH2OHCH2OH, is a common automobile antifreeze It is water soluble and fairly no
Переглядів 1День тому
Ethylene glycol EG, CH2OHCH2OH, is a common automobile antifreeze It is water soluble and fairly no

КОМЕНТАРІ

  • @akshatpandey2256
    @akshatpandey2256 2 дні тому

    Is this problem called Lectures at school on hackerrank?

  • @deepanshu-creatives
    @deepanshu-creatives 9 днів тому

    Basically, if any number of vowels are present, Alex is bound to win. Chris wins only if there are no vowels at all.

  • @user-lb6ir3ld4n
    @user-lb6ir3ld4n 16 днів тому

    this is totally wrong. there aren't even any g or u irreps in the D3h character table.

  • @SurprisedDivingBoard-vu9rz
    @SurprisedDivingBoard-vu9rz 23 дні тому

    If you know oxidation and reduction 50% chemistry is done. Whether organic or life or metals. Just something to do with oxygen.

    • @qnawire
      @qnawire 19 днів тому

      if you have any doubts in this question you can send us to our subject expert they will help you - t.me/unblurfree

  • @bharatahire6765
    @bharatahire6765 29 днів тому

    Can you provide code for this?

    • @qnawire
      @qnawire 28 днів тому

      if you have any doubts in this question you can send us to our subject expert they will help you - t.me/unblurfree

  • @abdulraheemakosile5024
    @abdulraheemakosile5024 Місяць тому

    Anyone got a better soluion for this?

    • @qnawire
      @qnawire 28 днів тому

      if you have any doubts in this question you can send us to our subject expert they will help you - t.me/unblurfree

  • @abdulraheemakosile5024
    @abdulraheemakosile5024 Місяць тому

    bruhh c'mon

    • @qnawire
      @qnawire 28 днів тому

      if you have any doubts in this question you can send us to our subject expert they will help you - t.me/unblurfree

  • @CuriousLad
    @CuriousLad Місяць тому

    Wait, which textbook is this referencing? Also, great explanation!

    • @qnawire
      @qnawire 28 днів тому

      if you have any doubts in this question you can send us to our subject expert they will help you - t.me/unblurfree

  • @easonback
    @easonback Місяць тому

    Your code is wrong. Used Java passed all the test cases: public static int countTeams(int teamSize_1, int teamSize_2, int p) { // Write your code here int maxTeams = Math.min(p / teamSize_1, p / teamSize_2); int maxTeamSize = Math.max(teamSize_1,teamSize_2); int minTeamSize = Math.min(teamSize_1,teamSize_2); for (int i = maxTeams; i >= 0; i --) { if ( (p - i * maxTeamSize) % minTeamSize == 0) { return i + (p - i * maxTeamSize) / minTeamSize; } } return -1; }

  • @Buy_YT_Views_66
    @Buy_YT_Views_66 Місяць тому

    This is the peak of human achievement.

  • @alhaitham7583
    @alhaitham7583 2 місяці тому

    Are you an AI?

    • @qnawire
      @qnawire Місяць тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @panashejonga4258
    @panashejonga4258 2 місяці тому

    bho here?

    • @qnawire
      @qnawire Місяць тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

    • @qnawire
      @qnawire Місяць тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @tawfiqnabil2467
    @tawfiqnabil2467 2 місяці тому

    The link in the telegram plz

  • @vaibhavpawar2002
    @vaibhavpawar2002 2 місяці тому

    Where is the code

    • @qnawire
      @qnawire 2 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @alyl603
    @alyl603 2 місяці тому

    I mean the overlap isn't an issue necessarily if I'm first going through each column from 1 to 2024 and coloring the topmost 1000 squares in each column then the area I have left to work with is 1024 completely uncolored rows, from which I can effectively paint 1000 squares in any way I want since it won't matter. ultimately end up with 2024*1000 + 1024*1000 = 3,048,000 no?

    • @qnawire
      @qnawire 2 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @learningmathswithconcepts7203
    @learningmathswithconcepts7203 2 місяці тому

    Plz find minimum work done in shaking

    • @qnawire
      @qnawire 2 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @talalbintariq8339
    @talalbintariq8339 2 місяці тому

    from which book is this question from?

    • @qnawire
      @qnawire 2 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @senpaix6613
    @senpaix6613 2 місяці тому

    TY

    • @qnawire
      @qnawire 2 місяці тому

      Glad ! to Help You Share with students and friends about our channel in our support Thank You !

  • @rishirockzz1600
    @rishirockzz1600 2 місяці тому

    hello sir, how do we solve for a p+ polysilicon device? expected to find Vtp and Φms flat band voltage is also not given. Determine the metal - semiconductor work function difference and the threshold voltage for a silicon MOS device at 𝑇 = 3 0 0 𝐾 for the following parameters: 𝑝 + polysilicon gate, 𝑁 𝑎 = 2 × 1 0 1 6 𝑐 𝑚 - 3 , 𝑡 𝑜 𝑥 = 8 𝑛 𝑚 = 8 0 Å , and 𝑄 𝑠 𝑠 ' = 2 × 1 0 1 0 𝑐 𝑚 - 2 .

  • @user-rm5wy3lt7q
    @user-rm5wy3lt7q 3 місяці тому

    what is the coincidence me working on this question today. great work!!!!

    • @qnawire
      @qnawire 3 місяці тому

      Awesome! Thank you! Glad ! to Help You Share with students and friends about our channel in our support Thank You !

  • @d.gandhi8878
    @d.gandhi8878 3 місяці тому

    What's the answers

    • @qnawire
      @qnawire 3 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @academicstuff548
    @academicstuff548 3 місяці тому

    Thanks you saved me.

    • @qnawire
      @qnawire 3 місяці тому

      Glad I could help Glad ! to Help You Share with students and friends about our channel in our support Thank You !

  • @gowthamsharma654
    @gowthamsharma654 3 місяці тому

    GG lifesaver!

    • @qnawire
      @qnawire 3 місяці тому

      Glad ! to Help You Share with students and friends about our channel in our support Thank You !

  • @nraphson
    @nraphson 3 місяці тому

    It's wrong For parallel flow ○T1 = 220-10 = 210⁰c ○T2 = 115-75 = 40⁰c Now LMTD ....

    • @qnawire
      @qnawire 3 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @worldoptics
    @worldoptics 3 місяці тому

    can you give the c++ code for this problem?

  • @shlokagrawal6405
    @shlokagrawal6405 3 місяці тому

    fuck numerade for their paywall, thanks

  • @iamadityavaishy
    @iamadityavaishy 3 місяці тому

    Give the code file please.

    • @qnawire
      @qnawire 3 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @me57shreyashjadhav37
    @me57shreyashjadhav37 3 місяці тому

    Wrong answer

    • @qnawire
      @qnawire 3 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @brutalbrothers05
    @brutalbrothers05 3 місяці тому

    Please also provide the code

    • @qnawire
      @qnawire 3 місяці тому

      def countTeams(teamSize_1, teamSize_2, p): # Calculate the maximum number of teams using the smaller team size max_teams = min(p // teamSize_1, p // teamSize_2) # Check if the total number of participants is divisible by both team sizes if p % teamSize_1 == 0 and p % teamSize_2 == 0: return max_teams else: return -1 # Example usage teamSize_1 = 3 teamSize_2 = 4 p = 7 print(countTeams(teamSize_1, teamSize_2, p)) # Output: 2

    • @NAVEEN-pg5ic
      @NAVEEN-pg5ic 3 місяці тому

      @@qnawire agar code na aata ho kripya krke likhe na

  • @amoghmokshith8111
    @amoghmokshith8111 3 місяці тому

    Bro can u send the code

    • @qnawire
      @qnawire 3 місяці тому

      def repeated_digit(n): # Check if a number has repeated digits s = set() while n != 0: d = n % 10 if d in s: return False s.add(d) n = n // 10 return True def calculate(L, R): answer = 0 for i in range(L, R + 1): if repeated_digit(i): answer += 1 return answer # Example usage L, R = 80, 120 print(calculate(L, R)) # Output: 27

    • @amoghmokshith8111
      @amoghmokshith8111 3 місяці тому

      @@qnawire thanks man

  • @MUHAMMADHAMZA-ue9qv
    @MUHAMMADHAMZA-ue9qv 3 місяці тому

    Thanks for the explanation I Appreciate it

    • @qnawire
      @qnawire 3 місяці тому

      Glad it was helpful! Glad ! to Help You Share with students and friends about our channel in our support Thank You !

  • @subhranildey2326
    @subhranildey2326 3 місяці тому

    Thanks.

    • @qnawire
      @qnawire 3 місяці тому

      Glad! to Help You Share with students and friends about our channel in our support. Thank You!

    • @arifism1
      @arifism1 2 місяці тому

      hi bro

  • @arthurguilhermedeboni3664
    @arthurguilhermedeboni3664 3 місяці тому

    wheres the final code?

    • @qnawire
      @qnawire 3 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @HyuukeShoemon
    @HyuukeShoemon 3 місяці тому

    Someone was able to solve this in HackerRank?

  • @raviashray1431
    @raviashray1431 4 місяці тому

    This is completely wrong, DSQI values from 0 to 1

    • @qnawire
      @qnawire 4 місяці тому

      we are sorry for If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @sausagefeet4860
    @sausagefeet4860 4 місяці тому

    Utter bullshit

    • @qnawire
      @qnawire 4 місяці тому

      we are sorry for If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @deekshithtirumala6474
    @deekshithtirumala6474 4 місяці тому

    It's o(n*q) can't we reduce complexity

    • @qnawire
      @qnawire 4 місяці тому

      we are sorry for If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @SuccessGeorge-ov9dn
    @SuccessGeorge-ov9dn 4 місяці тому

    Thank you

    • @qnawire
      @qnawire 4 місяці тому

      You're welcome Glad ! to Help You Share with students and friends about our channel in our support Thank You !

  • @rajadas9716
    @rajadas9716 4 місяці тому

    Where is the code

    • @qnawire
      @qnawire 4 місяці тому

      def getMinMachines(start, end): # Combine start and end times into a single list of tuples tasks = [(s, e) for s, e in zip(start, end)] # Sort tasks based on end times tasks.sort(key=lambda x: x[1]) # Initialize a list of machines machines = [] for task in tasks: # Check if there's an available machine assigned = False for machine in machines: if machine[-1][1] <= task[0]: machine.append(task) assigned = True break # If no available machine, create a new one if not assigned: machines.append([task]) # Number of machines created is the answer return len(machines) # Example usage start = [2, 1, 5, 5, 8] end = [5, 3, 8, 6, 12] print(getMinMachines(start, end)) # Output: 3

    • @rajadas9716
      @rajadas9716 4 місяці тому

      @@qnawire this code is not same as in the slide right? Cause I tried the slide code in IBM coding round, it didn't pass all the test cases

  • @sreeramreddy4531
    @sreeramreddy4531 4 місяці тому

    Were you able to find the answer ?

    • @qnawire
      @qnawire 4 місяці тому

      we are sorry for If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @tedb9602
    @tedb9602 4 місяці тому

    Here's my attempt at solving this: (Python) ``` def get_freq(word): return {c: word.count(c) for c in set(word)} def get_minimal_moves(word): freq = get_freq(word) moves = 0 new_word = word while any(freq[c] > 1 for c in freq): sorted_freq = sorted(freq.items(), key=lambda x:x[1], reverse=True) c = sorted_freq[0][0] indices = [i for i, x in enumerate(new_word) if x == c] i = freq[c] // 2 index = indices[i] left, right = new_word[:index], new_word[index+1:] if c in left or c in right: new_l = left new_r = right if c in left: j = indices[i-1] new_l = left[:j] + left[j+1:] if c in right: j = indices[i+1] - index - 1 new_r = right[:j] + right[j+1:] new_word = new_l + c + new_r moves += 1 freq = get_freq(new_word) return moves ```

  • @divineovundah7222
    @divineovundah7222 4 місяці тому

    Thanks

    • @qnawire
      @qnawire 4 місяці тому

      Welcome

  • @19_ammarsaquib_aec_ece46
    @19_ammarsaquib_aec_ece46 4 місяці тому

    Also provide the java code for this problem

    • @qnawire
      @qnawire 4 місяці тому

      The English lecture at HackerElementary School focuses on teaching students the letters of the alphabet. Here’s how the students can achieve a minimal word length: For each character c in the string: Find the first occurrence of c to the left of the current index. Find the first occurrence of c to the right of the current index. Delete both occurrences (if they exist). Repeat step 1 for all characters in the string. For example, consider the word adabacaea: Choosing index 4 (0-based) with character ‘a’: Delete the first occurrence of ‘a’ to the left (index 2). Delete the first occurrence of ‘a’ to the right (index 6). The resulting word is adbacea. Repeat this process for all characters. The minimum number of moves required to obtain a word of minimal length is the total number of deletions performed.

  • @studentshelperpuneet2220
    @studentshelperpuneet2220 4 місяці тому

    Bhai shi se solve kro kya h questions kya h answer kya h explaination kuchh pta hi nhi chl rha hai

    • @qnawire
      @qnawire 4 місяці тому

      we are sorry for If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @maxmuster7003
    @maxmuster7003 4 місяці тому

    Good work.❤

    • @qnawire
      @qnawire 4 місяці тому

      Thanks ✌️

  • @maxmuster7003
    @maxmuster7003 4 місяці тому

    Routine for searching 8x16 character font in bios memory and display 16 lines with "segment address + offset address", the byte of the memory location and the bits of the byte and then waiting for key press. Space bar = next 16 bytes, ESC = exit. Start batch file with segment + offset attached. Example: C:\MEMSPY.BAT C000 1A00 @echo off REM MEMSPY.BAT REM Display 16 bytes REM Need two parameter attached REM for segment and offset: like C000 1700 REM Space = next 16 bytes REM ESC = Exit echo a>tmp.deb echo mov ax,b800>>tmp.deb echo mov es,ax>>tmp.deb echo mov bx,%1>>tmp.deb echo mov si,%2>>tmp.deb echo cld>>tmp.deb echo mov ds,bx>>tmp.deb echo xor di,di>>tmp.deb echo mov ch,10>>tmp.deb REM --- Output segment address --- echo mov dx,bx>>tmp.deb echo call 0170>>tmp.deb echo mov al,3A>>tmp.deb echo stosb>>tmp.deb echo inc di>>tmp.deb REM --- Output offset address --- echo mov dx,si>>tmp.deb echo call 0170>>tmp.deb echo add di,2>>tmp.deb REM --- Get byte from ds:si --- echo lodsb>>tmp.deb REM --- Output byte --- echo xor dx,dx>>tmp.deb echo mov ah,al>>tmp.deb echo mov dh,al>>tmp.deb echo mov cl,2>>tmp.deb echo call 0172>>tmp.deb echo add di,2>>tmp.deb REM --- Output bits --- echo mov dl,ah>>tmp.deb echo mov cl,8>>tmp.deb echo mov al,31>>tmp.deb echo rol dl,1>>tmp.deb echo test dl,1>>tmp.deb echo jnz 0141>>tmp.deb echo mov al,30>>tmp.deb echo stosb>>tmp.deb echo inc di>>tmp.deb echo dec cl>>tmp.deb echo jnz 0136>>tmp.deb REM --- next row --- echo add di,76>>tmp.deb echo dec ch>>tmp.deb echo jnz 0112>>tmp.deb REM --- increase seg address + 64 kb --- echo cmp si,0>>tmp.deb echo jnz 0157>>tmp.deb echo add bx,1000>>tmp.deb REM --- get key from keyboard --- echo mov ah,0>>tmp.deb echo int 16>>tmp.deb echo cmp al, 1b>>tmp.deb echo jz 0187>>tmp.deb echo cmp al,20>>tmp.deb echo jz 010C>>tmp.deb echo jmp 0157>>tmp.deb REM -- Subroutine -- REM --- Output 4 hex ASCII --- echo org 0170>>tmp.deb echo mov cl,4>>tmp.deb echo rol dx,4>>tmp.deb echo mov al,dl>>tmp.deb echo and al,F>>tmp.deb echo cmp al,A>>tmp.deb echo jb 017F>>tmp.deb echo add al,7>>tmp.deb echo add al,30>>tmp.deb echo stosb>>tmp.deb echo inc di>>tmp.deb echo dec cl>>tmp.deb echo jnz 0172>>tmp.deb echo ret>>tmp.deb REM echo.>>tmp.deb echo n MEMSPY.COM>>tmp.deb echo rcx>>tmp.deb echo 88>>tmp.deb echo wcs:100>>tmp.deb echo q>>tmp.deb debug<tmp.deb>DEB.INF del tmp.deb cls MEMSPY.COM del MEMSPY.COM

    • @qnawire
      @qnawire 4 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @maxmuster7003
    @maxmuster7003 4 місяці тому

    Step 5: decimal 16 is hexadecimal 10.....hexadecimal 16 is decimal 22

    • @qnawire
      @qnawire 4 місяці тому

      If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @maxmuster7003
    @maxmuster7003 4 місяці тому

    How to make a screenshot of the text screen and to reload the screen using two batch files and some internal Debug commands: n, r w, q and n, r, l, q and segment address, file name and file size. Test in 4 steps from DosBox command prompt: dir ScreS.bat Screen1.SAV cls ScreL.bat Screen1.SAV @echo off REM ScreS.bat filename REM Save text screen to file. echo n %1>tmp.deb echo rcx>>tmp.deb echo FA0>>tmp.deb echo rds>>tmp.deb echo B800>>tmp.deb echo wds:0>>tmp.deb echo q>>tmp.deb debug<tmp.deb>nul del tmp.deb @echo off REM ScreL.bat filename REM Load text screen from file. echo n %1>tmp.deb echo rcx>>tmp.deb echo FA0>>tmp.deb echo rds>>tmp.deb echo B800>>tmp.deb echo lds:0>>tmp.deb echo q>>tmp.deb debug<tmp.deb>nul del tmp.deb

    • @qnawire
      @qnawire 4 місяці тому

      we are sorry for If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @maxmuster7003
    @maxmuster7003 4 місяці тому

    These are internal Debug commands. All values are hexadecimal. I like to use a Debug version in DosBox that provide 16 bit and 32 bit instructions. DosBox emulates a PC with intel CPU 80386/80387.

    • @qnawire
      @qnawire 4 місяці тому

      we are sorry for If you have any doubts so please send us our subject expert will help you - t.me/unblurfree

  • @mayankpandey7108
    @mayankpandey7108 4 місяці тому

    we need answers not quwstions

    • @qnawire
      @qnawire 4 місяці тому

      we are sorry for If you have any doubts so please send us our subject expert will help you - t.me/unblurfree