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Mathematics with Naveed
Pakistan
Приєднався 8 лип 2020
My videos are useful for mathematics learner at FSc, BS , MSc
and higher level. This channel covers subject like Linear Algebra,
Calculus, Complex Analysis,Differential Equations, Topology.
Thanks for watching
Mathematics videos by Muhammad Naveed.
and higher level. This channel covers subject like Linear Algebra,
Calculus, Complex Analysis,Differential Equations, Topology.
Thanks for watching
Mathematics videos by Muhammad Naveed.
Відео
Sin^2x is uniformly continuous on R
Переглядів 1537 місяців тому
we prove that Sin²x is uniformly continuous for all real numbers
Sinx is continuous for all real numbers
Переглядів 837 місяців тому
In this lecture we prove that sine function is continuous everywhere. We prove this result by delta epsilon definition method.
limit x approaches to zero x²sin(1/x)
Переглядів 497 місяців тому
In this lecture we prove that limit x approaches to 0 x^2sin1/x by ephsilon delta definition method. #limit #limitoffunction
limit of xsin(1/x) as x approaches to 0
Переглядів 2047 місяців тому
In this lecture we show that limit of trignometric function xsin1/x is zero as x approaches to zero by delta epsilon definition. #limitoffunction ua-cam.com/play/PL3bMIjFBNjoDIk8gw17hjqNR9yKdnkbei.html&si=CrPduAjOWpna_Xf8
Finding Limit of a function by ephsilon delta definition
Переглядів 168 місяців тому
In this lecture we find limit of a function by definition method that is we solve an example by delta ephsilon method. #limitoffunction ua-cam.com/play/PL3bMIjFBNjoDIk8gw17hjqNR9yKdnkbei.html&si=CrPduAjOWpna_Xf8
Limit of a function if exists is unique
Переглядів 2338 місяців тому
In this lecture we prove that limit of a function if it exists is unique. #limit #limitoffunction #realanalysis ua-cam.com/play/PL3bMIjFBNjoDIk8gw17hjqNR9yKdnkbei.html&si=CrPduAjOWpna_Xf8
Every monotonic increasing bounded sequence converges to its least upper bound
Переглядів 2618 місяців тому
In this lecture we prove that every monotonic increasing bounded sequence converges to its least upper bound. ua-cam.com/video/4ar32f_1w2k/v-deo.html ua-cam.com/video/VqMdP3o5Hkw/v-deo.html #monotonic #sequence ua-cam.com/play/PL3bMIjFBNjoDIk8gw17hjqNR9yKdnkbei.html&si=CrPduAjOWpna_Xf8
Every convergent sequence is bounded
Переглядів 938 місяців тому
In this lecture we prove that every convergent sequence is bounded but converse is not true, moreover we discuss an example of a sequence which is bounded but not convergent. ua-cam.com/video/PigvxwebXFk/v-deo.html ua-cam.com/video/4ar32f_1w2k/v-deo.html ua-cam.com/video/UELY9zQP0jY/v-deo.html #convergent #sequence #realanalysis playlist ua-cam.com/play/PL3bMIjFBNjoDIk8gw17hjqNR9yKdnkbei.html&s...
Limit of a sequence if exists is unique
Переглядів 5238 місяців тому
In this lecture we prove that the limit of a sequence is unique. ua-cam.com/video/PigvxwebXFk/v-deo.html ua-cam.com/video/VqMdP3o5Hkw/v-deo.html ua-cam.com/video/UELY9zQP0jY/v-deo.html #limit_of_sequence #realanalysis playlist ua-cam.com/play/PL3bMIjFBNjoDIk8gw17hjqNR9yKdnkbei.html&si=CrPduAjOWpna_Xf8
Prove that √2 is an irrational number
Переглядів 898 місяців тому
In this lecture we prove that sqrt2 is irrational number. ua-cam.com/video/4ar32f_1w2k/v-deo.html ua-cam.com/video/VqMdP3o5Hkw/v-deo.html ua-cam.com/video/UELY9zQP0jY/v-deo.html #irrationalnumber #irrational_numbers #realanalysis playlist ua-cam.com/play/PL3bMIjFBNjoDIk8gw17hjqNR9yKdnkbei.html&si=CrPduAjOWpna_Xf8
Adjacency Matrix of a Graph
Переглядів 14010 місяців тому
In this lecture we discuss adjacency matrix of a graph with some examples. We also discuss adjacency matrix of complete graph. #graphtheory #adjacencymatrix
K7 is planar on torus of genus one
Переглядів 30611 місяців тому
In this lecture we learn how to draw k7 that is complete graph of order 7 on torus of genus one. In short we prove k7 is planar on torus of genus one. k5 is planar on torus of genus one ua-cam.com/video/3U_e7ukFWCs/v-deo.html k6 is planar on torus of genus one ua-cam.com/video/LEx4HgQOJrg/v-deo.html #graphtheory #completegraph
K6 is planar on torus of genus one | graph theory
Переглядів 41311 місяців тому
In this video we discuss how to draw k5 complete graph of order 5 on torus of genus one. That k5 is planar on torus of genus one k5 is planar on torus of genus one ua-cam.com/video/3U_e7ukFWCs/v-deo.html k7 is planar ua-cam.com/video/akhYWOtIRyc/v-deo.html #graphtheory #completegraph
K5 is planar on torus of genus one
Переглядів 23911 місяців тому
In this lecture we learn ho to draw k5, complete graph of order 5 o on torus of genus one. k5 is planar on torus of genus 1. k7 is planar on torus of genus one ua-cam.com/video/akhYWOtIRyc/v-deo.html k6 is planar on torus of genus one ua-cam.com/video/LEx4HgQOJrg/v-deo.html #completegraph #graphtheory
Multivalued functions | Real valued function
Переглядів 35Рік тому
Multivalued functions | Real valued function
Neighbourhood and its types in mathematics | Deleted neighbourhood
Переглядів 140Рік тому
Neighbourhood and its types in mathematics | Deleted neighbourhood
Medial and Paramedial laws in LA semigroup
Переглядів 103Рік тому
Medial and Paramedial laws in LA semigroup
Blood Relation Reasoning Tricks | Family Relation Reasoning
Переглядів 272Рік тому
Blood Relation Reasoning Tricks | Family Relation Reasoning
Excelente, consulta como seria el procedimiento para el limite (x^(1/n)-a^(1/n))/(x-a). Saludos
Aur please koyi notes waghera provide kare
Please more videos ,,daily
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But,like you said, we need to look every subcover of A. Just finding some subcover which is not finite doesn't h-show that R is non-compact. Cuz, a space is compact if every open cover has a finite subcover. There might be some subcovers of A such that they are finite.
very helpful and easy to understand. u should buy a mic so that your voice is more clear
assalamoalikum sir g Left almost semi group ka notes ya book mil jayega
What a trick to find all possible topology!! Great and astonishing work keep it up sir
7:41 X is compact, so it is a compact neighbourhood of x, no need to consider any open cover
Thank you 😊
This is the definition of Hausdorff space. Isn’t it? T1 is different from Hausdorff but this definition is for T1
thanks
Fix your sound first
Mashallah..
Topology ka chapter 8 ka 8.5.1therom k dono parts plzz upload kr dy
Thank you from India
Closed subbase meaning plz send definition of this if ur watching i need definition today only
GOD BLESS MORE SIR
plss check de morgans law.
Jazak-llahu khairan kasiran
Thak you so much ❤
Very nice explanation Sir 🙏
Sir m=max(m1,m2) q lia 02:38
Great vid
Nice 🎉
Very helpful
Good effort sir
Assalamualaikum..sir aap product spaces nd functional space py videos bnaen
Thanks for uploading this video. Every LA-Semigroup and RA-Semigroup holds medial or bi-symmetry law but the converse may not be true. Hope that you will upload more videos.
Sir g agr apk sath notes hai tu plz share kare. . .
Nice problem but it would be so much nicer if you could use a word processor to show all the steps. And then make it downloadable. Three blue one brown has really nice presentation and the software is open source
Thanks for such a nice suggestion.
@@mathematicswithnaveed4928 Their presentation is stellar, I’m sure you agree. Even so, when you solve some problem, you could write it down using ms word or similar where you make some useful comments in between. When you’re happy, print it as pdf and make sure people can download it. Mathologer also has incredibly nice graphics and animation. I have no idea how ot’s made but when you find something really neat, you can make a screenshot. Much better than making notes yourself. While good to do so, one should transfer everything to a word processor so that everything can be saved digitally.
1st question you wrote 64/2 = 2???
Yh he made a mistake, 32 is the answer
You made it simple sir! Be blesed
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❤❤❤❤❤❤❤❤❤❤❤❤❤ thanks sir
Most welcome
❤
Thankyou😄
Welcome 😊
Thank you 😊
Nice way
How can it be negative when you are taking absolute value????
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Good ❤❤❤❤❤❤❤🎉🎉🎉❤❤❤
mashallah sir slay inshallah
Well
Sir agr 0 to 2 ki jgh limit me 0 to 1 diya ho to bhi yhi solution krskte hai na
Thank you sir🥰
This is a typical case in which one should not use the definition of the derivative directly.Assuming the product rule is known we set y(x) = x^(1/3) so that y(x)^3 = x. Now use the product rule twice to see that (y(x)^3 )'= 3 y(x) ^2 * y '(x) . But (y(x) ^3) ' = x ' =1,and therfore y '(x) = 1/3 * 1/y(x)^2 = 1/3 x^(-2/3)
Thank you very much
❤
Great video! Jesus loves you!
This notation software desperately needs copy-paste functionality
Your x looks like a u...