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Phil Cool Math
Приєднався 11 вер 2021
This Channel is basically for Mathematics 👍.
Let's eliminate this popular phobia for Mathematics in schools.
Mathematics is not that difficult but some students run away from it because of fear. On this channel, we remove that fear of Mathematics from the minds of students.
Let's chin up and fight the fear of Mathematics💪.
Let's eliminate this popular phobia for Mathematics in schools.
Mathematics is not that difficult but some students run away from it because of fear. On this channel, we remove that fear of Mathematics from the minds of students.
Let's chin up and fight the fear of Mathematics💪.
UK | Olympiad Mathematics | Only one solution is satisfying
This is beautifully solved #maths #algebra #olympiad #mathstricks #exponential #equation #education
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Відео
Russian | Olympiad Mathematics | Fully solved and confirmed
Переглядів 21115 годин тому
This is a beautiful Olympiad Mathematics #maths #algebra #olympiad #mathstricks #exponential #equation #mathematics #education
US | Olympiad Mathematics Challenge | Fully solved
Переглядів 1 тис.2 години тому
This is beautifully solved for you guys by Phil Cool Math #maths #algebra #exponential #olympiad #equation #mathstricks #mathematics #exponentialequation
Indian | Olympiad Mathematics Challenge | This is beautifully and fully solved.
Переглядів 1562 години тому
This is beautifully solved for you guys #maths #algebra #exponential #olympiad #equation #mathstricks #mathematics #education #exponentialequation #math
Russian | Olympiad Mathematics | Fully solved
Переглядів 5452 години тому
This is beautifully solved. You should check it out #maths #algebra #olympiad #exponential #mathstricks #equation #mathematics #education #exponentialequation #math
Indians | Can you solve this? | Olympiad Mathematics.
Переглядів 4794 години тому
This is beautifully solved for you guys #maths #algebra #olympiad #exponential #mathstricks #equation #mathematics #exponentialequation #education
Germany | Can you solve this? | Exponential Olympiad Mathematics.
Переглядів 2804 години тому
This is beautifully solved for you #maths #algebra #olympiad #exponential #mathstricks #mathematics #equation #education
Do it yourself | Problem on indices.
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This is personally for you #maths #algebra #olympiad #exponential #mathstricks #equation #mathematics #education #math #exponentialequation
Unusual quadratic equation | High school students
Переглядів 3397 годин тому
This is beautifully solved for you #maths #algebra #olympiad #exponential #equation #mathematics #education #exponentialequation #mathstricks
Olympiad Mathematics | Germany | Only one solution is satisfying
Переглядів 9207 годин тому
This is beautifully solved for you guys #maths #algebra #olympiad #exponential #mathstricks #equation #education #mathematics #math
Germany | Can you solve this? | Olympiad Mathematics | Simultaneous equation
Переглядів 5597 годин тому
This is beautifully solved #maths #algebra #olympiad #exponential #equation #mathematics #mathstricks #exponentialequation
Germany | Can you solve this? Olympiad Mathematics The two methods used
Переглядів 2 тис.9 годин тому
This is beautifully solved for you guys #maths #algebra #mathstricks #olympiad #exponential #equation #mathematics #education #math
Expanding an expression | Beautifully done
Переглядів 1449 годин тому
This is beautifully done ✅ #maths #algebra #mathstricks #olympiad #exponential #mathematics #education #exponentialequation #math #equation
Exponential equation | Do it yourself
Переглядів 22412 годин тому
This is for you #maths #algebra #olympiad #exponential #equation #mathstricks #education #exponentialequation #mathematics #math
Russians | Can you solve this? | Olympiad Mathematics
Переглядів 1,2 тис.12 годин тому
This is beautifully solved for you #maths #algebra #olympiad #exponential #mathstricks #equation #education #exponentialequation #mathematics #math
Germany | Can you solve this? | Olympiad Mathematics
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Germany | Can you solve this? | Olympiad Mathematics
Germany | Can you solve this? | Olympiad Mathematics
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Germany | Can you solve this? | Olympiad Mathematics
Brazilian | Can you solve this? | Olympiad Mathematics
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Brazilian | Can you solve this? | Olympiad Mathematics
Germany | can you solve this | Olympiad Mathematics
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Germany | can you solve this | Olympiad Mathematics
Germany | Can you solve this | Olympiad Mathematics
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Germany | Can you solve this | Olympiad Mathematics
Germany | can you solve this? | Olympiad Mathematics
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Germany | can you solve this? | Olympiad Mathematics
Russian | Surdic equation | How many high school students can solve this?
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Russian | Surdic equation | How many high school students can solve this?
Olympiad Mathematics | How to eliminate the root 🫚
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Olympiad Mathematics | How to eliminate the root 🫚
Russian Olympiad Mathematics | Fully solved
Переглядів 61419 годин тому
Russian Olympiad Mathematics | Fully solved
Russian | Olympiad Mathematics | Try this yourself
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Russian | Olympiad Mathematics | Try this yourself
Russian | Olympiad Mathematics | High school students can solve this
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Russian | Olympiad Mathematics | High school students can solve this
Russian | Olympiad Mathematics | The complete solution 💯
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Russian | Olympiad Mathematics | The complete solution 💯
Brazilian | Olympiad Mathematics | Well explained and confirmed 👍
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Brazilian | Olympiad Mathematics | Well explained and confirmed 👍
Quadratic equation involving fractions | Olympiad Mathematics | Fully solved
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Quadratic equation involving fractions | Olympiad Mathematics | Fully solved
Olympiad Mathematics Challenge | How I dealt with this.
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Olympiad Mathematics Challenge | How I dealt with this.
Да боже мой, 2!
Please sir help me with this division question. 5938÷35
@@soniasophia690 okay I will
Unnecessarily complicated. Since both sides/brackets are squared, then what is inside the brackets is also equal. Hence 2^n-64=2^n --> 2(2^n)-64=0
1•1•1+9=10
Simply x+2= + Or - 2. So x is either 0 or -4
Root x= minus 6
Minus 6
Don't let the square root symbol intimidate you. It's just a symbol. Just rewrite the original equation as a quadratic in sqrt(x). Multiply through by 2 and rearrange to get x + 2*sqrt(x) - 24 = 0. Now use the quadratic formula. a=1, b=2, c=-24 gives us sqrt(x) = (-6,4). Reject sqrt(x)=-6 because that is nonsense. Thus the only answer is x = 4^2 = 16.
Great explanation! 👍
It isn't a level of olympiad ! Very primitive level ....
You followed an unnecessarily long and complicated procedure. The result is 5 .
The solution set must be specified.
Okay 👍
5
x = 0
Thanks 👍
Hi, can you teach financial please?
@@hello-yu9tx Please I don't get your question. ❓
@PhilCoolMath I mean, did you study finance or maybe you have knowledge in it?
I found the solution without using the formula, creating a quadrst by adding the square of 5 on both sides.
@@Jan-m1t okay 👍
O wish you were my maths teacher in high-school I could not score E in maths
Wow, thanks
You can go through reminder theorem and get the question solve very fast and short
3x²+2=4 x²=⅔ So real roots are ±sqrt(⅔) 3x²+2= -4 x²= -2 So complex roots are ±i×sqrt2
Good 👍
3^x = 6 x= log(3) 6 x=1.6309
super
Thank you
x=log12/2log3=(log3+2log2)/2log3=½+log2/log3 x≈0.5+0.301/0.477≈1.131 3^(2×1.131)≈12.0019
Good job 👍
take a look at my approach
Solve something difficult or tricky, everyone can splve this.
Okay
2x^2 =2x 1x^1 2x x^1 2x (x ➖ 2x+1).
X=0,-4,-2+2i,-2-2i
Thanks
X=0 or -4
The soutins are x=0 and x= -4
x=log8/2log4=log2³/2log2²=3log2/4log2=¾=0.75 4^(¾)×4^(¾)=4^(6/4)=4^(3/2)=sqrt(4^3)=sqrt64=8
Good 👍
Why didn't you take the log of Both Sides right from the beginning?
Brazilian Olympiad Mathematics: (√x)/(2x) = x, x =? 1 > x > 0; (√x)/(2x) = 1/(2√x) = x, x√x = 1/2, x³⸍² = 1/2, (x³⸍²)²⸍³ = (1/2)²⸍³ x = (1/2)²⸍³ = (1/2²)¹⸍³ = (1/4)¹⸍³ = ³√(1/4) Answer check: x = (1/2)²⸍³ = ³√(1/4): (√x)/(2x) = 1/(2√x), 2√x = 2[(1/2)²⸍³]¹⸍² = [8(1/2)]¹⸍³ = ³√(1/4) (√x)/(2x) = 1/(2√x) = 1/(³√4) = ³√(1/4) = x; Confirmed Final answer: x = ³√(1/4) = (³√2)/[(³√2)(³√4)] = (³√2)/(³√8) = (³√2)/2 Note: x = 0, (√x)/(2x) = 0/0, The equation is not defined; x ≠ 0
√3x/x=6 => √3x=6x => (√3x)²=(6x)² => 3x=36x² => 36x²-3x=0 a=36; b=-3; c=0 X=-b±√∆/2a With ∆=3 => X=-(-3)±3/2×36 => x'=3+3/72 => x'=1/12 or => x"=3-3/72 => x"=0 S={1/12 ; 0}
Super succinct and clear demonstration ,......thanks for sharing Man !
Glad you enjoyed it!
Ерунда. Легко.
2
Carl Friedrich Gauß sends his regards
Nice information
y(10-y)=100 10y-y^2=100 y^2-10y+100=0 (10+or-sqrt(100-4*100))/2 No real solutions as the discriminant is negative. There are solutions in imaginary/complex numbers,but I can't remember how to write them.
1
Yes I do it
Thanks ❤
10^10 2^5^2^5 1^1^2^1 2^1(xy ➖ 2xy+1). (5)+(5)=10 (2^3)+(2^3) (2^1)+(1^3) (2)+(3) (y ➖ 3x+2).
Almost every other 2nd-order problem I have seen had two solutions. What makes this one different?
The numbers involved are so small, that x == 1/-1 becomes obvious, even for someone like me who doesn't do a lot of math-related stuff on a daily basis.
Check your videos before posting it. This is ridiculous 😂😂😂
Sure, that was a mistake 🙏
Where am i travelling to
sqrt(3x)/x = 6 => sqrt(3)*sqrt(x)/x = 6 => sqrt(3)/sqrt(x) =6 => sqrt(3)/6 = sqrt(x) | x^2 => x=3/36 = 1/12
You forgot to square x when you wrote 4 times x.... bad mistake
no real answers....
I'm not Russian, but can do it in my mind: y=x^2+2 y1=-3; y2=3 x1^2=-5; x2^2=1 x11=i*sqrt(5); x12=-i*sqrt(5);x21=1;x22=-1; i=sqrt(-1)
Too long bro
Am here to remember what I was doing but am looking clearly but I don’t remember anything 😂😂
Am here to remember what I was doing but am looking clearly but I don’t remember anything 😂😂