Відео

quality overview.

Thank you for the video. I can finally "understand" the concept and start practicing more! very helpful explaination

ethics mean nothing when you dont feel

I disagree

Sir if u wanna make that first example look a little simpler u could perhaps start with dy/dx = (2x^2)/y instead of multiplying coz then the integration and simplifying is simpler and it shows the idea of separable de's But love the video keep em coming :D Edit: Just saw ur third example - perhaps that should be the first?

NICE

awesome!

thank you daniel

In your last example do your students query that you have a discontinuous integrand (x = 1) and accordingly it is an improper integral? (I appreciate that it is convergent and the answer is correct.) I have an old Casio 9860 and a numworks, which result either maths error or undefined. My TI-84 Plus CE gives 1.57... I don't know if the new Casios have addressed this.

you need a better marker. It's too faint to read.

Thank you for such an informational and inspiring video

thank you daniel

Sir i deem this cameraman sub-par

appreciate Sir

Just a thought - divide both sides by e in the first line.

Good explanations sir, takes me back to the days of 2022

Hi Daniel. I am teacher working in Vanuatu in the Pacific region. We are offering the kids here opportunity to the SACE. We are a small school. This is my first time teaching the Stage 2 SACE Methods course. You mentioned you may be able to share the booklet you are using with your class. I have limited resources as we are new to SACE. I would be really grateful if I could get a copy? THanks, Ed Doyle

You a real one Daniel. Thank you.

Explanation involving only the properties of cis, z + 1 = cisθ + cis0 = cis(θ/2)[cis(θ/2) + cis(-θ/2)] = 2cos(θ/2)cis(θ/2). |z + 1| = 2cos(θ/2), Arg(z +1) = θ/2.

🙈 *Promo sm*

great video! keep it up!

Mr Royals --> Mr Virgo

Virgo could never

I just looked up the hot-crazy scale and now i got math....i thought this was gunna be funny

Lost the hair sir! Where did it all go?? Lookin sharp as always :)

W video sir

Key Concepts 1a - 0:28 1c - 0:58 1e - 2:23 1f - 4:53 2c - 7:30 4a - 10:55 4b - 14:43 4c - 15:24 5a - 19:19 5d - 19:43 5g - 20:20 5j - 20:38 5m - 21:10 6c - 23:03 6f - 23:50 6i - 25:05 6l - 27:24 6o - 28:44 7a - 30:10 7e - 31:10 8e - 31:58 8g - 32:53 9a - 34:51 9b - 38:55 9c - 42:13 10a - 45:55 10f - 47:48 11a - 50:54 11b -51:15 11c - 52:00 11d - 52:46 12a - 55:30 12b - 57:22 13 - 58:40 14 - 1:08:07 15a - 1:13:49 16a - 1:15:40 16c - 1:18:36 17a- 1:21:16 17c - 1:25:13 18a - 1:28:20 18c - 1:29:04 18e - 1:29:44 19 - 1:30:45 20 - 1:32:22 21a - 1:36:07 21b - 1:38:10 21c - 1:39:55 22 - 1:41:52 23a - 1:44:30 23c - 1:45:26 23e - 1:46:33 23g - 1:47:19 23i - 1:48:14 23k - 1:49:37 24b - 1:50:25 24d - 1:51:00 24f - 1:51:48 24h - 1:52:37 24j - 1:54:10 24l - 1:56:10 Constructing Functions Using Geometry 1 - 1:57:50 2a - 2:01:10 2f - 2:01:47 3 - 2:04:03 4a -2:08:32 4c - 2:10:13 5b - 2:13:35 6a - 2:18:10 7a - 2:26:06 7c - 2:28:32 8 - 2:32:12 Logarithms 1 - 2:35:15 2 - 2:36:22 3 - 2;40:36 4 - 2:42:12 5 - 2:45:30 6 - 2:48:20 7 - 2:54:22 8 - 2:56:08 9 - 2:57:47 10 - 2:58:50 11 (4 at bottom) - 3:01:40 Unit Circle 2 - 3:03:28 3 - 3:04:07 4 - 3:04:37 Applications of the Unit Circle a) 3:11:28 1 - 3:13:17 2 - 3:15:15 3a - 3:22:20 3b - 3:25:10 3c - 3:27:17 3d - 3:30:25 3e - 3:31:35 3f - 3:32:52 4a - 3:35:27 (using Pythagorean identity) 4c - 3:38:28 (using triangle method) 4b - 3:42:40 4d - 3:44:10 Trigonometric Functions 1 - 3:47:00 2 - 3:49:00 3 - 3:51:15

Love the title and the absolute menace you were when taking down that 2020 exam sir

i have no idea who u r im literally from australia but great maths LOL

♥♥♥

love you ❤❤ my aussie teacher

"Promo sm" 🙌

thank you so much

legend, ur the only thing keeping me together for my SATS 👍

Fun fact: When a polynomial p(x) is divided by (x - a)², the remainder is the equation of the tangent at x = a. In this case the equation of the tangent is y = (2a - 2)x - 3 - a². ∴ -3 - a² = -7 and a = ±2. The tangents are y = 2x - 7 and y = -6x - 7 at (2, -3) and (-2, 5) respectively.

When you do problem solving with quadratics, can you please cover question 9 aswell?

My preference is to avoid fractions. x² + 5x + 2 = 0 4x² +20x +8 = 0 (2x + 5)² = 17 2x + 5 = ± √17 2x = -5 ± √17 x = (-5 ± √17)/2

This video is amazing! - really clear for binomial data!. I can't seem to find anywhere else where these equations are used, it's really frustrating as all the equations seem to be for continuous data. Where did you get these formulas from? is there a book or resource or something

Good luck with test ppl

saving me for the SAT tmrw

thank you sir daniel

Not part of Specialist course nor is SHM.

👌 𝐩𝓻Ỗ𝓂Ø𝓈Ｍ

Sir was this SPEC EXAM FOR IIIT HYDERABAD

from where is the 1.96 ?

Hi Mr. Royals