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Embark on a journey of numbers and logic with our math UA-cam channel! Whether you're a beginner or looking to sharpen your skills, our short, engaging videos cover various math topics. Subscribe for bite-sized lessons, problem-solving hacks, and a sprinkle of math magic. Let's make math your favorite subject - one video at a time! 🎓
France | A nice Exponential equation | Euler's identity | w function | math Olympiad | (–5)^m=5
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USA | A beautiful Olympiad Exponential Trick (9/6)^9/6
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A nice Exponential equation | can you solve | math olympiad | m^m=3
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Japanese | Can You Solve this ? | Math Olympiad
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New York | Nice Exponent Math Simplification | Find the Value of X
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Brazil | A nice exponential problem | International math Olympiad Simplification
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German | A nice Exponential equation | Math Olympiad | 99% People can't solve it
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Russia | Viral Olympiad mathematics | A nice exponential equation
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Australia | A very nice Exponential equation | Math Olympiad
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Ukraine | A nice Exponential problem | Math Olympiad Simplification | Can You Solve it
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A nice Exponential problem | Square root Simplification | find x
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USA | Viral Math Olympiad | A nice exponential equation | can you solve it
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USA | Viral Math Olympiad | A nice exponential equation | can you solve it
New York | Olympiad mathematics | A nice exponential equation | can you solve it
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New York | Olympiad mathematics | A nice exponential equation | can you solve it
British | Viral Math Olympiad | a nice Square root Simplification | Can you solve it
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British | Viral Math Olympiad | a nice Square root Simplification | Can you solve it
Canada | Viral Math Olympiad Simplification | a nice algebraic expression | Can You Solve it
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Canada | Viral Math Olympiad Simplification | a nice algebraic expression | Can You Solve it
Poland | A nice Square root Simplification | Can You Solve it | Math Olympiad
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Poland | A nice Square root Simplification | Can You Solve it | Math Olympiad
France | Viral Math Olympiad | A nice exponential equation | You should know this equation
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France | Viral Math Olympiad | A nice exponential equation | You should know this equation
A nice Exponential equation | Factorial simplification | can you solve it
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A nice Exponential equation | Factorial simplification | can you solve it
British | A nice Exponential problem | Math Olympiad
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British | A nice Exponential problem | Math Olympiad
A nice Square root Simplification | International math Olympiad | Can You Solve it
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A nice Square root Simplification | International math Olympiad | Can You Solve it
New York | A nice exponential problem l Math Olympiad Simplification
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New York | A nice exponential problem l Math Olympiad Simplification
USA | Vedic method | Math Olympiad |Can You Solve it | A nice exponential problem
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USA | Vedic method | Math Olympiad |Can You Solve it | A nice exponential problem
A nice vedic Exponential equation | exponential simplification | using discriminate | Find x
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A nice vedic Exponential equation | exponential simplification | using discriminate | Find x
Indian | Can You Solve it | Vedic Math Olympiad | x=? y=?
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Indian | Can You Solve it | Vedic Math Olympiad | x=? y=?
Germany | Math Olympiad | A nice exponential problem solved | Vedic method
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Germany | Math Olympiad | A nice exponential problem solved | Vedic method
Japan | A nice exponential equation | Math Olympiad
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Japan | A nice exponential equation | Math Olympiad
USA | Vedic Exponential math Olympiad Simplification 👍
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USA | Vedic Exponential math Olympiad Simplification 👍
France | A nice exponential problem| You Should know this method
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France | A nice exponential problem| You Should know this method
Mexico | Find Conjugate and absolute value | can you solve it
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Mexico | Find Conjugate and absolute value | can you solve it
Ireland | Nice Square root Simplification | Can You Solve it 👍
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Ireland | Nice Square root Simplification | Can You Solve it 👍
Very interesting equation. Hope UA-cam recommends this to more people.
1.825 x 1.825 = 3.330625 square root of 3 is 1.73205080....
To many steps: m^10=m^(2*5)=5^(2*m). Exponents and bases needs to be the same on each side. therfore: m=5.
is 0 another correct answer?
1 091 * 1 5551 * 6
It's always nice to see someone making such videos. Though, some remarks: 1. The way to find the solution is needlessly complicated. x = sqrt(x) + sqrt(x) = 2 sqrt(x) = sqrt(4x) Is equivalent to (note that x must be non negative to restrict ourselves to real solutions anyway) x² = 4x. Now note that 0 may be a solution and proceed for the other case where we then can divide by 0 which instantly results in x = 4. So there is your result, x in {0, 4} solves it. 2. The way to double check makes me, well, furious. It's good practice to do so, don't get me wrong. But everytime I see people replace x on both sides of the equation and put an equals sign between it, and THEN simplify, it makes me sad. Either start with one side and simplify (and potentially complexity again) to end at the other side of the equation. Or for God's sake make clear (and sure) that you are talking about equivalences, by putting <=> between the equations. Starting with something that you want to check, do something to the equation and land at something true (through implications) is neither a proof nor a check of your result (ex falso quod libet). Just had to write this, I feel better now, thanks 😅
Let a=9^x then 3a=999 a=333 so 9^x=333 Use logarithms in base 9 log(9,9^x)=log(9,333) xlog(9,9)=log(9,333) x= log(9,333)
if you are going to write log2 and log3 values directly, why didn't you use a calculator from the beginning? the divisor line should be aligned with the equal and addition signs, not below them. if you are a maths teacher, there should be a lecture in the background, not music. also, increase the tempo, the seasons changed until the video was over. these are the reasons for my downvote.
What is the comma for?
掛け算割り算できるもんは一目瞭然に計算できるからそんなややこしくしないでええよ。
This should be3 minutes! You spent to much time rewriting.
Ainda bem que terminou antes de eu precisar pegar a lupa. Kkkkk
5^x + 5^x = 90 2 · 5^x = 90 5^x = 45 x · lg(5) = lg(45) x = lg(45) / lg(5) x = log₅45 x = log₅(5 · 9) x = log₅5 + log₅9 x = 1 + log₅3² x = 1 + 2 · log₅3
You're taking the long way round.
Эх, жил бы я в Канаде, все олимпиады бы там затащил...
Do you need to go through all those steps at 5^x = 45 just use definition of a logartithm log_5(45)
Or if you want that form 5^x = 9 × 5 5^(x-1) = 3² x-1 = log_5(3²) x = 2log_5(3) + 1 But may as well just leave it log_5(45) it's the same answer.
I expected to find x at least as a fraction number but i got stuck with logarithms after i had log_5(45) than on the video all those simplifications just to still have a logarithm...at this point your solution log_5(45) looks way easier and correct at the same time.
@@dauz889 you can usually leave your answer in logarithmic form, unless it's some thing like log_10(100) you would just write that as 2, but often you aren't going to get nice numbers. Both forms are fine, but just by using the definition of a logarithm, you can do this question in a couple lines.
As,,,saya g ngerti 85 yg bawah dari mana. Ko 85 ada 2
Really stupid
More faster: (9/4)^(9/4) = (9/4)^(2+ 1/4); (9/4)^(2+1/4) = (9/4)^2 * (9/4)^(1/4); (81/16) * ((3/2)^2)^(1/4)=(81/16) * (3/2)^(1/2).
2:27 using (Ln) is way more better
I got m=1+(1/log 8)
It's quite easy. Just take log and then simplify. Math olympiad?
Probably this is the highest level în France ... kind of lame...
log of 80 base 8=1+1/3log of2 base10=m .ans.
why you so slow bro
(9/4)^9^4 (3^2/2^2)^9/4 [(3/2)^2]^9/4. 2.9/4 = 9/2 (3/2)^9/2 √3^9/√2^9 81√3/16√2 81√3.√2 = 81√6 16√2.√2 = 16.2 = 32 81√6/32
Why not just (8+1)/2 => 4 + 1/2 |=> (9 *9)/(4*4)* sqrt(3/2)?
5 уножим на 5 пишем 25 потом одну двойку добавим 1 будет 3 уножим на двойку будет 6 легче будет
5χ5 =25 , 2χ2=4. + 2 from 25 = 625 in about 3sec. This is not s trick this is nothing 😅
the step where the person rightw Kto the 3 power +k-27-3 == 0 has no logical explanation unless one knows the answer in advance. and the answer to the problem being worked (not the one on the tag line) is clearly 3. total bs
The right-hand side of the original equation was equal to 39
It's easy to solve even just in mind. 3+-√3, 3-+√3. And so it's trivial to verify in mind as well.
the solution is 1... since -7^1 = -7^(2 * 1/2) = (-7 ^ 2) ^ 1/2 = 49 ^ 1/2 = 7
This guy does not understand even basic algebrta or arithmetic..!! If you can replace -1 with e^πi, you should be able to replace the same -1 with i^2 also, or 3-4 also, or 6-7 also, or anything that is equal to -1. And each one will give a different answer, apparently meaning everything = everything else....!!! What a riduculous conclusion!
This checks out, because 2log(i) = i(pi).
Scrap the music --- it's ridiculous that you thought that *any* music at all was appropriate for this video. And explain what you're doing, by *speaking.*
I can tell the guy doesn't understand what he's doing but rather copies the answer from some book.
Yes, look at the way he writes π , not sure he even realizes what is the symbol he is copying
Is not log(i) = i*pi*(4*k+1)/2 and x = ( log(7) + i*pi*2*n) / ( log(7) + i*pi*(2*k+1) ), where k and n are integers?
no it's (2 π + 2 n π - i log(7))/(π - i log(7)) where n is any integer
how a a power a =b power b? 2² is not 3³?
Use log rules. So log base 8 of 4! Took 20 seconds. But yes second method is nearly as fast.
What a great
Well youre using logs already for log 7 so why not do log7 70
Three digital calculation send video
Too lengthy
Wow ❤❤ very easy explanation😄
Oh, you can calculate 7^2.1834 in mind. That's awesome dude
2/3 ?
Log(7) isn't _exactly_ 0.845, so the solution is only an approximation. The verification only works because you do it backwards with the same degree of precision. That's not saying anything is "wrong", but you should indicate an approximation by these "wavy" type equality signs.
x=2/3. Лёгонький примерчик. Упростить и прологарифмировать по основанию 2.
Second is better
8^х = 4 Х = 2/3