Відео

Abbott Estates

So so helpful. Really glad I came across your videos before my exam.

Wolf Pass

Haley Gateway

Thank You So Much Mam Very clear

Thank you for your knowledge mam it was a really helpful video🙇

Excellent video! You explain the concepts in a very simply and understandable way. Thank you very much :)

Applicant name wife ka daal diya kya hoga

But little fast

Excellent class

Is this series completed?

Is this series completed?

👍

6207 Howell Drives

Wilkinson Lights

Reilly Hollow

Best explanation❤❤

Sonny Light

Thank you so much! Accounting from the sender's perspective using LastByteSent - LastByteAcked <= rwnd, and from receiver perspective would be rwnd = RcvBuffer - (LastByteRcvd - LastByteRd) is clear with this visualization

Thank you mam

Very useful video ❣️

Most helpful thank you 😊

CORRECTION: The Transmission Control Protocol (TCP) header can be between 20 and 60 bytes in size, depending on whether optional fields are included, NOT 20-40.

Thankyou mam, i understand clearly ❤

Very well explained mam 😊

Thank you so much..

So good teaching

Thank u

Thank you so much

❤

After spending whole day finally found your lectures playlist and cleared my concepts, and now I will sleep peacefully. Hope in coming days this channel will rock. ❤

Nice explanation Ma'am ❤️❤️🙏

We're lucky to have a professor like you. Thank you for being strict mam.

Mam ur lec is excellent...but I need ur help to clear my doubt....at msg 3, we r informing r1,r3,r4 that they can communicate with N10,N11,N12 of the autonomous sys 3....but u wrote n1,n2,n3 ........and lly at msg 4 we are telling the router9,8 that they can communicate with networks of as1 ...but u wrote n10,n11,n12....this got me confused ...plz help me clear my doubt.....rest thanku ❤helped me alot

Thank You very much !!! 💛

This was full copied in our class seminar😅😅

Plz explain bottom up and bottom down approach method diffence

Madam you not explain knapsack algorithm using memory fuction bottom up

Tq mam ❤

mam suppose if there is process no 5 which is of 310 kb then in the first fit can we accomodate this proceess in the process in the remaining space the accomodated by process p2

Mam it's so super and very understandable

Fantastic video on electronic mail Mam ! ✉ The way you explained the workings of email protocols like SMTP, IMAP, and POP3 was very clear and informative. The historical context and the breakdown of how emails are sent and received really helped me understand the entire process. Thanks for making such a complex topic so accessible. Looking forward to more great content! 👍

You are awesome ma'am 💓

Thank you so much ma'am! 😊

In the formula for R and S, note the following correction pl R is A11 S is A22 By mistake it is written as A22 for R and A11 for S.

why you deleted node 3...?

Pls note the correction , the correct formula for V is V = (B21+B22)(A12- A22)

Maam in the formula for V, the formula is (B21+B22)(A12-A22). You have written B22 instead of A22

At 0.44, Pls note the following correction. Regional ISP address is 192.168.10.0 / 24 Totally it will be 256 addresses and each subnet mask will have 64 addresses

In example 2 there is no edge from A to D In out degree and indegree example, you made a mistake and told that Indegree is number of edges coming out of a vertex